Question about Texas Instruments TI-83 Plus Calculator

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Inverse sine (sin^-1) gives you the angle when the opposite side length and the hypotenuse, in relation to that angle, are given. therefore, if you want to do sin^-1(x), 0<x<1 for all real triangles ex. sin^-1(1/2) would equal 30. if you get a decimal, then go to [Mode] and select degrees instead of radians to get angle measures instead of radians... :)

Posted on May 14, 2009

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Posted on Jan 02, 2017

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Does it refuse to do so or does it give an error message?

Three common errors:

Three common errors:

- Not having the correct angle unit.
**Wrong result, No error message** - Confusing reciprocal of sine (1/sin(x) with arc sine (x) ,sin^-1(x). Confusing the reciprocal of cosine, 1/cos(x) with arc cosine (cos^-1(x)).
**Wrong result, No error message** - Taking the argument of the inverse sine and/or inverse cosine functions outside the interval [-1,1].
**This gives a domain error.**

Oct 28, 2013 | Texas Instruments TI-81 Calculator

The sine and cosine function have a range between [-1, 1]. The domain of their inverse functions is [-1,1]. So 20/1 which is 20 is out of the domain of definition of the functions. No limitations for tangent and cotangent.

Oct 22, 2013 | Casio FX-115ES Scientific Calculator

It seems that you are trying to calculate the inverse sine (arcsine) of 90. However the domain of definition of the arcsine function is the closed interval [-1, 1]. Any value outside of this interval will result in an error.

Apr 20, 2013 | Office Equipment & Supplies

Make sure the argument is between negative one and positive one, inclusive. The inverse cosine is defined only for arguments in that domain, anything else will give you a domain error.

Oct 26, 2011 | Texas Instruments TI-84 Plus Calculator

Make sure your calculator is in degree mode.

It is probably in radian mode so it can't calculate the inverse sin.

To change this, go to Mode -> Deg.

Hope this helps, cheers!

It is probably in radian mode so it can't calculate the inverse sin.

To change this, go to Mode -> Deg.

Hope this helps, cheers!

Mar 06, 2011 | Texas Instruments TI-30 XIIS Calculator

Is your Ti83 plus in degree mode. You can change to radians by pressing the MODE key, and sliding down 2 more positions, and press the ENTER key. Because you got this error your principle value for x and y should be examined. Generally you really should be in radian mode when working with arcsin (aka. sin^-1), and arccos. You probably weren't using arctan because, you would have never gotten this error message due to the fact it goes on forever. And this way your answers for y= arcsin(x), or arccos(x) will be on the x axis, and domains at 0, pi/2, and pi.

You can work in degree mode but, if the number you place in the brackets of your arc sin or arc cos function is larger than 1 or smaller than -1 you will get a ERR:DOMAIN. Using the arctan or (aka. inverse tan) function in the degree mode can be used for computing endless waves, or as an angles that are usually in brackets of cosine or sine. Example: cos(arctan(Beta). This functions that y to never be greater than 1 or, less than 0. Example: sin(arctan(angle). This functions that y to never be less than -1 or, greater than 1.

I hope this answers your question to why you got this error and, helps you to decide on what the correct mode setting should be.

You can work in degree mode but, if the number you place in the brackets of your arc sin or arc cos function is larger than 1 or smaller than -1 you will get a ERR:DOMAIN. Using the arctan or (aka. inverse tan) function in the degree mode can be used for computing endless waves, or as an angles that are usually in brackets of cosine or sine. Example: cos(arctan(Beta). This functions that y to never be greater than 1 or, less than 0. Example: sin(arctan(angle). This functions that y to never be less than -1 or, greater than 1.

I hope this answers your question to why you got this error and, helps you to decide on what the correct mode setting should be.

Dec 17, 2010 | Texas Instruments TI-83 Plus Calculator

Since you are familiar with sines, cosines, you know that their ranges (interval of values) varies from -1 to 1. The inverse functions of sine and cosine tkae their values in that very domain, [-1,1].

However you fed the arc sine function (sin^-1) a vlaue of (25/20.48) and that value is obviously larger outside the [-1,1] domain, hence the DOMAIN error message.

No such domain limitations exist for arc tangent (tan^-1) because the range of the tangent function spans the open interval ]negative infinity to positive infinity[.

However you fed the arc sine function (sin^-1) a vlaue of (25/20.48) and that value is obviously larger outside the [-1,1] domain, hence the DOMAIN error message.

No such domain limitations exist for arc tangent (tan^-1) because the range of the tangent function spans the open interval ]negative infinity to positive infinity[.

Nov 02, 2010 | Texas Instruments TI-84 Plus Silver...

your value is not within the domain of the function, that is why it's giving you that error message, try the value times -1, or -(your value)

May 01, 2010 | Texas Instruments TI-89 Calculator

The inverse sine is only defined for values in the range [-1..+1]. Arguments outside this range will produce domain errors.

Apr 14, 2009 | Texas Instruments TI-83 Plus Calculator

I think you may find arcsin(x) is equivalent in older nomenclature to sin^-1 (x)...ie use the "2nd" and the SIN key instead of typing arcsin.

eg. arcsin(0.5) is 30 degrees is the same as sin^-1(0.5)

The ^-1 does not mean reciprocal, but "the angle whose sin is." Here the minus one indicates a kind of inverse operation. The word arcsin indicates that same inverse.

eg. arcsin(0.5) is 30 degrees is the same as sin^-1(0.5)

The ^-1 does not mean reciprocal, but "the angle whose sin is." Here the minus one indicates a kind of inverse operation. The word arcsin indicates that same inverse.

Mar 23, 2009 | Texas Instruments TI-89 Calculator

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