Question about Computers & Internet

4 Answers

Cannot log in - Computers & Internet

Posted by on

  • john_macbeth Feb 14, 2009

    maxell memory stick will not work. It will not allow me to log in.

  • john_macbeth Feb 26, 2009

    memory stick and driver are not working together

×

4 Answers

  • Level 3:

    An expert who has achieved level 3 by getting 1000 points

    Superstar:

    An expert that got 20 achievements.

    All-Star:

    An expert that got 10 achievements.

    MVP:

    An expert that got 5 achievements.

  • Master
  • 6,487 Answers

Can you please explain your problem further so we can help you better, because your concern is not that clear....

Posted on Feb 14, 2009

  • Level 3:

    An expert who has achieved level 3 by getting 1000 points

    Superstar:

    An expert that got 20 achievements.

    All-Star:

    An expert that got 10 achievements.

    MVP:

    An expert that got 5 achievements.

  • Master
  • 10,594 Answers

Use another memory stick instead of Mexell.

Posted on Feb 14, 2009

  • Level 3:

    An expert who has achieved level 3 by getting 1000 points

    All-Star:

    An expert that got 10 achievements.

    MVP:

    An expert that got 5 achievements.

    Vice President:

    An expert whose answer got voted for 100 times.

  • Master
  • 679 Answers

Please explain some more.
thanks

Posted on Feb 13, 2009

  • Level 3:

    An expert who has achieved level 3 by getting 1000 points

    Superstar:

    An expert that got 20 achievements.

    All-Star:

    An expert that got 10 achievements.

    MVP:

    An expert that got 5 achievements.

  • Master
  • 13,433 Answers

Hello

can you clarify your problem a little?

Posted on Feb 13, 2009

  • Ekse Feb 14, 2009

    Can you tell us in detail what you are attempting to do, the memory stick doesn't allow you to login? are you not able to open the memory stick or to login to computer? Please explain.

×

1 Suggested Answer

6ya6ya
  • 2 Answers

SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
click here to download the app (for users in the US for now) and get all the help you need.
goodluck!

Posted on Jan 02, 2017

Add Your Answer

Uploading: 0%

my-video-file.mp4

Complete. Click "Add" to insert your video. Add

×

Loading...
Loading...

Related Questions:

Tip

The Log function!!


I calculators you can't change or set the base of 'log' is default 10 so you need to know these:

log x (base y) = log x / log y


when log x it's automatic log x (base 10) here some examples:

log 8 (base 2) = log 8 / log 2
log 27 (base 3) = log 27 / log 3


and the base it's default 10 again, and that is how you need to use it in calculators(no bases), and here the explanation to this:

log x (base y) = log x (base 10) / log y (base 10) = (log x / log 10) / (log y / log 10) = (log x / log 10) * (log 10 / log y) = log x / log y


here so other stuff about 'log' :

log (x*y) = log x + log y
log (x/y) = log x - log y


Hope it's helped

on Jul 07, 2009 | Casio fx-300ES Calculator

1 Answer

2log(base4)x + log(base4)3=log(base4)x-log(base4)2


Hi,
It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.
Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

2*log(4,x) -log(4,x) +log(4,3) = log(4,x)-log(4,x) -log(4,2)

which is equivalent to log(4,x) +log(4,3) = -log(4,2)

Gather the constant terms on the right, and use log(a) +log(b)=log(a*b)

log(4,x) = -log(4,2) -log(4,3) = - { log(4,2)+log(4,3)} = -log(4,2*3)

You get log(4,x)= -log(4,6).

Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

Use the rule log(a) +log(b) = log(a*b) valid in any base, to obtain
log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

There are a few other shortcuts to get the solution but I preferred to take a pedestrian, step by step, approach.

Hope it helps.


Nov 25, 2009 | Casio FX-300MS Calculator

2 Answers

I need help with a change of base formula problem.


It's simple here some logs:

log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
you just need to know that the default base of log in calculators is 10, so log x mean
log x base 10 = log x / log 10,
so write log x / log y for log x base y example:
log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

2 Answers

How do you input a logarithm base into the ti83 plus?


You can't it's default 10 so learn this logs:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
so just divide the logs
hope it helps

Jun 28, 2009 | Texas Instruments TI-83 Plus Calculator

1 Answer

How to calculate


It's very simple: the calculators have a default base 10 so that log x it's log x base 10 so here is some logs:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
Hope it's helped

Apr 09, 2009 | Sharp EL-520WBBK Calculator

1 Answer

To solve the problem using log


Look the calculators has a default base 10 and you can't change it but you may learn this:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
so instead input log 8 base 2 you need to input log 8 / log 2
your example answer is about 0.919... if i get right what did you write.
Glad to help :)

Feb 21, 2009 | HP 33s Calculator

1 Answer

Find log(1-.2)


I don't get it but here some help with logs:
log x base y = log x / log y (when log x is default base 10 in calculators) and
log (x*y) = log x + log y
log (x/y) = log x - log y
the bases is default 10
hope it's helped

Feb 05, 2009 | Casio FX-300MS Calculator

1 Answer

Logarithmic functions


All calculators it's the same:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2
Hope you understand :)

Dec 16, 2008 | Casio FX-7400G Plus Calculator

1 Answer

Using logs


Here something that would help you:

log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.
and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

Not finding what you are looking for?
Computers & Internet Logo

Related Topics:

16 people viewed this question

Ask a Question

Usually answered in minutes!

Top Computers & Internet Experts

Les Dickinson
Les Dickinson

Level 3 Expert

18384 Answers

kakima

Level 3 Expert

102366 Answers

David Payne
David Payne

Level 3 Expert

14161 Answers

Are you a Computer and Internet Expert? Answer questions, earn points and help others

Answer questions

Manuals & User Guides

Loading...