Question about Bagatrix Algebra Solved! 2005 (105101) for PC

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Posted on Jan 02, 2017

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | Computers & Internet

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | SoftMath Algebrator - Algebra Homework...

If your question is the inverse of 3x / (4x - 1) then

(4x - 1) / 3x

If you meant (3x / 4x) - 1 then

- 4

(4x - 1) / 3x

If you meant (3x / 4x) - 1 then

- 4

Jun 26, 2014 | SoftMath Algebrator - Algebra Homework...

4X+3-3=3X-4-3=3X-7

4X=3X-7

4X-3X=3X-3X-7

X=-7

The answer is X=-7

4X=3X-7

4X-3X=3X-3X-7

X=-7

The answer is X=-7

Dec 06, 2011 | Knowledge Adventure Math Blaster...

3x - 1 = ?

So we'll add 1 to each side of the equation (whatever you do to one side of the = sign, you have to do to the other):

3x = 1

Then, we'll divide both sides by 3, thus leaving us with:

Answer: x = ⅓

So we'll add 1 to each side of the equation (whatever you do to one side of the = sign, you have to do to the other):

3x = 1

Then, we'll divide both sides by 3, thus leaving us with:

Answer: x = ⅓

Mar 24, 2010 | SoftMath Algebrator - Algebra Homework...

I THINK YOU WANT TO KNOW THE VALUE OF X

X+4+2/3 = 6

(3X +12+2)/3 = 6

3X+14 = 3*6

3X + 14 =18

3X = 18 - 14

3X = 4

X = 4/3

X = 1.333 this is answer

X+4+2/3 = 6

(3X +12+2)/3 = 6

3X+14 = 3*6

3X + 14 =18

3X = 18 - 14

3X = 4

X = 4/3

X = 1.333 this is answer

Nov 04, 2009 | SoftMath Algebrator - Algebra Homework...

The possible solutions are

x= -y/3

y= -3x/1

x= -y/3

y= -3x/1

Feb 26, 2009 | Bagatrix Algebra Solved! 2005 (105101) for...

7x-3 + 3x = -53

7x + 3x - 3 = -53

10x - 3 = -53

10x = -53 + 3

10x = -50

x = -5

Therefore 4x + 9 is equal to 4 times (-5) plus 9

-20 + 9 equals -11

7x + 3x - 3 = -53

10x - 3 = -53

10x = -53 + 3

10x = -50

x = -5

Therefore 4x + 9 is equal to 4 times (-5) plus 9

-20 + 9 equals -11

Dec 17, 2008 | SoftMath Algebrator - Algebra Homework...

(x+3y=0)*3=3x+9y

y=1 x= -3

y=1 x= -3

Jun 29, 2008 | Bagatrix Algebra Solved! 2005 (105101) for...

B. 2((2-Y)/3)-Y=3

2(2-Y)-Y=9

4-2Y-Y=9

-3Y=9-4

-3Y=5

-Y=5/3

Y=-1.67

A. 3X+(-1.67)=2

3X-1.67=2

3X=2+1.67

3X=3.67

X=3.67/3

X=1.22

2(2-Y)-Y=9

4-2Y-Y=9

-3Y=9-4

-3Y=5

-Y=5/3

Y=-1.67

A. 3X+(-1.67)=2

3X-1.67=2

3X=2+1.67

3X=3.67

X=3.67/3

X=1.22

Nov 05, 2007 | SoftMath Algebrator - Algebra Homework...

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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