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I need to know how to solve a system of equations on my fx-9750GII calculator

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  • Casio Master
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Here how it is done. Don't mind the calculator it was done on. On your you may have systems of up to 3 linear equations.
Follow the screen captures. I do not think any additional comments are warranted.

I need to know how to solve a system of equations - f32e8007-72b3-4a5b-9d0e-1702d7497839.png
293d03a0-4f1e-41a4-aa64-24eff0688990.pngd095ec16-80c7-46cf-a704-a4048c096d7a.png8d2a2a7f-3fc2-432a-bfa5-464784403ad1.pngPressing the F1 key on the last screen allows you to repaet with the same or different coefficients.

Posted on Oct 11, 2013

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SOURCE: @ symbol

According to the TI-89 Guidebook:

This notation indicates an “arbitrary integer” that represents any integer. When an arbitrary integer occurs multiple times in the same session, each occurrence is numbered consecutively. After it reaches 255, arbitrary integer consecutive numbering restarts at @n0.

Hope this helps. If you need any more info just ask away! :)

Posted on Jan 30, 2009

  • 1 Answer

SOURCE: how do I calculate normal distribution using a

I don't know about fx-9750gII, but for fx-991MS
Change the mode to REG
Then
Shift->3(DISTR)->1(P())->give your Z value

Posted on Feb 04, 2010

  • 1 Answer

SOURCE: i do not know how

Hey it is. Okay, so start with a equation: say, y = -(1 |x|). Now type y = -(1 , then press the [OPTN] button, next to the shift. Next press the [NUM] button or F5. The first menu button should be Abs or absolute value. When your done it should look like this. y = -(1 Abs (x)) then graph it.

Posted on Aug 30, 2010

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Casio fx9750gii


Here how it is done. Don't mind the calculator it was done on. On your you may have systems of up to 3 linear equations.
Follow the screen captures. I do not think any additional comments are warranted. Pressing the F1 key (REPT)-- see last screen capture--allows the user to repeat the solution with the same coefficients or other ones (different system)

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0e99c85e-d431-4e98-853c-4efc5dcd58ee.png6ae879c4-a5bf-42ec-a66f-80f299b59f88.png1b6ce73a-78d4-4451-a482-9fe2019ae8c1.pngb2b2bd77-44b3-4d12-a67e-c812fe401f1e.png

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b4c488c.jpg Hope it helps.

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