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I have a school project I'm trying to resolve, getting prepaired to take my ged.

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Posted on Jan 02, 2017

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We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Hi Jacqueline:

A rectangle has four sides, the lengths of the opposite sides are equal, and the corners are right angles.

The perimeter is the distance around the outside edge, so it would be twice the length plus twice the width.

2 times 5 = 10 feet

2 times 6 = 12 feet

10 plus 12 = 22 feet

What is important is to understand the question.

If you need help with the course, get back to me.

Cheerfuls!

A rectangle has four sides, the lengths of the opposite sides are equal, and the corners are right angles.

The perimeter is the distance around the outside edge, so it would be twice the length plus twice the width.

2 times 5 = 10 feet

2 times 6 = 12 feet

10 plus 12 = 22 feet

What is important is to understand the question.

If you need help with the course, get back to me.

Cheerfuls!

May 13, 2015 | Computers & Internet

That depends on the rectangle.

A 1x19 rectangle has 19 squares.

A 2x18 rectangle has 36 squares.

...

A 9x11 rectangle has 99 squares.

A 10x10 rectangle (a square) has 100 squares.

All of these rectangles have a perimeter of 40.

A 1x19 rectangle has 19 squares.

A 2x18 rectangle has 36 squares.

...

A 9x11 rectangle has 99 squares.

A 10x10 rectangle (a square) has 100 squares.

All of these rectangles have a perimeter of 40.

May 29, 2014 | Computers & Internet

Infinite.

A one meter by 48 meter rectangle has an area of 48 square meters and a perimeter of 98 meters. A one centimeter by 4800 meter rectangle has the same area and a perimeter of 9600.02 meters. A one millimeter by 48,000 meter rectangle has the same area and a perimeter of 96,000.002 meters. A rectangle one micron by 48,000,000 meters has an area of 48 square meters and a perimeter of 96,000,000.000002 meters. Keep making the rectangle skinnier and skinnier without changing the area, and the perimeter keeps getting longer and longer.

A one meter by 48 meter rectangle has an area of 48 square meters and a perimeter of 98 meters. A one centimeter by 4800 meter rectangle has the same area and a perimeter of 9600.02 meters. A one millimeter by 48,000 meter rectangle has the same area and a perimeter of 96,000.002 meters. A rectangle one micron by 48,000,000 meters has an area of 48 square meters and a perimeter of 96,000,000.000002 meters. Keep making the rectangle skinnier and skinnier without changing the area, and the perimeter keeps getting longer and longer.

May 01, 2014 | Computers & Internet

1 tile by 20 tiles - perimeter of 1+ 20 +1 + 20 = 42

2 tiles by 10 tiles - perimeter of 2 + 10 + 2 + 10 = 24

(can't make a rectangle with 3 rows)

4 tiles by 5 tiles - perimeter of 4 + 5 + 4 + 5 = 18

5 tiles by 4 tiles - perimeter of 5 + 4 + 5 + 4 = 18

(can't make a rectangle with 6, 7, 8 or 9 rows)

10 tiles by 2 tiles - perimeter of 10 + 2 + 10 + 2 = 24

20 tiles by 1 tile - perimeter of 20 + 1 + 20 + 1 = 42

So 6 different rectangles. Smallest perimeter is 18.

2 tiles by 10 tiles - perimeter of 2 + 10 + 2 + 10 = 24

(can't make a rectangle with 3 rows)

4 tiles by 5 tiles - perimeter of 4 + 5 + 4 + 5 = 18

5 tiles by 4 tiles - perimeter of 5 + 4 + 5 + 4 = 18

(can't make a rectangle with 6, 7, 8 or 9 rows)

10 tiles by 2 tiles - perimeter of 10 + 2 + 10 + 2 = 24

20 tiles by 1 tile - perimeter of 20 + 1 + 20 + 1 = 42

So 6 different rectangles. Smallest perimeter is 18.

Jan 08, 2014 | Computers & Internet

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Mathsoft StudyWorks! Mathematics Deluxe...

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Computers & Internet

Translate the English into Mathematics.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

**Solve for L: Do it'! **

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is** L'=-4+3W**

and the new perimeter is** P'=2(L'+W)**

Now your turn to do some work.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is

and the new perimeter is

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

The width is 96. Since this sounds like a homework problem, you'll have to show your work.

May 19, 2011 | Texas Instruments TI-84 Plus Calculator

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