I'm a calculus student trying to get around a domain error. I understand cos^-1 general domain is -1

If you're in the MATHPRINT mode, press

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 right-arrow ) / 2 5 ENTER

If you're in the CLASSIC mode, press

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 ) ) / 2 5 ENTER

In either case you should get an answer of about 103.

Posted on Apr 27, 2013

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Posted on Jan 02, 2017

**Domain errror** meaning that an argument must be in a specified domain.

It's not clearly what do you want to do but for three possible options solutions are on the captured images below(for radian mode).

Posted on Feb 23, 2013

SOURCE: "Err: Domain"

I think you may find arcsin(x) is equivalent in older nomenclature to sin^-1 (x)...ie use the "2nd" and the SIN key instead of typing arcsin.

eg. arcsin(0.5) is 30 degrees is the same as sin^-1(0.5)

The ^-1 does not mean reciprocal, but "the angle whose sin is." Here the minus one indicates a kind of inverse operation. The word arcsin indicates that same inverse.

Posted on Mar 05, 2010

Here is a set.

Angles are in radians.

Angles are in radians.

Oct 17, 2014 | Miscellaneous

The sine and cosine of an angle have values in the closed interval [-1,1]. That means

When you consider the inverse problem where you want to find the angle whose sine or cosine is known, you must take the values of the sine or cosine in the interval [-1,1]. That is the domain of the functions arc sine and arc cosine. So if you take a value outside the domain [-1,1], and want to calculate the angle to which it belongs, the calculator signals that there a domain error, because there is no angle that answers the question.

Mar 30, 2014 | Office Equipment & Supplies

The arccosine function is defined for arguments in the range from -1 to +1. 50/30 is greater than 1 and thus is out of the domain.

Feb 06, 2014 | Texas Instruments TI 30XIIS Scientific...

It's not clearly what do you want to do but for three possible options solutions are on the captured images below(for radian mode).

Feb 23, 2013 | Texas Instruments TI-89 Calculator

Make sure the argument is between negative one and positive one, inclusive. The inverse cosine is defined only for arguments in that domain, anything else will give you a domain error.

Oct 26, 2011 | Texas Instruments TI-84 Plus Calculator

You didn't say which part of mathematics you want to study or what is you previous knowledge.

For algebra see these courses:

On The Open University you can find even more courses and on this site you can find links to a lot of online resources for algebra (lessons, tutorials, games, problems...).

For calculus I recommend:

And if you have questions or you don't understand something you can ask here.

I hope I helped you :)

For algebra see these courses:

- Visual Math Learning
- Math.com (this site also has section for practicing math problems)
- Algebra 1 (interactive UC college prep course)

On The Open University you can find even more courses and on this site you can find links to a lot of online resources for algebra (lessons, tutorials, games, problems...).

For calculus I recommend:

And if you have questions or you don't understand something you can ask here.

I hope I helped you :)

Sep 09, 2011 | Office Equipment & Supplies

Is there a question? Why so secretive, spill it out.

To access the arc cosine (cos^-1) press 2nd COS and enter the argument. Make sure you are within range, because the domain of arc cosine is from -1 to +1. Any value outside of this closed interval will warrant a DOMAIN ERROR.

To access the arc cosine (cos^-1) press 2nd COS and enter the argument. Make sure you are within range, because the domain of arc cosine is from -1 to +1. Any value outside of this closed interval will warrant a DOMAIN ERROR.

May 29, 2011 | Texas Instruments TI-83 Plus Calculator

I do not know the program you installed, so I will skip the part.

As to the derivative of the sine function, your result is correct if the angle unit is degree.

d(sin(x))/dx = cos(x) is true only if the angle unit is the radian. In degrees, you would have a factor Pi/180 which is 0.174532925. I suggest you consult a calculus book to understand where that factor comes from.

As to the derivative of the sine function, your result is correct if the angle unit is degree.

d(sin(x))/dx = cos(x) is true only if the angle unit is the radian. In degrees, you would have a factor Pi/180 which is 0.174532925. I suggest you consult a calculus book to understand where that factor comes from.

Mar 17, 2011 | Texas Instruments TI-89 Calculator

You are indeed committing an error. The sequence [2nd][COS] is activating the function arcosine or arccos or cos^-1, the inverse of the cosine function. If you remember the properties of the cosine functions, you know that cos(x) is defined over the real line ]- infinity to infinity[, but its range spans the interval [-1,1].

Since the arcosine function is the inverse of the cosine, its domain of definition is the range of the cosine, namely the closed interval [-1,1].

Thus if you enter [2nd][COS][3180.04] the calculator flags this as a domain error, because 3180.04 is outside the interval [-1,1]

Restrict the argument of cos^-1 to any value inside the closed interval [-1,1].

When manipulating the trigonometric functions and their inverses you must keep in mind that the results you get are dependent on the angle unit your calculator is configured for (deg, rad).

Since the arcosine function is the inverse of the cosine, its domain of definition is the range of the cosine, namely the closed interval [-1,1].

Thus if you enter [2nd][COS][3180.04] the calculator flags this as a domain error, because 3180.04 is outside the interval [-1,1]

Restrict the argument of cos^-1 to any value inside the closed interval [-1,1].

When manipulating the trigonometric functions and their inverses you must keep in mind that the results you get are dependent on the angle unit your calculator is configured for (deg, rad).

Jun 29, 2010 | Texas Instruments TI-84 Plus Calculator

The cosine function takes its value on the whole real line, the angle domain spans ]-infinity, + infinity[. The range of the function is however limited to the [-1, +1] interval.

Thus if you want to calculate the arc (angle) from the value of the cosine, the cosine must be in the interval [-1, +1]. Any value outside this domain will give you a domain error.

Check that the values you feed to the arc cosine function are in the interval [-1,+1].

If the angle unit is the degree the value returned bay [cos^-1] is in degrees, and if the angle unit is the radian, the value returned is in radians

Thus if you want to calculate the arc (angle) from the value of the cosine, the cosine must be in the interval [-1, +1]. Any value outside this domain will give you a domain error.

Check that the values you feed to the arc cosine function are in the interval [-1,+1].

If the angle unit is the degree the value returned bay [cos^-1] is in degrees, and if the angle unit is the radian, the value returned is in radians

Mar 04, 2010 | Texas Instruments TI-89 Calculator

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