Question about Super Tutor Trigonometry (ESDTRIG) for PC

Ad

Simple 0.5(cos15 + (squer of 3).sin 15) =0.5(cos15+(3x3).Sin15) =0.5(0.9659+9x0.2588) =0.5(0.9659+2.3292) =0.5x3.2951 =1.64755 Zulfikar Ali ali_zulfikar@yahoo.com 989980221

Posted on Mar 15, 2009

Ad

Hi,

A 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

The service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

Good luck!

Posted on Jan 02, 2017

Ad

Could you give us the original question to see how you got 54.4? As you say, sine values can only be numbers between 0 and 1, and 0 and 1.

Good luck,

Paul

Good luck,

Paul

Oct 08, 2015 | Office Equipment & Supplies

Press SIN 4 3 2ND [ANGLE] 1 3 0 2ND [ANGLE] 2 ENTER

2ND [ANGLE] 1 gives you the degrees symbol, 2ND [ANGLE] 2 gives you the minutes symbol. If you need seconds, use ALPHA ["] (on the + key).

Note that this usually won't give you an EXACT value, but only a ten-digit approximation.

2ND [ANGLE] 1 gives you the degrees symbol, 2ND [ANGLE] 2 gives you the minutes symbol. If you need seconds, use ALPHA ["] (on the + key).

Note that this usually won't give you an EXACT value, but only a ten-digit approximation.

Dec 05, 2012 | Texas Instruments TI-84 Plus Calculator

If necessary, press SHIFT MODE 3 to switch the calculator to degrees mode. Then press

SIN 3 0 *** 4 5 *** ) =

*** is the DMS key, located just above the ENG key.

SIN 3 0 *** 4 5 *** ) =

*** is the DMS key, located just above the ENG key.

Jul 02, 2011 | Casio FX-115ES Scientific Calculator

You demand is to say the list unreasonanble. What you are trying to do is to find all the values of x that make sin(x^3-x) larger than or equal to 0. There is an infinite number of them: remember that the sine function is periodic. The algorithm of the solve( looks for the values of x where the expression inside the command nears zero.

What you need is a program for the TI that solves inequalities. You may want to go to the ticalc.org web site to look for such a program.

To show you that even when you are looking for the zeros you have an infinite number of them.

What you need is a program for the TI that solves inequalities. You may want to go to the ticalc.org web site to look for such a program.

To show you that even when you are looking for the zeros you have an infinite number of them.

Apr 27, 2011 | Texas Instruments TI-89 Calculator

The key is called SHIFT on Casio calculators. To get the arcsine of an angle you press [SHIFT][SIN], then enter the angle measure in the appropriate unit (degree in your case) and press ENTER. Your result should be 15.01073397 or 15, to nearest degree.

Sep 05, 2010 | Casio FX-115ES Scientific Calculator

Sin 0 = 0

Sin 90 = 1

Sin 180 = 0

Sin 270 = -1

Sin 360 = Sin 0 = 0

Is there an angle greater than 360???

Is there any greater value of Sine than 1 ???

Sin 90 = 1

Sin 180 = 0

Sin 270 = -1

Sin 360 = Sin 0 = 0

Is there an angle greater than 360???

Is there any greater value of Sine than 1 ???

Aug 11, 2010 | Pyramid Calculus WIZ 2.0 (cp11395) for PC,...

Use the rule for differentiating products of functions: ()' signifies derivative

(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'

But

(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form

sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]

then calculated the derivative of

29/2*[cos(X)-cos(3X)]

which is

29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent

29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'

But

- (29)'=0 derivative of a constant is zero
- (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
- (sin(X))'=cos(X)

(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form

sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]

then calculated the derivative of

29/2*[cos(X)-cos(3X)]

which is

29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent

29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

Jun 21, 2010 | Vivendi Excel@ Mathematics Study Skills...

Hii..this can be done as follow

cos^2 x = 1 - sin^2 x--------(1)

2cos^2 x=1+ sin x

2cos^2 x - sin x -1=0

Substituting formula (1)

2(1 - sin^2 x) - sin x - 1 = 0

2sin^2 x + sin x - 1 = 0

Factor this

(2 sin x - 1)(sin x +1) = 0

2 sin x - 1 = 0 or sin x +1 = 0

sin x = 1, and sin x = -1

cos^2 x = 1 - sin^2 x--------(1)

2cos^2 x=1+ sin x

2cos^2 x - sin x -1=0

Substituting formula (1)

2(1 - sin^2 x) - sin x - 1 = 0

2sin^2 x + sin x - 1 = 0

Factor this

(2 sin x - 1)(sin x +1) = 0

2 sin x - 1 = 0 or sin x +1 = 0

sin x = 1, and sin x = -1

Apr 26, 2010 | SoftMath Algebrator - Algebra Homework...

You should buy a dog that takes you on walks.

Then you won't have the problem that you have.

Then you won't have the problem that you have.

Aug 23, 2009 | Microsoft Computers & Internet

Hi rowanwah

The sine of an angle is only applicable is a right triangle. If you just want a number, ie, the actual value of the sine 15 degrees you can look it up on Google. Do a search for "sine and cosine functions"

If you want the mathematical description of the sine of an angle it is described as follows

In a triangle ABC, there are 3 angles angle A, angle B and angle C. There are also 3 sides, Side AB, Side AC and side BC. The sine of angle A is equal to the side opposite Angle A divided by the Hypotenuse (the longest side opposite the right angle)

The Cosine of angle A is equal to the side adjacent to Angle A divided by the hypotenuse

Hope this helps Loringh PS Please leave a rating for me Thanks

The sine of an angle is only applicable is a right triangle. If you just want a number, ie, the actual value of the sine 15 degrees you can look it up on Google. Do a search for "sine and cosine functions"

If you want the mathematical description of the sine of an angle it is described as follows

In a triangle ABC, there are 3 angles angle A, angle B and angle C. There are also 3 sides, Side AB, Side AC and side BC. The sine of angle A is equal to the side opposite Angle A divided by the Hypotenuse (the longest side opposite the right angle)

The Cosine of angle A is equal to the side adjacent to Angle A divided by the hypotenuse

Hope this helps Loringh PS Please leave a rating for me Thanks

Nov 15, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

95 people viewed this question

Usually answered in minutes!

×