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Algebra equations if a=3,b=-2,c=0,d=-1 what is ab-2d+ac

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Go through the expression replacing each letter symbol by its value then perform the operations
3*(-2)-2*(-1)+(3*0)=-6+2+0=-4

Posted on Oct 18, 2013

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-1 (negative one).
If this is homework, be sure to show your work.

Posted on Apr 30, 2013

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Posted on Jan 02, 2017

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How to graphing regarding ohter axes?


Add a graph .
In Documents Toolbox, select 3: Graph/Entry Edit
Unfold the menu and select Equation (not function). Enter your equation.
For the 3D part, I am afraid you will have to read the manual.

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1 Answer

8x + 3y = 3 4x + 5y = -23


This is best written as two separate equations:

8x+3y = -23 and 34x+ 5y = -23
Solving the first one for x:
8x = -23-3y
x = -23/8 - 3/8y
Substituting this value for x into the second equation:
34(-23/8 - 3/8y) + 5y = -23
-97.75 - (34)(.375)y + 5y = -23
-97.75 - 12.75y + 5y = -23
-97.75 -7.75y = -23
-7.75y = 97.75-23=74.75
y = -74.75/7.75 = -9.645161
Substitution back into the equation for x:
x = -23/8 - 3/8(-9.645161)
x = -2.875 + 3.616935
x =.741935

Dec 12, 2014 | Bagatrix Algebra Solved! 2005 (105101) for...

1 Answer

Maths equation


(-9/3)x=-2
First simplify -9/3 to -3 : -3x=-2
Divide by -3.
x=-2/-3=2/3

Oct 24, 2013 | Office Equipment & Supplies

1 Answer

How to factor 5x^2-3x-10 ?


This equation doesn't have whole number factors so you have to solve it by completing the square or using the quadratic equation. I used the quadratic equation and got the following answers.

[3 + sqrt(209)]/10 and [3 - sqrt(209)]/10

I hope this helps you out.

Jul 05, 2011 | SoftMath Algebrator - Algebra Homework...

1 Answer

Make an outline about the subject math alebra


Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics.
Factors and expansions a, b real; n positive integer (a ± b)² = a² ± 2ab + b²
(a ± b)³ = a³ ± 3a²b + 3ab² ± b³
(a ± b)4 = a4 ± 4a³b + 6a²b² ± 4ab³ + b4
a² - b² = (a - b)(a + b)
a² + b² = (a - bi)(a + bi)
a³ - b³ = (a - b)(a² + ab + b²)
a³ + b³ = (a + b)(a² - ab + b²)
a4 + b4 = (a² + 2½ab + b²)(a² - 2½ab + b²)
an - bn = (a - b)(an-1 + an-2b + ... + bn-1), for n even
an + bn = (a + b)(an-1 - an-2b - ... - bn-1), for n odd


Jun 19, 2011 | Computers & Internet

4 Answers

Fred is 3 years older than his sister mary, in 7 years she will be six-sevenths of his age. how old are they?


Fred = Mary +3
7*mary = 6/7 *Fred
substitute fred =mary + 3
7m = 6/7 * (mary + 3) 7m = 6/7*m + 6/7*3 7m - 6/7*m = 6/7*3 m(7-6/7)= 6/7*3
m = (6/7*3) / (7-6/7) m=0.419 years old
substitue m into fred = mary+3 Fred = 3.419 Years old

Jun 08, 2011 | Computers & Internet

1 Answer

I need assistance understanding this algebra equation and the steps to solve it. 7+(9-5x)=5(2-x)


this is a simple algebraic equation in which we have to calculate the value of 'x' using simple operations

7+(9-5x)=5(2-x)


step 1(pen the brackets) 7+9-5x=10-5x
step 2(add 7 and 9) 16-5x=10-5x

now as 5x gets cancelled both the sides of the equal sign therefore no solution of this algebraic equation exist.

Mar 24, 2011 | MathRescue Word Problems Of Algebra Lite

1 Answer

How to factor a polynomial equation on casio fx-300es?


Hello,
The Casio FX-300ES does not handle symbolic algebra. So it cannot factor a general polynomial expression. The methods can be found in any book on Algebra.
However if you are interested in approximate factorization of quadratic and cubic polynomials, you can use the calculator to do that. It can solve aX^3 +bX^2+cX+d =0 and the quadratic equations.

If you want to factor a cubic polynomial P3(X) = aX^3+bX^2+cX+d , you write the corresponding cubic equation as aX^3+bX^2+cX=d =0 , then you divide all terms of the equation by a to obtain

X^3+(b/a)X^2+(c/a)X+(d/a)=0.

You use the calculator to solve (approximately) this equation.
Suppose you find the 3 roots X1,X2,and X3. Then the polynomial X^3+(b/a)X^2+(c/a)X+(d/a) can be cast in the factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can be written as

P3(X) = a*(X-X1)(X-X2)(X-X3)

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots

Hope it helps.

Sep 27, 2009 | Casio fx-300ES Calculator

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