What is the height of a rectangle with perimeter 132.8 mm and base length 60.2 mm?

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Posted on Jan 02, 2017

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Posted on Apr 19, 2010

perimeter is 2X( L + B)

so that is 2 X (11+12)= 2 X 23 = 46 yards

area is LX B =11X12=132 square yards

grade 3 maths really

so that is 2 X (11+12)= 2 X 23 = 46 yards

area is LX B =11X12=132 square yards

grade 3 maths really

Aug 03, 2017 | The Computers & Internet

the perimeter of any square sided object is 2 times the height added to 2 times the width: (2h)+(2w). The actual answer for your sizes is 46 yards given by 2 times 11 plus 2 times 12. Hope this helps.

Aug 03, 2017 | The Computers & Internet

We are given the following data:

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

length = 5/2 * width

length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5

width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width

Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width

Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Mathsoft StudyWorks! Mathematics Deluxe...

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Computers & Internet

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

A hexagonal based prism has a lateral area that is made up of 6 rectangular faces. If the hexagon at the base is regular, all the lateral rectangles are congruent (identical).

To calculate the lateral area of one of the rectangular faces you need to multiply the length of a side (s) of the regular hexagon by the height (h).

For the lateral area of the prism use A_l=6*s*h=P_b*h, where P_b is the perimeter of the base.

Sorry I cannot proceed further, because**"using the area and the height?"** is not clear enough for me.

To calculate the lateral area of one of the rectangular faces you need to multiply the length of a side (s) of the regular hexagon by the height (h).

For the lateral area of the prism use A_l=6*s*h=P_b*h, where P_b is the perimeter of the base.

Sorry I cannot proceed further, because

May 22, 2013 | Computers & Internet

The total area of the prism is made up of the areas of the two bases plus the lateral area.

Atotal =2 A_base +P_base*height. Here A_b is the area pf a base, and P_b is the perimeter of the base.

If you take the base to be a rectangle with length L=9in, and width W=4 in, then**height= 6 in.**

With this choice**A_b=9*4=36 sq. in**

**P_b=2*(9+4)=26 in.**

Now I leave the rest to you.

Understand this calculation and apply it to the other similar questions you posted.

Atotal =2 A_base +P_base*height. Here A_b is the area pf a base, and P_b is the perimeter of the base.

If you take the base to be a rectangle with length L=9in, and width W=4 in, then

With this choice

Now I leave the rest to you.

Understand this calculation and apply it to the other similar questions you posted.

Mar 05, 2013 | Computers & Internet

Translate the English into Mathematics.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

**Solve for L: Do it'! **

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is** L'=-4+3W**

and the new perimeter is** P'=2(L'+W)**

Now your turn to do some work.

W=L-5 (in inches)

P=2(L+W)=2(L+L-5)=2(2L-5)

Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)

P=4L-10.

Set P= 50 (inches), to get 4L-10=50

Find W= L (the one you just found) -5 =

Now, with W the value you just calculated

the new length is

and the new perimeter is

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

All triangles have three sides.

There are two main formulas that do not call on trigonometric ratios.

**The classic one**:

*Heron's Formula *if you have the length of the three sides. Let those measures be **a, b,** and** c**.

There are two main formulas that do not call on trigonometric ratios.

- 1. You need the length of a base and it corresponding height (the length of the segment perpendicular to that base and passing through the vertex (summit) opposite to that base.
**Area=(1/2) * (measure of the base)*(measure of the height).**The base and height must be expressed in the same unit.

- Calculate the semi-perimeter p with
**p=(1/2)(a+b+c)** - Area=Square root of
**(p*(p-a)*(p-b)*(p-c))** **a, b, and c must be expressed in the same unit.**

May 21, 2011 | Casio FX82ES Scientific Calculator

Jun 25, 2018 | Computers & Internet

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