Question about Microsoft Computers & Internet

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Hi there.

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http://cplus.about.com/od/learnc/ss/tcsharpins_2.htm

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Posted on Mar 04, 2009

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Posted on Jan 02, 2017

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Hi, I would imagine the letters GTSD, sum it up, ie, the TD bit means Turbo Diesel. not sure.

Hope this helps, you could look for pictures of turbos on web, basically its a fan, driven by exaust gases, that turns a fan that forces more air into engine,= more speed.so its going to be between exaust manifold and air intake, I have fitted them, but cant really explain them in simplistic terms.

Hope this helps, you could look for pictures of turbos on web, basically its a fan, driven by exaust gases, that turns a fan that forces more air into engine,= more speed.so its going to be between exaust manifold and air intake, I have fitted them, but cant really explain them in simplistic terms.

Sep 20, 2014 | Toyota Avensis Cars & Trucks

iostream.h file input output header file for c++ by which we can use input/output data.

So you must reinstall the c++ to your system and after that linker error would not go on.

So you must reinstall the c++ to your system and after that linker error would not go on.

Aug 26, 2011 | Borland Turbo C++ 3.0 Full Version...

#include <iostream>

using namespace std;

int main ()

{

int num = 0, i = 1, sum = 0;

cout << "Enter a positive integer: ";

cin >> num;

while (i <= num)

{

sum += i;

i++;

}

cout << "The sum is " << sum << endl;

return 0;

}

using namespace std;

int main ()

{

int num = 0, i = 1, sum = 0;

cout << "Enter a positive integer: ";

cin >> num;

while (i <= num)

{

sum += i;

i++;

}

cout << "The sum is " << sum << endl;

return 0;

}

Oct 30, 2010 | Compaq Visual Fortran Professional Edition...

In FORTRAN:

PROGRAM MATMULT

PARAMETER (N=3)

DIMENSION X(N,N), Y(N,N), Z(N,N)

DOUBLE PRECISION SUM

READ, X

READ, Y

DO 200 J=1, N

DO 100 K=1, N

SUM = 0.0

DO 50 L=1, N

SUM = SUM + X(J,L) * Y(L,K)

50 CONTINUE

Z(J,K) = SUM

100 CONTINUE

200 CONTINUE

WRITE, Z

END

PROGRAM MATMULT

PARAMETER (N=3)

DIMENSION X(N,N), Y(N,N), Z(N,N)

DOUBLE PRECISION SUM

READ, X

READ, Y

DO 200 J=1, N

DO 100 K=1, N

SUM = 0.0

DO 50 L=1, N

SUM = SUM + X(J,L) * Y(L,K)

50 CONTINUE

Z(J,K) = SUM

100 CONTINUE

200 CONTINUE

WRITE, Z

END

Aug 04, 2010 | Computers & Internet

hi,

here is the code u looking for

#include <iostream.h>

using namespace std;

float sub (float a, float b)

{

float dif;

dif=a - b;

return dif;

}

float addition (float c, float d)

{

float sum;

sum=c+d;

return sum;

}

float divi (float e, float f)

{

float quo;

quo = e/f;

return quo;

}

float multi (float f, float g)

{

float pro;

pro=f * g;

return pro;

}

int main ()

{

float a;

float b;

float opt;

cout << "Welcome to the calculator" << endl;

cout << "There are four options " << endl;

cout << "Option 1 is subtraction, Option 2 is addition, option 3 is division, and option 4 is multiplication " << endl;

cout << "Enter your option and two digits " << endl;

cin >> opt >> a >> b;

if (opt == 1)

{

float temp= sub (a, b);

cout << "Your difference is " << temp << endl;

}

else

if (opt==2)

{

float temp2= addition (a, b);

cout << "Your sum is " << temp2 << endl;

}

else

if (opt == 3)

{

float temp3= divi (a,b);

cout << "Your quotient is " << temp3 << endl;

}

else

if (opt == 4)

{

float temp4= multi (a,b);

cout << "Your product is " << temp4 << endl;

}

else

{

cout << "That function is not supported in calculator!" << endl;

}

cout << "Thank you for using calculator" << endl;

return 0;

}

Thanks!

here is the code u looking for

#include <iostream.h>

using namespace std;

float sub (float a, float b)

{

float dif;

dif=a - b;

return dif;

}

float addition (float c, float d)

{

float sum;

sum=c+d;

return sum;

}

float divi (float e, float f)

{

float quo;

quo = e/f;

return quo;

}

float multi (float f, float g)

{

float pro;

pro=f * g;

return pro;

}

int main ()

{

float a;

float b;

float opt;

cout << "Welcome to the calculator" << endl;

cout << "There are four options " << endl;

cout << "Option 1 is subtraction, Option 2 is addition, option 3 is division, and option 4 is multiplication " << endl;

cout << "Enter your option and two digits " << endl;

cin >> opt >> a >> b;

if (opt == 1)

{

float temp= sub (a, b);

cout << "Your difference is " << temp << endl;

}

else

if (opt==2)

{

float temp2= addition (a, b);

cout << "Your sum is " << temp2 << endl;

}

else

if (opt == 3)

{

float temp3= divi (a,b);

cout << "Your quotient is " << temp3 << endl;

}

else

if (opt == 4)

{

float temp4= multi (a,b);

cout << "Your product is " << temp4 << endl;

}

else

{

cout << "That function is not supported in calculator!" << endl;

}

cout << "Thank you for using calculator" << endl;

return 0;

}

Thanks!

Mar 19, 2009 | Microsoft Computers & Internet

Q.2# Dim n, sum as Double

Dim i as Integer

n=100

sum=0

for i=1 to n

sum=sum+1/n

next i

Q.3# Dim sum as Double

sum=0

for i=1 to 99

if i%2 <> 0 then sum=sum+i end if

next i

Dim i as Integer

n=100

sum=0

for i=1 to n

sum=sum+1/n

next i

Q.3# Dim sum as Double

sum=0

for i=1 to 99

if i%2 <> 0 then sum=sum+i end if

next i

Sep 16, 2008 | Microsoft AccRepair DS2 2004 for Fr...

no jack =no sub audio signal so you would have to get some kind of summing filter. this would sum (mix) the two signals together and extract the sub audio from both channels in order to drive the powered sub woofer you have. could be expensive dont know.

Apr 24, 2008 | Audio Players & Recorders

#include<stdio.h>

float add(float,float);

float sub(float,float);

float product(float,float);

float divide(float,float);

void main()

{

float n1,n2;

char sym,choice;

printf("This Program is a program for calculator\n\n");

scanf("%f%c%f",&n1,&sym,&n2);

if(sym=='+')

printf("\n%f",add(n1,n2));

if(sym=='-')

printf("\n%f",sub(n1,n2));

if(sym=='*')

printf("\n%f",product(n1,n2));

if(sym=='/')

printf("%f",divide(n1,n2));

printf("\nDo you wish to continue[y/n]");

scanf("%s",&choice);

if(choice=='y'||choice=='Y')

main();

}

float add(float m1,float m2)

{

return(m1+m2);

}

float sub(float m1,float m2)

{

return(m1-m2);

}

float product(float m1,float m2)

{

return(m1*m2);

}

float divide(float m1,float m2)

{

return(m1/m2);

}

float add(float,float);

float sub(float,float);

float product(float,float);

float divide(float,float);

void main()

{

float n1,n2;

char sym,choice;

printf("This Program is a program for calculator\n\n");

scanf("%f%c%f",&n1,&sym,&n2);

if(sym=='+')

printf("\n%f",add(n1,n2));

if(sym=='-')

printf("\n%f",sub(n1,n2));

if(sym=='*')

printf("\n%f",product(n1,n2));

if(sym=='/')

printf("%f",divide(n1,n2));

printf("\nDo you wish to continue[y/n]");

scanf("%s",&choice);

if(choice=='y'||choice=='Y')

main();

}

float add(float m1,float m2)

{

return(m1+m2);

}

float sub(float m1,float m2)

{

return(m1-m2);

}

float product(float m1,float m2)

{

return(m1*m2);

}

float divide(float m1,float m2)

{

return(m1/m2);

}

Feb 21, 2008 | Computers & Internet

When you are define the parameters you should initial them with zero. unless you do so the system will initial, then they will receive random number or minimum number.

Aug 23, 2007 | Borland Turbo C++ Suite 1.0...

I have my sum hooked up to my sub woofer

Apr 06, 2007 | Rockford Fosgate RFX-9200 CD Player

Jan 17, 2018 | Microsoft Computers & Internet

Dec 28, 2017 | Microsoft Computers & Internet

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