# How many combinations for the numbers 1, 2, 3, 4, 5 and 6?

How many different combinations are there for the numbers 1, 2, 3, 3, 4, 5 and 6?

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That depends on how many of those six numbers you take.
If you only take one number, there are six combinations.
If you take two numbers, there are fifteen combinations.
If you take three numbers, there are twenty combinations.
If you take four numbers, there are fifteen combinations.
If you take five numbers, there are six combinations.
If you take all six numbers, there is only one combination.
In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

Posted on Apr 30, 2013

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Posted on Jan 02, 2017

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You need to send them a notarized letter showing safe ownership in order to get the master combination. When you call Honeywell, you will need to provide your safe's model number, the serial number (found on the right of the safe, near the model number), and your key number.

Jan 04, 2017 | Home Security

### How many different number combinations are there using the numbers 1 1 0 8

I assume you mean different decimal numbers, using those four digits, right? If so, the answer can be reached two ways.

One way is to actually build up the model by changing one digit at a time, then moving a decimal place. Thus: 1108, 1101, 1100 then 1118, 1111, 1110 then 1188, 1181, 1180 and so on. You will count 81 combinations.

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There is only one combination using all five digits, namely 1, 2, 3, 4, 7 in some order.

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### Number combinations

One-number combinations: { 1 2 6 9 }
Two-number combinations: { 12 16 19 26 29 69 }
Three-number combinations: { 126 129 169 269 }
Four-number combinations { 1269 }

Or did you want permutations?

Jul 07, 2014 | Computers & Internet

### I want to know how many combinations you can get using the numbers 1 to 20

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### Does anybody know how many different combinations there are for the numbers 1, 2, 3, 4, 5 and 6?

That depends on how many of those six numbers you take.
If you only take one number, there are six combinations: {1}, {2}, {3}, {4}, {5}, and {6}.
If you take two numbers, there are fifteen combinations: {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,3}, {2,4}, {2,5}, {2,6}, {3,4}, {3,5}, {3,6}, {4,5}, {4,6}, and {5,6}.
If you take three numbers, there are twenty combinations.
If you take four numbers, there are fifteen combinations.
If you take five numbers, there are six combinations.
If you take all six numbers, there is only one combination: {1,2,3,4,5,6}.
In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

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Buy the identical lock if possiable and return as defective and they will reset. Otherwise odds or 1 in 999,000 differant combos. This is airport baggage security lock.

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Are all five numbers coming from the pool for 35 numbers?

if yes the combinations would be

35 x 34 x 33 x 32 x 31

38,955,840

if not from one pool but five different pools for 35 then it would be 35 to the 5th power
or
35 x 35 x 35 x 35 x 35

52,521,875

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