Question about Super Tutor Trigonometry (ESDTRIG) for PC

Simple 0.5(cos15 + (squer of 3).sin 15) =0.5(cos15+(3x3).Sin15) =0.5(0.9659+9x0.2588) =0.5(0.9659+2.3292) =0.5x3.2951 =1.64755 Zulfikar Ali ali_zulfikar@yahoo.com 989980221

Posted on Mar 15, 2009

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Posted on Jan 02, 2017

Could you give us the original question to see how you got 54.4? As you say, sine values can only be numbers between 0 and 1, and 0 and 1.

Good luck,

Paul

Good luck,

Paul

Oct 08, 2015 | Office Equipment & Supplies

Press SIN 4 3 2ND [ANGLE] 1 3 0 2ND [ANGLE] 2 ENTER

2ND [ANGLE] 1 gives you the degrees symbol, 2ND [ANGLE] 2 gives you the minutes symbol. If you need seconds, use ALPHA ["] (on the + key).

Note that this usually won't give you an EXACT value, but only a ten-digit approximation.

2ND [ANGLE] 1 gives you the degrees symbol, 2ND [ANGLE] 2 gives you the minutes symbol. If you need seconds, use ALPHA ["] (on the + key).

Note that this usually won't give you an EXACT value, but only a ten-digit approximation.

Dec 05, 2012 | Texas Instruments TI-84 Plus Calculator

If necessary, press SHIFT MODE 3 to switch the calculator to degrees mode. Then press

SIN 3 0 *** 4 5 *** ) =

*** is the DMS key, located just above the ENG key.

SIN 3 0 *** 4 5 *** ) =

*** is the DMS key, located just above the ENG key.

Jul 02, 2011 | Casio FX-115ES Scientific Calculator

You demand is to say the list unreasonanble. What you are trying to do is to find all the values of x that make sin(x^3-x) larger than or equal to 0. There is an infinite number of them: remember that the sine function is periodic. The algorithm of the solve( looks for the values of x where the expression inside the command nears zero.

What you need is a program for the TI that solves inequalities. You may want to go to the ticalc.org web site to look for such a program.

To show you that even when you are looking for the zeros you have an infinite number of them.

What you need is a program for the TI that solves inequalities. You may want to go to the ticalc.org web site to look for such a program.

To show you that even when you are looking for the zeros you have an infinite number of them.

Apr 27, 2011 | Texas Instruments TI-89 Calculator

The key is called SHIFT on Casio calculators. To get the arcsine of an angle you press [SHIFT][SIN], then enter the angle measure in the appropriate unit (degree in your case) and press ENTER. Your result should be 15.01073397 or 15, to nearest degree.

Sep 05, 2010 | Casio FX-115ES Scientific Calculator

Sin 0 = 0

Sin 90 = 1

Sin 180 = 0

Sin 270 = -1

Sin 360 = Sin 0 = 0

Is there an angle greater than 360???

Is there any greater value of Sine than 1 ???

Sin 90 = 1

Sin 180 = 0

Sin 270 = -1

Sin 360 = Sin 0 = 0

Is there an angle greater than 360???

Is there any greater value of Sine than 1 ???

Aug 11, 2010 | Pyramid Calculus WIZ 2.0 (cp11395) for PC,...

Use the rule for differentiating products of functions: ()' signifies derivative

(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'

But

(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form

sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]

then calculated the derivative of

29/2*[cos(X)-cos(3X)]

which is

29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent

29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'

But

- (29)'=0 derivative of a constant is zero
- (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
- (sin(X))'=cos(X)

(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form

sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]

then calculated the derivative of

29/2*[cos(X)-cos(3X)]

which is

29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent

29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

Jun 21, 2010 | Vivendi Excel@ Mathematics Study Skills...

Hii..this can be done as follow

cos^2 x = 1 - sin^2 x--------(1)

2cos^2 x=1+ sin x

2cos^2 x - sin x -1=0

Substituting formula (1)

2(1 - sin^2 x) - sin x - 1 = 0

2sin^2 x + sin x - 1 = 0

Factor this

(2 sin x - 1)(sin x +1) = 0

2 sin x - 1 = 0 or sin x +1 = 0

sin x = 1, and sin x = -1

cos^2 x = 1 - sin^2 x--------(1)

2cos^2 x=1+ sin x

2cos^2 x - sin x -1=0

Substituting formula (1)

2(1 - sin^2 x) - sin x - 1 = 0

2sin^2 x + sin x - 1 = 0

Factor this

(2 sin x - 1)(sin x +1) = 0

2 sin x - 1 = 0 or sin x +1 = 0

sin x = 1, and sin x = -1

Apr 26, 2010 | SoftMath Algebrator - Algebra Homework...

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Then you won't have the problem that you have.

Then you won't have the problem that you have.

Aug 23, 2009 | Microsoft Computers & Internet

Hi rowanwah

The sine of an angle is only applicable is a right triangle. If you just want a number, ie, the actual value of the sine 15 degrees you can look it up on Google. Do a search for "sine and cosine functions"

If you want the mathematical description of the sine of an angle it is described as follows

In a triangle ABC, there are 3 angles angle A, angle B and angle C. There are also 3 sides, Side AB, Side AC and side BC. The sine of angle A is equal to the side opposite Angle A divided by the Hypotenuse (the longest side opposite the right angle)

The Cosine of angle A is equal to the side adjacent to Angle A divided by the hypotenuse

Hope this helps Loringh PS Please leave a rating for me Thanks

The sine of an angle is only applicable is a right triangle. If you just want a number, ie, the actual value of the sine 15 degrees you can look it up on Google. Do a search for "sine and cosine functions"

If you want the mathematical description of the sine of an angle it is described as follows

In a triangle ABC, there are 3 angles angle A, angle B and angle C. There are also 3 sides, Side AB, Side AC and side BC. The sine of angle A is equal to the side opposite Angle A divided by the Hypotenuse (the longest side opposite the right angle)

The Cosine of angle A is equal to the side adjacent to Angle A divided by the hypotenuse

Hope this helps Loringh PS Please leave a rating for me Thanks

Nov 15, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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