Question about Microsoft Windows Vista Home Premium with Service Pack 1: Windows
This sounds like "homework".
A binary-search requires an "ordered" table of values.
Sort your values into the proper order.
LET TOP=1; * Point to first element in the table.
LET BOT=1000; * Point to the *LAST* item in the table.
LET BINARY = 2;
IF VALUE(MIDDLE) = KEY THEN STOP;
IF KEY < VALUE(MIDDLE)
THEN TOP = MIDDLE;
ELSE BOTTOM = MIDDLE;
IF TOP = BOTTOM THEN STOP;
Posted on Sep 10, 2009
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Posted on Jan 02, 2017
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