Question about Casio Rare Vintage Scientific Calculator Fx-4800p 4 Line Dot Matrix Lcd

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Posted on Jan 02, 2017

SOURCE: Weather casio FX-115ES can solve 5*5 matrix

According to the manual for the Casio FX115ES, the largest matrix it solves is a 3x3.

Posted on Sep 11, 2008

SOURCE: Casio FX-100AU

Just input #20 then press log button then (2/10 shift 5 (m)) so it will look like 20log (2/10m) = 46.02

Posted on Sep 23, 2008

SOURCE: Inputing factors on a casio fx-115es calculator

Unless I am failing to understand your problem, just combine like terms to get:

9x^2+2x+4 and then enter those coefficients into the quadratic solver.

That will get you the two answers -- both of them will be complex.

If you wanted to turn those two answers into factors (complex) of the original equation simply

change the signs on each and put an x in front.

Of course, the quadratic formula would also work.

CG

Posted on Apr 28, 2009

SOURCE: want to solve quadratic equations on my casio 3650p super fx

Hello,

In your manual, Appendix Program Library, (Page A1) you have the listing of the problem to solve the quadratic equation. Type it in your calculator and execute it.

Hope it helps.

Posted on Oct 02, 2009

SOURCE: Why does it solve in fractions?

The calculator has two Input/Output modes: the default MthIO (new) and the old LineIO.

- In MthIO you enter fractions and radicals as you see them in textbook (multiple levels). Calculations are exact and results are generally a mixture of fractions and radicals.
- In LineIO, numbers are entered the old way and all numbers, operations are written on a single line. All fractions and radicals are converted into decimals numbers.

If you use the default MthIO you can let your calculator perform the operations in exact arithmetic. When you obtain the end result, you can easily convert a fraction/radical result into a decimal one by pressing the [S<=>D] key, or press [SHIFT][=] instead of [=].

However if you do not care about the MthIO and its nifty functionalities, you can configure your calculator to use LineIO.

To set LineIO press [SHIFT][MODE][2:LineIO]

Posted on Jan 29, 2010

https://www.youtube.com/watch?v=rCVM6RWMjQ4

Jan 7, 2015 - Uploaded by Yabets Jab

In this video you can simply understand how to find a value of a given missing number in a table on Casio fx ...Missing: 4800p

https://www.youtube.com/watch?v=OGmHagjZPjg

Oct 31, 2012 - Uploaded by cpobyrne1

How to perform a linear regression on a Casio scientific calculator. Example uses a ... A Casio fx-83WA calculator is used for the demonstration. .... Lagrange Interpolation Easily Explained on Casio fx-991ES Calculator!Missing: 4800p

Jan 05, 2016 | Casio Office Equipment & Supplies

You calculate logarithm by using the **log** key for decimal logs and the **ln **key for natural logs.

Jul 24, 2014 | Casio Fa-9860-av2.0 Fx-9750gii &...

The Casio FX-300MS does not provide base 2 logarithms as a single key operation. However, you can use the natural logarithm (ln, base e = 2.7182818...) and the formula

log2 ( x ) = ln( x ) / ln( 2 )

To calculate the base 2 logarithm of 16, key in

[ln] 16 [/] [ln] 2 [=]

and get displayed the correct answer 4.

The same simple formula also works for any other base, and actually for any other logarithms provided by your calculator. The FX-300MS also provides a logarithm to base 10 (lg). You could also

type

[lg] 16 [/] [lg] 2 [=] to get the solution to the problem above, or

[lg] 25 [/] [lg] 5 [=] to get the base 5 logarithm of 25.

log2 ( x ) = ln( x ) / ln( 2 )

To calculate the base 2 logarithm of 16, key in

[ln] 16 [/] [ln] 2 [=]

and get displayed the correct answer 4.

The same simple formula also works for any other base, and actually for any other logarithms provided by your calculator. The FX-300MS also provides a logarithm to base 10 (lg). You could also

type

[lg] 16 [/] [lg] 2 [=] to get the solution to the problem above, or

[lg] 25 [/] [lg] 5 [=] to get the base 5 logarithm of 25.

Mar 20, 2014 | Casio FX-300MS Calculator

You can calculate the logarithm to any base by using the relationship

logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

Apr 07, 2011 | Casio FX-115ES Scientific Calculator

Shift LN raises e (about 2.718) to a power. Try this:

1 . 0 5 9 5 ^ 2 . 5 =

^ is the key to the left of the log key, below the big cursor pad.

1 . 0 5 9 5 ^ 2 . 5 =

^ is the key to the left of the log key, below the big cursor pad.

Feb 11, 2011 | Casio FX-300MS Calculator

You seem to be doing it correctly. The natural logarithm of 2/3 is about -0.405 and the natural log of 1/30 is about -3.401.

As for the common log of 10y, that would depend on the value of y. If y is e/10, then the log of 10y would be about 0.4343.

As for the common log of 10y, that would depend on the value of y. If y is e/10, then the log of 10y would be about 0.4343.

Feb 11, 2011 | Casio FX-7400G Plus Calculator

call 1-800-706-2534 option 1 for a new manual.

Oct 09, 2010 | Computers & Internet

Enter it almost exactly as you typed it. Just remember that ln will automatically enter the left-parenthesis, and that you don't need to close all parenthesis before pressing =.

( ( ln 1 . 0 2 ) - ln 0 . 7 1 ) x^2 / 3 . 9 2 x^2 =

( ( ln 1 . 0 2 ) - ln 0 . 7 1 ) x^2 / 3 . 9 2 x^2 =

Aug 01, 2010 | Casio FX-115ES Scientific Calculator

Your calculator knows only the decimal logarithms log or log_10 and the natural logarithms (ln or log in base e).

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

So you cannot compute directly the logarithms in any bases other than 10 and e.

A workaround consists in using the relation

log in base b of a number a (log_b (a))

log_b(a)= (log_10(a) ) / (log_10 (b))

or the relation

log_b(a)= ln(a)/ln(b)

log_2(0.3)=log(0.3)/log(2) where log is log in base 10

Similarly

log_2(0.3)=ln(0.3)/ln(2)

As to the multiplicative factor you had at the beginning of your expression, just multiply the value obtained by one on the formulas above (both formulas will give the same result) by 0.3

Jul 18, 2010 | Casio FX-115ES Scientific Calculator

ln(x+1)-ln x=ln 4

Oct 24, 2009 | Casio FX-300MS Calculator

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