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Age problem Inee and Imee are twins. Their mother is 28 years older than they are and 4 times as old as the sum of their ages. How old are Inee and Imee now?

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They are 4 years old and the mother is 32. This is a system of two equations. The first equation is 28 + x (their mother is 28 years older than they are). The second equation is 8x (she is 4 times as old as their sum) their sum is 2x (x being the twins age) time 4 which is 8x. Set these two equal to each other and you get 28 + x = 8x, bring the x to the other side by subtracting and x on both sides and you end up with 28=7x , now divide off the 7 and get x=4. Verify your work and take 4 + 28 and you get 32. Now take 4*2 (sum of their ages ) and multiply it by 4 and you get 32.

Posted on Jun 26, 2009

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X+X+28=4(X+X)
2X+28=4X+4X
28=8X-2X
28=6X
X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

Posted on Apr 21, 2009

  • Wayne Mineard
    Wayne Mineard Apr 21, 2009

    Duh! Should be:



    X+28=4(X+X)

    X+28=8X

    28=8X-X

    28=7X

    4=X



    Answer is 4. Mother is 32.



    I hate not being able to correct posts. :-(

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1 Answer

Adjoa is three years older than her brother Kwame.seven years ago,the sum of their ages 13years.calculate the sum of their present ages.


Let Adjoa's age be x and Kwame's y.
  • Adjoa is 3 years older than Kwame: x=y+3
  • Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
  • Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
  • 2y-4-7=13
  • 2y=24
  • y=24/2=12 years
  • x=y+3=12+3=15 years
  • sum of their present ages is x+y=12+15=27 years

Sep 27, 2011 | Office Equipment & Supplies

1 Answer

The sum of ages of marian, diana and carlos are 17. Two years from now marian will twice as old as diana. if carlos is half as old as marian four years from now. How ald are they now ? Pls show the...


Let m be Marian's age, d Diana's age and c Carlos age.
  • sum of ages is 17: m+d+c=17
  • two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
  • Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
  • now: m+d+c=m+m/2-1+m/2-2=17
  • 2m=17+3=20
  • m=20/2=10 years
  • d=m/2-1=5-1=4 years
  • c=m/2-2=5-2=3 years
Marian is 10 years old, Diana 4 years old and Carlos is 3 years old.

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

1 Answer

Cory is 6 years older than her sister.Four years ago, she was 4 times as old her sister.how old is cory now?


let c = cory's age now let s = her sisters age now
cory's age now = sisters age + 6 years
=> c = s + 6
4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)
4 years ago cory was 4 times older than her sister
=> c - 4 = 4*(s-4)
We can simplify this to c = 4s - 16 +4 c = 4s - 12
We can then use simultaneous equations to solve the two equations
(i) c = s + 6 (ii) c = 4s - 12
If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24
We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12
For clarity: Her sister's age now is of course 6 4 years ago Cory would of been 8 and her sister would of been 2
I hope this helps and good luck! If you have more questions - ask away!
Please take the time to rate this answer
Many Thanks Don.

Sep 13, 2011 | Sunburst My Mathematical Life Single...

3 Answers

Daughter is 3 year old and her mother is 28 years older than the daughter.how many years later will the mother be three times older than her daughter?


daughter = x
mother = x+28

Equation = x+28=3x

Solve:

x+28=3x
-x -x
28 = 2x
/2 /2
x=14

Answer:
Daughter = 14
Mother = 42

Mar 04, 2011 | Computers & Internet

1 Answer

The average age of 3 girls is 20 years and their ages are in the ratio 3:5:7.The age of the eldest girl is:


The average is 20, it means the total is 60. The sum of ratio is 15 (3+5+7)
Therefore the age of a girl is calculated by multiplying the respective ration with total and dividing by sum of ratio
Age of Eldest girl = 7 x 60 /15 = 28

Hope it helps! Good Luck!
CreativeTECH

Feb 15, 2011 | Computers & Internet

1 Answer

Cindy is 5 years older than Alex and 7 years older than peter sum


Three unknowns with three equasions:
cindy is 5 years older than alex. write it as c = a + 5
cindy is 7 years older than peter. write it as c = p + 7
The sum of their ages is 21. write it as c + a + p = 21
first solve for peters age in terms of alex's age.
c = p + 7 or
(a + 5) = p + 7 or
p = (a + 5) - 7 or
p = a - 2
substitute in and solve the equasion:
(a + 5) + a + (a - 2) = 21 or
3a + 3 = 21 or
3a = 24 or
a = 8

c = a + 5 or
c = 8 + 5 = 13

c = p + 7 or
p = c - 7 or
p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6
This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

Sep 20, 2009 | Puzzle Toys

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