I know to go into mode-1 and then QUAD(2) so that I get STAT 2 on my screen, and there is a stat sign on the top right corner. How do I input the values for a, b and c to get the roots (x-values) of the quadratic? I read some other answers but they didn't make sense.
There is some confusion here.
In stat mode [Quad] the calculator tries to fit a quadratic function to your (already entered) data. It gives you the coefficients a, b, and c of the 2nd degree polynomial that best describes the data.
To solve an equation you need to use the solver not statistics.
SOURCE: how do I use sharp EL 531W to solve quadratic equations?
Hello,
This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Callit disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)
2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.
To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.
Hope it helps.
SOURCE: how to solve quadratic equation in SHARP EL-531WH
Hello,
This calculator does not have a program to which you give the
equation, and which returns the solutions. Sorry. You have to use the
formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Call it disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)
2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.
To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.
Hope it helps.
SOURCE: How do I use sharp EL W531 to solve quadratic
Hello,
This calculator does not have a program to which you give the
equation, and which returns the solutions. Sorry. You have to use the
formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Call it disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)
2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.
To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.
Hope it helps.
SOURCE: i am trying to solve
This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation 5x^2+15x+3 =0
This calculator cannot solve equations because it does not have an equation solver.
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do u know how resolt quadratic eqution on ypur sharp El-531XG?? plz tell me if you know thxx you !!!
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