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Class Not Found...Java/lang/class not found Exception

Posted by Anonymous on

5 Suggested Answers

6ya6ya
  • 2 Answers

SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
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goodluck!

Posted on Jan 02, 2017

shevng
  • 175 Answers

SOURCE: Aim Problem?

its your program must go to your nearest service center to reprogram your phone.



peace!

Posted on Dec 15, 2007

  • 317 Answers

SOURCE: my caculator is disappeared after

This problem can only be solved by formatting the mobile completely.
below is link given for formatting the mobile

http://www.fixya.com/support/r5875102-format_nokia_mobile_phones_3110c_2700c

Posted on Mar 01, 2011

  • 943 Answers

SOURCE: Array index out of bounds

it is an error in java which arises when ur request is out of the applications reach ....

Posted on Sep 26, 2011

  • 154 Answers

SOURCE: null pointer java/lang/nullpointer exception error in nokia 5130 in calculator

Calculator program in your mobile is affectedso Update the mobile softwareor else FLASH it

Posted on Nov 13, 2011

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What is Java/lang/IllegalAccessError: Cannot Access class com/nokia/mid/impl/jms/core/MIDletRegistry from class napi/bf?


No Mobile Phone user wants to see error messages like this.
This is for programmers,
As Microsoft now own Nokia, perhaps they can assist with this Java Language problem. Lucky Microsoft....!
Some phones are just not user friendly or "smart"
Thats why Nokia are no longer Mobile Phone leaders.

Jul 22, 2014 | Nokia Asha 200 Mobile Phone - Unlocked/No...

1 Answer

Java/lang/IllegalAccessError: Cannot Access class com/nokia/mid/impl/jms/core/MIDletRegistry from class napi/bf


Java/lang/IllegalAccessError: Cannot Access class com/nokia/mid/impl/jms/core/MIDletRegistry from class napi/bf

Jul 16, 2013 | Nokia X Cell Phones

2 Answers

What is strings in java?


Handling character strings in Java is supported through two final
classes: Java String and StringBuffer. The String class implements immutable character strings, which are read-only once the string has been created and initialized, whereas the StringBuffer class implements dynamic character strings. All string literals in Java programs, are implemented as instances of String class. Strings in Java are 16-bit Unicode.

Nov 21, 2012 | Sun Java Programming Language (cdj-275)

1 Answer

Can't check missed calls shows Uncaught Exception:java.lang.null


Hi,
When attempting to access a corrupted call list database on the BlackBerry smartphone, the Uncaught exception:java.lang.NullPointerException error message appears:

Isolate the corrupt data by turning on advanced logging for Intellisync.
  1. Turn on advanced logging for Intellisync.
  2. Once the corrupt data entry has been isolated, delete it from the desktop email client and the BlackBerry smartphone.
I Hope it helped you.
Thank you for using ' Fixya ' and have a nice day!!

Nov 10, 2009 | RIM BlackBerry Pearl Flip 8220 Cellular...

4 Answers

Java is not working


Hello there :
first you are going to want to ensure that your your current version of java is installed correctly and is not corrupted and if it needs to be reinstalled
download the latest java version and reinstall this . www.java.com
this should be able to take care of the problem that you are having ok?
best regards michael

Aug 23, 2009 | ArcMedia JavaScript Source Code 3000 Pro...

1 Answer

How to write jdbc connections


http://www.jdbc-tutorial.com/

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welcome_title_image.gif Java JDBC Tutorial Java JDBC Tutorial
The JDBC ( Java Database Connectivity) API defines interfaces and classes for writing database applications in Java by making database connections. Using JDBC you can send SQL, PL/SQL statements to almost any relational database. JDBC is a Java API for executing SQL statements and supports basic SQL functionality. It provides RDBMS access by allowing you to embed SQL inside Java code. Because Java can run on a thin client, applets embedded in Web pages can contain downloadable JDBC code to enable remote database access. You will learn how to create a table, insert values into it, query the table, retrieve results, and update the table with the help of a JDBC Program example.


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Although JDBC was designed specifically to provide a Java interface to relational databases, you may find that you need to write Java code to access non-relational databases as well.
JDBC Architecture jdbc.jpg Java application calls the JDBC library. JDBC loads a driver which talks to the database. We can change database engines without changing database code.
JDBC Basics - Java Database Connectivity Steps Before you can create a java jdbc connection to the database, you must first import the
java.sql package.
import java.sql.*; The star ( * ) indicates that all of the classes in the package java.sql are to be imported.
1. Loading a database driver,
In this step of the jdbc connection process, we load the driver class by calling Class.forName() with the Driver class name as an argument. Once loaded, the Driver class creates an instance of itself. A client can connect to Database Server through JDBC Driver. Since most of the Database servers support ODBC driver therefore JDBC-ODBC Bridge driver is commonly used.
The return type of the Class.forName (String ClassName) method is “Class”. Class is a class in
java.lang package.
try { Class.forName(”sun.jdbc.odbc.JdbcOdbcDriver”); //Or any other driver } catch(Exception x){ System.out.println( “Unable to load the driver class!” ); } 2. Creating a oracle jdbc Connection

The JDBC DriverManager class defines objects which can connect Java applications to a JDBC driver. DriverManager is considered the backbone of JDBC architecture. DriverManager class manages the JDBC drivers that are installed on the system. Its getConnection() method is used to establish a connection to a database. It uses a username, password, and a jdbc url to establish a connection to the database and returns a connection object. A jdbc Connection represents a session/connection with a specific database. Within the context of a Connection, SQL, PL/SQL statements are executed and results are returned. An application can have one or more connections with a single database, or it can have many connections with different databases. A Connection object provides metadata i.e. information about the database, tables, and fields. It also contains methods to deal with transactions.
JDBC URL Syntax:: jdbc: <subprotocol>: <subname> JDBC URL Example:: jdbc: <subprotocol>: <subname>•Each driver

Feb 01, 2009 | Microsoft Windows XP Home Edition

1 Answer

Unable to View Java Applet


"load: class JFI.class not found."
Based on the console output, it means that it cannot find the java applet class. In other words, the applet is missing on the server side. There is nothing that you can do about it, unless you know the person who created the applet. Good luck :)

Dec 23, 2008 | ArcMedia JavaScript Source Code 3000 Pro...

2 Answers

StartActivity fails to launch class called


This example is working try it.

Forwarding.java
----------------------

package com.example.android.apis.graphics;
import android.app.Activity;
import android.content.ActivityNotFoundException;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
public class Forwarding extends Activity
{
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.forwarding);
Button goButton = (Button)findViewById(R.id.go);
goButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
try {
Intent intent = new Intent();
intent.setClass(Forwarding.this, ForwardTarget.class);
startActivity(intent);
finish();
} catch(Exception e) {
System.out.println(e.getMessage());
}
}
});
}
}


ForwardTarget
--------------------

package com.example.android.apis.graphics;
import android.app.Activity;
import android.os.Bundle;
public class ForwardTarget extends Activity
{
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);

setContentView(R.layout.forward_target);
}
}



AndroidManifest.xml
-----------------------------

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.android.apis.graphics"
android:versionCode="1"
android:versionName="1.0.0">
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".Forwarding"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".ForwardTarget"/>
</application>
</manifest>


forwarding.xml
---------------------

<?xml version="1.0" encoding="utf-8" ?>

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:padding="4dip"
android:gravity="center_horizontal" android:layout_width="fill_parent"
android:layout_height="fill_parent">
<TextView android:layout_width="fill_parent"
android:layout_height="wrap_content" android:layout_weight="0"
android:paddingBottom="4dip" android:text="forwarding" />
<Button android:id="@+id/go" android:layout_width="wrap_content"
android:layout_height="wrap_content" android:text="go">
<requestFocus />
</Button>
</LinearLayout>

forward_target.xml
---------------------------

<?xml version="1.0" encoding="utf-8" ?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:padding="4dip"
android:gravity="center_horizontal" android:layout_width="fill_parent"
android:layout_height="fill_parent">
<TextView android:layout_width="fill_parent"
android:layout_height="wrap_content" android:layout_weight="0"
android:text="forward_target" />
</LinearLayout>


Nov 03, 2008 | Google Android

2 Answers

I closed my Eclipse editor after usual work; and i came on next day to office,try to open it ,but not getting opened by saying "An error has occured .see the log file"


Start by looking at the last line:

MESSAGE Missing required bundle org.eclipse.gef_0.0.0.

Looks like it can't find the GEF (graphical editing framework) libraries. They should be in your eclipse/plugins directory - if not, download a fresh copy from http://www.eclipse.org/gef/downloads/ and extract into the plugins directory.

Can you post the output after doing this, so we can see if the Quantum / OSGI libs are missing too?

Sep 18, 2007 | Eclipse 5443

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