Pythagorean triples uses this formula a^2+ b^2= c^2, what does the ^ mean?

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^ means "raised to the power of."

a^2 is "a raised to the power of 2" or "a squared."

Posted on Jul 12, 2013

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Posted on Jan 02, 2017

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3^2=9

4^2=16

9+16=25 =5^2

You can write 3^2+4^2=5^2

(3,4,5) form a Pythagorean triple.

If you construct a right triangle with legs =3 and 4, the hypotenuse will be 5, because in a right triangle the Pythagorean theorem holds true.

It says (leg_1)^2+l(leg_2)^2=(hypotenuse)^2

Other Pythagorean triples are (5,12,13), (9,40,41)

Here is a link to more info on Pythagorean triples

Pythagorean Triples Advanced

4^2=16

9+16=25 =5^2

You can write 3^2+4^2=5^2

(3,4,5) form a Pythagorean triple.

If you construct a right triangle with legs =3 and 4, the hypotenuse will be 5, because in a right triangle the Pythagorean theorem holds true.

It says (leg_1)^2+l(leg_2)^2=(hypotenuse)^2

Other Pythagorean triples are (5,12,13), (9,40,41)

Here is a link to more info on Pythagorean triples

Pythagorean Triples Advanced

Sep 04, 2014 | Office Equipment & Supplies

The equation of a circle is (x-h)^2 + (y-k)^2 = r^, where h and k are the x and y coordinates of the centre of the circle. However the centre is the origin, so we have x^2 + y^2 = r^2.

Now, we need to figure out r. However, we can calculate r because it is the distance from the origin to (-6,2). We can use Pythagorean Theorum, a^2 + b^2 = c^2, were a is -6 and b is 2. We get 6^2 + 2^2 =c^2. c^2= 40.

Thus, the formula of the circle is x^2 + y^2 = 40.

Good luck.

Paul

Now, we need to figure out r. However, we can calculate r because it is the distance from the origin to (-6,2). We can use Pythagorean Theorum, a^2 + b^2 = c^2, were a is -6 and b is 2. We get 6^2 + 2^2 =c^2. c^2= 40.

Thus, the formula of the circle is x^2 + y^2 = 40.

Good luck.

Paul

Apr 14, 2014 | ixl.com

With the insertion of a plus sign it's "a squared plus b squared is equal to c squared." Applied to the Pythagorean Theorem it's "the sum of the squares of the sides is equal to the square of the hypotenuse."

Jul 12, 2013 | Office Equipment & Supplies

Pythagorean Theorem?

The formula should be L=(P-2W)/2 or L= (P/2)-W

P is the perimeter of the rectangle, L its length, and W the width. But where do you hook the Pythagorean Theorem here? In other words, where is the question you are asking?

The formula should be L=(P-2W)/2 or L= (P/2)-W

P is the perimeter of the rectangle, L its length, and W the width. But where do you hook the Pythagorean Theorem here? In other words, where is the question you are asking?

Sep 18, 2012 | Bagatrix College Algebra Solved Full...

This calculator is unable to factor a polynomial expression.

In general there are a few factoring methods

In general there are a few factoring methods

**Factor by grouping terms****Factor by completing the square**(quadratic polynomial)**Factor by finding two integers such their sum is equal to the coefficient of the middle term, and their product is equal to the third (constant term)**. This is valid for a quadratic polynomial where the leading coefficient (of the x^2 term) is equal to 1.**X^2+SX+P**

Jul 31, 2012 | Casio FX-115ES Scientific Calculator

The general answer is no. However the calculator can be used to find the slope and the y-intercept. You write the formula for the rate of change (a) and use the calculator to calculate it. Then you use the formula to find the y-intercept.

If you have 2 points, you can use the 2 -var statistics program to find a linear regression.

If you have 2 points, you can use the 2 -var statistics program to find a linear regression.

Jul 05, 2011 | Casio FX-115ES Scientific Calculator

what do u mean which kind of program

Feb 19, 2010 | Microsoft Visual Basic 6.0 for PC

For this type of problem, a equals the constant cost of operation (monthly rent..etc) and b equals the cost to manufacture the items.

first equation: 320 = a + b(10)

second equation: 520 = a +b(20)

320 = a + 10b

520 = a + 20b subtract equation 2 from equation 1

-200 = -10b divide by -10

20 = b plug b into one of the equations

320 = a +(20)(10) multiply

320 = a +200 subtract 200

120 = a

Let me know if i need to explain further.

first equation: 320 = a + b(10)

second equation: 520 = a +b(20)

320 = a + 10b

520 = a + 20b subtract equation 2 from equation 1

-200 = -10b divide by -10

20 = b plug b into one of the equations

320 = a +(20)(10) multiply

320 = a +200 subtract 200

120 = a

Let me know if i need to explain further.

Dec 29, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Change csc to 1/sin. Find a common denominator and add the two left terms.

1/sin - sin = (1 -sin^2)/sin. Rewrite formula

(1 - sin^2)/sin = cos^2/sin Divide out the /sin.

1 - sin^2 = cos^2 Rearange.

1 = cos^2 + sin^2 Yes, that's true. It's like the Pythagorean formula.

1/sin - sin = (1 -sin^2)/sin. Rewrite formula

(1 - sin^2)/sin = cos^2/sin Divide out the /sin.

1 - sin^2 = cos^2 Rearange.

1 = cos^2 + sin^2 Yes, that's true. It's like the Pythagorean formula.

May 22, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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