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Write the function as a set of ordered pairs, Give the domain and range of f. f(a)=t,f(b)=s,f(c)=q,f(d)=t

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  • k24674 Apr 20, 2013

    Domain is {a,b,c,d}, and the range is {t,s,q}

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An ordered pair is made up of two values written in a specified order. In functions, an ordered pair is made up of a value from the definition domain followed by its corresponding value in the range.
To a corresponds t thus the pair is (a,t)
To b corresponds s, the pair is (b,s)
To c corresponds q, the pair is (c,q)
The last pair is (d,t)
You can now define your function as a set of ordered pairs f: {(a,t),(b,s), (c,q), (d,t) }. When you write the set, the order of the pairs is not important. Just make sure THAT IN EACH PAIR the first listed is from the set {a,b,c,d } and the second listed is from
{t,s,q }. The second t in the last set cannot be written because no repetition is allowed in sets.

Posted on Apr 20, 2013

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SOURCE: Inputting the Domain Range

Feb 26, 2010 - I was right to suggest to you to read the page on domain and range of functions: it would have clarified the concepts to you.
The domain of the sine function is from -infinity to + infinity. But since the function is periodic, with a period equal to 2Pi, by limiting the DOMAIN of values to -1*Pi to +1*PI you see all there is to see. All the rest can be obtained by translation of the curve.

The RANGE of the sine function is LIMITED to values in the interval [-1, 1]
Let us summarize: The DOMAIN of the sine function is ]-infinity, +infinity[ and its RANGE is [-1,+1].
That being said, there is something I would like to point to you
These are the numbers.

You want a "square", so be it. Here is the window setting
and the corresponding picture. Does it look like a square?

c12c0fa.jpg ade7a0b.gif

Why do you insitst on drawing a square? Horizontally you have the angle ( a number with a unit), while vertically you have a ratio of two lengths ( a pure number). Would even think about a square if you drew your sine function with the degree as angle unit. Horizontally you would have a domain [-180 degrees, 180 degrees] while vertically you have a range [-3.14..., +3.14...]. How can that be a square?

I showed you how you can fix every dimension in the graph window (see the first picture) . Choose any values that you believe will give you a square graph. And I do mean to say "that make you believe", because there is no meaning attached to the "fact" that the window looks like a square. An angle cannot be compared to a the projection of one side of a right triangle onto the hypotenuse.

Posted on Feb 26, 2010

  • 135 Answers

SOURCE: Inputting a Domain within a Rang

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Posted on Jun 25, 2010

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SOURCE: I am trying to find

Go to Y= and you will see Plot 1, Plot 2 and Plot 3 at the top of the screen. One of these is highlighted. Navigate the cursor to the highlighted option(s) and press Enter to deselect it.

This error happens when you are trying to graph data in a list and the lists are either empty or not the same length.

Posted on Mar 06, 2011

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Feb 26, 2010 - I was right to suggest to you to read the page on domain and range of functions: it would have clarified the concepts to you.
The domain of the sine function is from -infinity to + infinity. But since the function is periodic, with a period equal to 2Pi, by limiting the DOMAIN of values to -1*Pi to +1*PI you see all there is to see. All the rest can be obtained by translation of the curve.

The RANGE of the sine function is LIMITED to values in the interval [-1, 1]
Let us summarize: The DOMAIN of the sine function is ]-infinity, +infinity[ and its RANGE is [-1,+1].
That being said, there is something I would like to point to you
These are the numbers.

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and the corresponding picture. Does it look like a square?

c12c0fa.jpg ade7a0b.gif

Why do you insitst on drawing a square? Horizontally you have the angle ( a number with a unit), while vertically you have a ratio of two lengths ( a pure number). Would even think about a square if you drew your sine function with the degree as angle unit. Horizontally you would have a domain [-180 degrees, 180 degrees] while vertically you have a range [-3.14..., +3.14...]. How can that be a square?

I showed you how you can fix every dimension in the graph window (see the first picture) . Choose any values that you believe will give you a square graph. And I do mean to say "that make you believe", because there is no meaning attached to the "fact" that the window looks like a square. An angle cannot be compared to a the projection of one side of a right triangle onto the hypotenuse.

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6a4af11.jpg

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6cfb89a.jpg

Now rate all the solutions I provided for you

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