1 x 60 =240

2 x 60 =240

3 x 60 =240

4 x 60 =240

5 x 60 =300

6 x 60 =360

1 to 4 is multipy by 4, greater than 4 use actual number

You need a cell to put these numbers first. Lets say A1 is your reference cell where the numbers are going to be input. B1 is the cell that you are going to see the calculation. Type the following formula in B1

=IF(A1<4,4*60,A1*60)

after doing this you can put any number in A1 and it will give you the calculation in B1 as the way you wanted.

Posted on Feb 24, 2009

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

See if this works

=IF(J28<17,0,IF(J28<=25, J27*0.12, IF(J28<=30, J27*0.15, IF(J28<=35, J27*0.2, IF(J28<=40, J27*0.25, J27*0.3)))))

You may have to adjust for your boundary conditions. For example, if the value is 25, do you want to multiply by 12% or 15%?

Good luck,

Paul

=IF(J28<17,0,IF(J28<=25, J27*0.12, IF(J28<=30, J27*0.15, IF(J28<=35, J27*0.2, IF(J28<=40, J27*0.25, J27*0.3)))))

You may have to adjust for your boundary conditions. For example, if the value is 25, do you want to multiply by 12% or 15%?

Good luck,

Paul

Nov 28, 2016 | Office Equipment & Supplies

You should multiply the top line only of the fraction.

eg 2/3 x 5 = 10/3

This will often give an improper fraction, that is, one with the numerator (top line) greater than the bottom (denominator). Its value is then greater than one.

You can then reduce this by dividing the bottom into the top line, and writing the remainder as a fraction

eg 10/3 = 3 and 1/3

.

eg 2/3 x 5 = 10/3

This will often give an improper fraction, that is, one with the numerator (top line) greater than the bottom (denominator). Its value is then greater than one.

You can then reduce this by dividing the bottom into the top line, and writing the remainder as a fraction

eg 10/3 = 3 and 1/3

.

Jan 07, 2016 | Mathsoft StudyWorks! Middle School Deluxe...

Color regist adjust failure

• The color shift amount is greater than the specified

range during main scan direction registration correction.

• The color shift amount is greater than the specified

range during sub scan direction registration correction.

• On the color shift test pattern, the maximum and minimum

deviations detected in the main and sub scan

directions go over the predetermined value.

• The color shift amount is greater than the specified

range during main scan direction registration correction.

• The color shift amount is greater than the specified

range during sub scan direction registration correction.

• On the color shift test pattern, the maximum and minimum

deviations detected in the main and sub scan

directions go over the predetermined value.

Dec 23, 2014 | Konica Minolta Bizhub C451 Copy-print-scan

Domain and range are concepts that many students have trouble with, so you are not alone!

Domain is the x values of the relation.

Range is the y values of the relation.

If you have trouble remembering which one is which , like I do, D comes before R, just like x comes before y;)

To determine if a relation is a function, there are several tests that you can use. For every x value, there can be one and only one y value. If there is more than one y value for any x value, it is not a function.

Another test is the vertical line test. If a vertical line only goes through one point on the line, it is a function. If it goes through two points on the line, it is not a function.

As an example, let's look at y = (x-3)^2 + 6.

This parabola is in the form, y=a(x-h)^2 + k, where a indicates a stretch or compression, and whether the parabola opens up or down. If a is positive, it opens up, and the y value of the vertex represents a minimum. If a is negative, it opens down, and the y value of the vertex is a maximum. The values h and k are the x and y values of the vertex.

In this case, a is one, so the parabola opens up, with a minimum value of 6.''

Now back to the domain and range.

Since we can use any value for x in the equation, for the domain, x is an element of real numbers, sometimes written (xER).

For the range, y can only be greater than or equal to the minimum. So the range is y is an element of all real numbers, such that y is greater or equal to 6, sometimes written (yER'y>=6). Sorry I couldn't find the greater than or equal to character;)

Good luck.

Paul

Domain is the x values of the relation.

Range is the y values of the relation.

If you have trouble remembering which one is which , like I do, D comes before R, just like x comes before y;)

To determine if a relation is a function, there are several tests that you can use. For every x value, there can be one and only one y value. If there is more than one y value for any x value, it is not a function.

Another test is the vertical line test. If a vertical line only goes through one point on the line, it is a function. If it goes through two points on the line, it is not a function.

As an example, let's look at y = (x-3)^2 + 6.

This parabola is in the form, y=a(x-h)^2 + k, where a indicates a stretch or compression, and whether the parabola opens up or down. If a is positive, it opens up, and the y value of the vertex represents a minimum. If a is negative, it opens down, and the y value of the vertex is a maximum. The values h and k are the x and y values of the vertex.

In this case, a is one, so the parabola opens up, with a minimum value of 6.''

Now back to the domain and range.

Since we can use any value for x in the equation, for the domain, x is an element of real numbers, sometimes written (xER).

For the range, y can only be greater than or equal to the minimum. So the range is y is an element of all real numbers, such that y is greater or equal to 6, sometimes written (yER'y>=6). Sorry I couldn't find the greater than or equal to character;)

Good luck.

Paul

Oct 03, 2014 | Office Equipment & Supplies

You first compute the capital stock value using the par value of $10. That would be 75,000 X $10 = $750,000. The final calculation uses the $13 balance. ($23-$10). That is, again, multiplied by the 75,000 to obtain $975,000 which is paid-in-capital in excess of capital stock. Adding both calculated amounts, we get $1,725,000 the full value of the stocks.

Oct 02, 2014 | Computers & Internet

i had the same assignment..are you from STI jovannie_art?

Jun 30, 2011 | Patton & Patton Flow Charting 5 (29000U)

create a flowchart that will increase the value of the number by 5 if it is greater than 10 and display the result. otherwise multiply the value by 5 and display the result.

Jun 23, 2011 | Audio Players & Recorders

Open the preferences menu in your browser and set the desired font sizes. It is possible someone has set minimum font size to too large a value. This works in Firefox. I am not sure about IE, as I don't use that crappy program unless i am forced to.

It is usually best to set minimum font sizes and allow the site to set the font to any value greater than the set value. Make this value the size you can read comfortably. Warning, anything smaller than 8 points is hard to read,

It is usually best to set minimum font sizes and allow the site to set the font to any value greater than the set value. Make this value the size you can read comfortably. Warning, anything smaller than 8 points is hard to read,

Feb 27, 2009 | Packard Bell Computers & Internet

I you have a row with 6 values you can get the minimum number from that area. Example:

A1: 6

A2: 8

A3: 3

A4: 9

A5: 2

A6: 7

in B2 we want to pick the smallest value in that group and multiply it with 60. This is what you type in B2

=min(A1:A6)*60

Yeah :)

that's all.... Good Luck :)

A1: 6

A2: 8

A3: 3

A4: 9

A5: 2

A6: 7

in B2 we want to pick the smallest value in that group and multiply it with 60. This is what you type in B2

=min(A1:A6)*60

Yeah :)

that's all.... Good Luck :)

Feb 24, 2009 | Microsoft Excel for PC

Try this:

=IF((E2<38),B2*14.3, IF((E2<44),B2*15.05, IF((E2<50),B2*15.8,0)))

Note that <38 is the same as <=37. Also, you can replace the 0 at the end with empty quotes "" for a blank cell.

=IF((E2<38),B2*14.3, IF((E2<44),B2*15.05, IF((E2<50),B2*15.8,0)))

Note that <38 is the same as <=37. Also, you can replace the 0 at the end with empty quotes "" for a blank cell.

Dec 03, 2007 | Computers & Internet

Jan 28, 2016 | Microsoft Excel for PC

148 people viewed this question

Usually answered in minutes!

×