Suppose a tree 50 ft in height cast a shadow of length 60 ft. What is the angle of elevation from the end of the shadow to the top of the tree with respect to the ground?

Height =50

length = 60

angle=x

tangent(x)=50/60

tangent(x)=0.833

x=39.8 degree

Posted on Mar 01, 2009

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Posted on Jan 02, 2017

The flagpole is twenty (20) feet tall.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Feb 26, 2015 | CyberEd Trigonometry Problem Solver

11.4 meters.

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Since this looks like a homework problem, be sure to show YOUR work.

Feb 16, 2014 | Computers & Internet

e.

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If this is homework, be sure to show your work.

Sep 25, 2013 | Computers & Internet

x is the height of tree, y and z are as denoted in picture:

Please rate my answer if it was helpful :)

- cos(22°)=y/215==>y=cos(22°)*215=199.3 ft
- sin(22°)=z/215==>z=sin(22°)*215=80.5 ft
- tan(52°)=(x+z)/y==>x+z=y*tan(52°)=255.1 ft
- x=255.1-z=255.1-80.5=174.6 ft

Please rate my answer if it was helpful :)

Sep 06, 2011 | Casio fx-300ES Calculator

Depends ur height and building's height

Feb 12, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

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