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3 +/- sqrt(19) .

In words, three plus and minus the square root of 19.

If this is homework, make sure you show your work.

Posted on May 06, 2013

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Posted on Jan 02, 2017

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To find the x-intercept, set y equal to zero and solve for x.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

Nov 06, 2014 | Computers & Internet

If you plot this, it is approximately a straight line (with a y error or +/-.2). An ideal straight line would have y points of 7,8,9,10,11,12 for the given x's. The formula for this line is y=.5x + 6 . The gradient (slope) is .5 and the intercept is 6.

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

The gradient can be calculated using the formula:

(y2-y1)/(x2-x1) = (12-7)/(10-2) = 5/10 = 0.5

The intercept is where the graph crosses the y axis and can be calculated once the gradient is known by substituting any associated x and y into the formula: y=.5x + i (where i is intercept). For example the point (2,7) gives 7 = .5(2) +i

7 = 1 + i

6 = i

or using (12,12), 12 = (.5)(12) + i

12 = 6 + i

6 = i

Mar 01, 2014 | Office Equipment & Supplies

First of all you equation is not one : it has nothing on the right side of the = sign. But to answer the general question let us write the equation as **50+25x-5y=0**

**X-intercept (also know as roots) There may be several**

Definition: X-intercepts are those values of the independent variable x**for which y=0**. For a straight line there con be at most 1 x-intercept.

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is** x=-(50/25)=-2**

**Y-intercept (also know as the initial value.** There can only be 1 y-intercept, otherwise the expression does not represent a function.

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

**50+25x-5y=0**

50+25(0)-5y=0, or 50-5y=0. The solution is**y=50/5=10**

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Definition: X-intercepts are those values of the independent variable x

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

50+25(0)-5y=0, or 50-5y=0. The solution is

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Jan 28, 2014 | Computers & Internet

I will not try to make sense of the context (there is no a). You have a linear relation between two variables x and s (y). Here is how you find the x- and y-intercepts.

x-intercepts (or zeros, roots).

**The x-intercepts are the values of x when y=0. There could be several x-intercepts.**

Set y=0 in the relation 90=6x+3(0) or x=90/6=15. Note: for a linear function**y=ax+b **there is only one x-intercept.**x=-b/a**

**y-intercept**. For a function there can only be **one y-intercept**.

I**t is the value of y when x=0**

Set x=0 in 90=6(0)+3y, This gives** y=90/3=30**

The coordinates of the points of intersection of the line with the axes are (15, 0) and (0,30).

x-intercepts (or zeros, roots).

Set y=0 in the relation 90=6x+3(0) or x=90/6=15. Note: for a linear function

I

Set x=0 in 90=6(0)+3y, This gives

The coordinates of the points of intersection of the line with the axes are (15, 0) and (0,30).

Nov 11, 2013 | Computers & Internet

Isolate the y by subtracting 10x from both sides to get y=9-10x .

The slope is the factor of x, in this case -10 .

The intercept is the constant term, in this case 9 .

The slope is the factor of x, in this case -10 .

The intercept is the constant term, in this case 9 .

Oct 15, 2012 | Office Equipment & Supplies

The x intercept is where your line will cross the x axis. Therefore, the value for y at this point is 0. Substitute 0 for y in this equation and solve for x.

6x + 3(0) = 27

x = 27/6

x = 4 1/2

x intercept = (4 1/2, 0)

Follow the same reasoning for the y intercept.

6(0) + 3y = 27

y = 27/3

y = 9

y intercept = (0,9)

Now plot these two points and draw your line through them.

6x + 3(0) = 27

x = 27/6

x = 4 1/2

x intercept = (4 1/2, 0)

Follow the same reasoning for the y intercept.

6(0) + 3y = 27

y = 27/3

y = 9

y intercept = (0,9)

Now plot these two points and draw your line through them.

May 18, 2012 | SoftMath Algebrator - Algebra Homework...

Use the definitions of the intercepts.

x-intercepts (or zeros or roots) are the values of the independent variables that make the function equal to zero. To obtain an intercept set y=0 in equation : 5x=-10, mean x=-10/5=-2

y-intercept: value of y when x=0.

Just set x=0 in equaltion and solve for y

-4y=-10, gives y=5/2

And Sorry, I cannot enter the answer in the drop box.

x-intercepts (or zeros or roots) are the values of the independent variables that make the function equal to zero. To obtain an intercept set y=0 in equation : 5x=-10, mean x=-10/5=-2

y-intercept: value of y when x=0.

Just set x=0 in equaltion and solve for y

-4y=-10, gives y=5/2

And Sorry, I cannot enter the answer in the drop box.

May 10, 2012 | SoftMath Algebrator - Algebra Homework...

x-intercept: set y=0, and find x=4

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

Jan 12, 2012 | Mcgraw-Hill Glencoe Algebra 1 Florida...

x-intercept (or zero of the function)

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Aug 27, 2011 | Texas Instruments TI-84 Plus Calculator

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