Question about Lands Phones

Let x be the width and y be the length

we know that the length (y) is 8 inches more than the width (x)so y = x + 8

we know that the total perimeter 60cm (23.622 inches)

so 2x + 2y = 23.622

substituting for y gives

2x + 2(x + 8) = 23.622

simplifies to

2x + 2x + 16 = 23.622

simplifies to

4x = 7.622

so

x = 1.9055

therefore the rectangle is width 1.9055 inches and length 9.9055 inches

Posted on Oct 11, 2013

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Posted on Oct 11, 2013

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Posted on Jan 02, 2017

3600

Be sure to show your work.

Be sure to show your work.

Jan 04, 2017 | Homework

We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Solve the resulting quadratic equation

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

**Width =6**

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

2X^2+3X-90=0

Discriminant: (3)^2-4(2)(-90)=729=(27)^2

Two roots

X_1=(1/4)*(-3+27)=6

X-2=(1/4)*(-3-27) =-(15/2), negative

Since the width must be positive, reject the negative root and keep X_1=6

Length=2(6)+3=15

Check 6*(15)=90. Checks OK

Apr 23, 2014 | Office Equipment & Supplies

Ten inches by eight inches (10x8).

If this is homework, make sure to show your work.

If this is homework, make sure to show your work.

Feb 24, 2014 | Computers & Internet

Translate the English into Mathematics.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

**Solve for L: Do it'! **

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is** L'=-4+3W**

and the new perimeter is** P'=2(L'+W)**

Now your turn to do some work.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is

and the new perimeter is

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.

to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.

2. let the length of rectangle be x cm

and breadth = 20 cm

now original perimeter = 2(x+20) cm

new length = x-30 cm

breadth remains same = 20 cm

new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2

2(x-10) = 2(x+20) /2

2x -20 = x + 20

x = 40 cm

hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.

2. let the length of rectangle be x cm

and breadth = 20 cm

now original perimeter = 2(x+20) cm

new length = x-30 cm

breadth remains same = 20 cm

new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2

2(x-10) = 2(x+20) /2

2x -20 = x + 20

x = 40 cm

hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

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