Question about Newmark Learning Common Core Mathematics Grade 3

You only gave one pair of points so I assume you want a line going through those two points.

y = (2/3)x - 7/3

Posted on Jul 31, 2013

Move the tangent, to the sin, inverse the fraction then divide!

Posted on Oct 21, 2013

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Posted on Jan 02, 2017

If you plot this, it is approximately a straight line (with a y error or +/-.2). An ideal straight line would have y points of 7,8,9,10,11,12 for the given x's. The formula for this line is y=.5x + 6 . The gradient (slope) is .5 and the intercept is 6.

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

Mar 01, 2014 | Office Equipment & Supplies

You could use Concatenate command. Means to join together.

B2 = Concatenate A2, ,H2 Note the space in middle, for dentist chico. Otherwise will be dentistchico

B2 = Concatenate A2, ,H2 Note the space in middle, for dentist chico. Otherwise will be dentistchico

Sep 15, 2011 | Microsoft Excel for PC

The site seems to eat the plus signs I enter, so I will use PLUS to symbolize addition.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

To find the equation of the straight line (y = a*x PLUS b) that passes through two points P1(x1,y1) and P(x2,y2) , you need to use

1. the coordinates of the points to calculate the slope a (gradient) as a=(y2-y1)/(x2-x1)

2. Replace the calculated value of a in the equation and write that one of the points ( P1(x1,y1) for example) satisfies the equation. In other words y1=a*x1 PLUS b.

Here y1 and x1 are known values, a has been calculated, and only b is still unknown. You can now use the equation y1=a*x1 PLUS b to calculate b as

b=(y1-a*x1)

Example: Equation of the line through (1,5) and (3,6)

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5, x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=(1/2)*3 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

I trust you can substitute you own values for (x1,y1, x2,y2) to duplicate the calculations above.

Jan 27, 2011 | Texas Instruments TI-84 Plus Calculator

Calculate
the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=6, y1=5,
x2=3, and x1=1. You should get a=(6-5)/(3-1)=1/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

The equation is y=(1/2)x PLUS b, where b is not known yet.

To find b, substitute the coordinates of one of the points in the equation. Let us do it for (3,6).

The point (3,6) lies on the line, so 6=3/2 PLUS b.

Solve for b: 6 MINUS 3/2=b, or b=9/2=4.5

Equation is thus y=(x/2) PLUS 9/2 =(x PLUS 9)/2

Oct 20, 2010 | Texas Instruments TI-84 Plus Calculator

Calculate the slope (gradient) of the line as a=(y2-y1)/(x2-x1) where y2=1, y1=0, x2=0, and x1=-6. You should get a=(1-0)/(0-(-6))=1/6

The y-intercept is the y-cordinate for x=0. Its value is 1.

The equation is then y=(x/6) 1.

The y-intercept is the y-cordinate for x=0. Its value is 1.

The equation is then y=(x/6) 1.

Oct 18, 2010 | Texas Instruments TI-84 Plus Calculator

Apply a different shape
fill
You can fill a selected shape (such as data markers, titles, data labels, or
a legend) with a solid color, gradient, picture, or texture. You cannot use
shape fill to format lines in a chart (such as gridlines, axes, trendlines, or
error bars).

On a chart, click the chart element that you want to change, or do the following to select it from a list of chart elements:

**Format** tab, in the **Shape Styles** group,
click **Shape Fill**

** Tip ** If you don't like the change that you made, you
can undo it immediately. On the Quick Access Toolbar, click **Undo**
, or press CTRL+Z.

On a chart, click the chart element that you want to change, or do the following to select it from a list of chart elements:

- Click a chart.
This displays the
**Chart Tools**, adding the**Design**,**Layout**, and**Format**tabs.

- On the
**Format**tab, in the**Current Selection**group, click the arrow next to the**Chart Elements**box, and then click the chart element that you want to use.

- Do one of the following:
- To use a different fill color, under
**Theme Colors**or**Standard Colors**, click the color that you want to use.**Tip**Before you apply a different color, you can quickly preview how that color affects the chart. When you point to colors that you may want to use, the selected chart element will be displayed in that color on the chart.

- To remove the color from the selected chart element, click
**No Fill**. - To use a fill color that is not available under
**Theme Colors**or**Standard Colors**, click**More Fill Colors**. In the**Colors**dialog box, specify the color that you want to use on the**Standard**or**Custom**tab, and then click**OK**. Custom fill colors that you create are added under**Recent Colors**so that you can use them again.

- To fill the shape with a picture, click
**Picture**. In the**Insert Picture**dialog box, click the picture that you want to use, and then click**Insert**. - To use a gradient effect for the selected fill color, click
**Gradient**, and then under**Variations**, click the gradient style that you want to use. For additional gradient styles, click**More Gradients**, and then in the**Fill**category, click the gradient options that you want to use.

- To use a texture fill, click
**Texture**, and then click the texture that you want to use.

- To use a different fill color, under

Jun 01, 2010 | Microsoft Office Professional 2007 Full...

You can use cell validation.

Select the cells you want to have the dropdown list.

Press the following keys "alt" "d" "l" and you get a message box.

select List from the drop down.

Now you can type in your list in the blank box separated by commas

Select the cells you want to have the dropdown list.

Press the following keys "alt" "d" "l" and you get a message box.

select List from the drop down.

Now you can type in your list in the blank box separated by commas

Nov 29, 2009 | Microsoft Excel for PC

get a sheet of graph paper. draw a line vertical and draw another line in the center perpendicular to the vertical. the meeting point is 0,0 - the upper right quadrant is X-Y. the bottom right quadrant is Y -X, the left bottom is -Y -X and what's left is -X +Y.

take your first coordinate. count up 2 and to the right 3. make a point. second coordinate - count up 4 and over right 1, make a point. now join the two points with a straight line. measure the distance between the points.

take your first coordinate. count up 2 and to the right 3. make a point. second coordinate - count up 4 and over right 1, make a point. now join the two points with a straight line. measure the distance between the points.

Dec 15, 2007 | Electronic Arts The Sims 2: Christmas...

columns total in additin cells of rows equal are total

Oct 24, 2007 | Oracle 10g Database Standard (ODBSEONUPP0)

Relative cell reference is address of cell , when copied from one cell to another gets changed automatically.

e.g. Put formula in cell c5 as A5+1 when you copy this from c5 to c6 the address of A5 will automatically changed to A6.

Absolute Cell Reference

As above now put formula in cell C5 as $A$5+1 ,now copy this formula from C5 to C6 if you this formula youwill find cell Address of A5 does not changed.

Mixed Cell Reference:

If we put Dollar ($) sign before Alphabetic cell address i.e.$c5 then even if you copy this formula in any cell , coloumn (c) will remains constant.

Similarly if we put Dollar ($) sign before Numeric cell address i.e.c$5 then you copy this formula in any cell row address of the cell remains same.(5).

Pl elobarate on remaining two points 'Specific order of formulas ' and 'advance formulas,

Sep 15, 2007 | Microsoft Office Standard for PC

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