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How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm

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Let x be the width and y be the length


we know that the length (y) is 8 inches more than the width (x)so y = x + 8

we know that the total perimeter 60cm (23.622 inches)
so 2x + 2y = 23.622


substituting for y gives
2x + 2(x + 8) = 23.622

simplifies to
2x + 2x + 16 = 23.622


simplifies to
4x = 7.622

so
x = 1.9055

therefore the rectangle is width 1.9055 inches and length 9.9055 inches

Posted on Oct 11, 2013

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The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Posted on Oct 11, 2013

  • kakima Oct 11, 2013

    Sorry, I missed the change in units. The length is 8 inches more than the width, or (in centimeters), width+width+20.32=30. Solving for width gives 4.84cm and that gives a length of 25.16cm.

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