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Java code for Solving system of linear equations using parallel processing Abstract of theproject This project is aimed at analyzing the available methods forsolving a system of linear equations of the form n x n. Using a couple ofiterative and/or direct methods, implement a program for these methods thatcould be run on a parallel processor. At the end, a graph can be plotted withtime taken for execution of a method considered V/s number of processors used(2, 4, 8, 32). For example following questions need to be addressed ? For a method considered, evaluate that as the number of processors is increased does the time taken necessarily reduce to solve the equation(s). For a given number of processors which is the best method that could be employed which takes least time. Keywords Generic Technology keywords Parallel Processing, Linearequation methods Specific Technology keywords Unix/ Windows,C Project type keywords Analysis, Implementation Functional componentsof the project Parallel processing engine implementation Implementation of algorithms to solve system of linear equations of the form Ax=B (matrix size NxN) using the parallel processing engine. Steps to start-offthe project Understanding of Parallel Processing technology Study of methods available to solve a system of linear equation of the form Ax=b (matrix size of NxN)

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2x-3 = 3-3(x + 3)

Posted on Oct 27, 2010

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How can i write this in my calculator example. 2x=10 the answer is x=5 but how can i put x in the calculator

What you want to do is solve the linear equation 2x=10 to find the value of the unknown x that makes the equality true. Solving an equation usually involves rearranging therms, factors and so on. However your calculator was not designed to handle the solution of equations, no matter how simple they are.
Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Oct 16, 2013 | Casio FX350MS Scientific Calculator

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Explain what it means for a system of linear equations to have no solutions, one solution, two solutions, and infinite solutions.

  1. No solutions: The system is incoherent, incompatible Example: 2x+3y=8 and 2x+3y= 15. The two lines are parallel and distinct.
  2. One solution: There exits a pair of values (x,y) that satisfy both linear equations. The two lines on a Cartesian graph have one intersection point.
  3. Infinite number of solutions: The two equations are one and the same (one is just multiplied by some constant). The graph of the two lines yields the same line. One is superposed on the other. Any ordered pair (x,y) that satify one equation (there is an infinity of such pairs) satisfies the other.
  4. Two solutions: cannot happen because the two lines can either intersect once, be parallel, or superposed one on the other.

Dec 13, 2012 | Mathsoft StudyWorks! Mathematics Deluxe...

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How to find values of x in higher order equations(above cube) on casio 570 ES?

In equation mode, you have system of linear equations (3 unknown) you have polynomial (quadratic and cubic), and solver. Use the solver foe any type of equation (nonlinear, polynomial of order higher than 4, trigonometric, exponential, logs).

May 21, 2012 | Casio Scientific Calculator Fx-570 Fx570...

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Edit Casio FX - 9860G SD have complex equations??

Thhe Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to a+ib, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).
Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Alternatively, after you create the system of 4 linear equations you can use the matrix utility to find Real(x), Im(x), Real(y) and Im(y) and recompose the x and y.

Mar 17, 2012 | Casio FX-9860G Graphic Calculator

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Solving linear equations in 3 variables by matrix method in casio fx-115ES

Press key Mode, first select option 5:EQN (by pressing key 5), then option 2: a_nX+b_nY+c_nZ=d_n (by pressin 2).
Now input coefficients from equations in table (each column is for one variable), just type in number and press =, then use arrows to move to another cell.

Sep 02, 2011 | Casio FX-115ES Scientific Calculator

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I am doing a java application to structural involves the solution of system of linear simultaneous equations.may yuo pliz assist me with a java code to solve the equations.its urgent .pliz...

The absolutely-best, most-robust, software for solving systems of linear equations is the LINPACK software library.

It was originally written in FORTRAN.

But, see:

which indicates that a JAVA version exists.

Mar 02, 2011 | Computers & Internet

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I m unable to multiply two 4 cross 4 matrix ,how to solve this problem?

This calculator cannot handle matrices that have anyone dimension larger than 3.
How to solve your problem?

  1. Set up the problem by hand (pencil paper): use Cramer's rules. Make use of the calculator to perform the various calculation.
  1. Sacrifice one equation which you will use to eliminate one variable of the 4 by expressing it in terms of the other three. Do the algebra to obtain a system of 3 equations in three unknowns.
  2. Use the calculator to find the solutions ( the three variables that are left).
  3. Use the 4th equation (the one you scacrificed) to obtain the value of the 4th unknown.

use a computer program devoted to solving linear equations

OR buy another calculator that can handle larger systems of equations (a graphing calculator, maybe).

Feb 16, 2011 | Casio FX-115ES Scientific Calculator

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Solving simultaneous equation with scientific


Let us assume you have two simultaneous linear equations :

a_1*x+ b_1*y+c_1=0
a_2*x +b_2*y+c_2=0

where a_1, a_2, b_1, b_2, c_1,c_2 are coefficients (numerical or algebraic).
The problem is to obtain the particular values of the unknowns x and y for which the two equations are both satisfied: If you substitute the particular values of x and y you find in any of the two equations you discover that both equalities are true.

A small system of equations like the one above can be solved by some very simple algorithms (elimination, substitution, combination) which can be carried out by hand.

The solution of large systems of linear equations can be sought by making use of the concepts of matrices (plural of matrix), determinants, and certain rules called Cramer's rules.

Due to its repetitive nature, the algorithm ( a well defined, limited sequence of steps) is suitable for a calculating machine (computer or calculator).

Certain calculators have, embedded in their ROM, a program that solves linear systems of simultaneous equations. Usually you are asked to enter the values of the coefficients a_1, etc. in a set order, then you press ENTER or EXE (Casio) . If a solution exits (not all linear systems have solutions) the calculator displays it.

Hope that satisfies your curiosity.

Aug 12, 2009 | Sharp EL-531VB Calculator

2 Answers

Algebra college

Consider the following system of 3 equations in 3 unknowns:
x + y = 2
2x + 3y + z = 4
x + 2y + 2z = 6Our goal is to transform this system into an equivalent system from which it is easy to find the solutions. We now do this step by step.
  • Subtract 2*(Row1) from Row2 and place the result in the second row; subtract Row1 from Row2 and place in the third row. Leave Row1 as is.
x + y = 2
y + z = 0
y + 2z = 4
  • Subtract Row2 from Row3, and place the result in row3. Leave Row1 and Row2 as they are.
    x + y = 2
    y + z = 0
    z = 4 From the last form of the system we can deduce the following unique solution to the system:
z = 4, y = -4, and x = 2-(-4) = 6Equivalently, we say that the unique solution to this system is (x, y, z) = (6, -4, 4).

Sep 17, 2008 | Belkin (F5D7230-4) Router (587009)

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