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Posted on Jan 02, 2017

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Jul 03, 2017 | The Computers & Internet

I calculators __you can't__ change or set the base of 'log' is __default 10__ so you need to know these:

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped**☺**

log x (base y) = log x / log y

when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2

log 27 (base 3) = log 27 / log 3

and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y

here so other stuff about 'log' :

log (x*y) = log x + log y

log (x/y) = log x - log y

Hope it's helped

on Jul 07, 2009 | Casio fx-300ES Calculator

Hello Mylene Selle...

I think you are just having in with this ruse... No/Yes?

(to drive up site access...?

**Philippine Government E-Procurement System Guides**

(see bottom of page)

Even on this (FIXYA) site you have no "LOGOUT" button.

You just click on your**user n**ame...

Down drops a dialog box ...

and you choose from one of the many "**OUT**s"

Log... sign... drop... (heck) let's even FLIP-OUT"

A search on the internet reveals this is a

GOVERNMENT site...

So once you are in...

Lookie here:

https://www.bing.com/search?q=philgeps+logout+process&form=EDGEAR&qs=PF&cvid=f94744c8301d4d3fb3d53e93c60f41bf&cc=US&setlang=en-US&PC=DCTE

Perhaps this will help.

Carnac the Magnificent

I think you are just having in with this ruse... No/Yes?

(to drive up site access...?

(see bottom of page)

Even on this (FIXYA) site you have no "LOGOUT" button.

You just click on your

Down drops a dialog box ...

and you choose from one of the many "

Log... sign... drop... (heck) let's even FLIP-OUT"

A search on the internet reveals this is a

GOVERNMENT site...

So once you are in...

Lookie here:

https://www.bing.com/search?q=philgeps+logout+process&form=EDGEAR&qs=PF&cvid=f94744c8301d4d3fb3d53e93c60f41bf&cc=US&setlang=en-US&PC=DCTE

Perhaps this will help.

Carnac the Magnificent

Mar 15, 2017 | The Computers & Internet

http://gppb.topicsolutions.net/t1317-how-to-renew-my-philgeps-certificate

Jan 28, 2015 | Computers & Internet

google is your best friend,just type the keyword...

Jul 08, 2014 | ASUS P4S533-MX MB, DDR+SDR/ VGA/ Audio/...

We'll need more information; like how do you get your email? Gmail, or Yahoo, or your internet service provider. Do you use Outlook, or a web based email. What kind of computer or device are you using to view your email, etc. Thanks!

Jan 13, 2014 | Computers & Internet

Hi,

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

**2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2) **

which is equivalent to**log(4,x) +log(4,3) = -log(4,2)**

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =**- { log(4,2)+log(4,3)}** = -log(4,2*3)

You get**log(4,x)= -log(4,6)**.

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.

Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

which is equivalent to

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) =

You get

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain

log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.

Nov 25, 2009 | Casio FX-300MS Calculator

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

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