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Bridge parabola The cable of the horizontal suspension bridge are supported by two towers 150 ft. apart and 50 ft high. If the cable is 5 ft. above the floor of the bridge at the center, what is the height of the cable 15 ft. from the end of the bridge? Ans. y= 33.8 ft.

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bridge parabola - 5bb1218.jpg

Height is 41 feet :)

Posted on Mar 02, 2009

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Weight at sea level vs. weight at 7500 ft


Here is how I would solve the problem starting from the expression for the gravitational acceleration as a function of the radius. You might not like the fact that I use SI units, but I will show you how to adapt my calculations to suit your needs.
The ratio of the acceleration at altitude h to the acceleration at sea level is a pure number (no dimensions). Just express the Earth radius and the altitude in the same units and your result will be correct.
To get the weight you can write
w(h)/w(at sea level)=g(h)/g, or
w(h)=150 lb* g(h)/g and your result will be in pounds.
If the text of the image is too small, press CTRL + to increase the size. You can also press CTRL- to decrease it.

9746e454-18fd-4842-ba96-25a3cccb6417.png

Dec 21, 2013 | Educational & Reference Software

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How to write an electricity bill in c program(9'th class)


#include <iostream.h>
#include <conio.h>
int main()
{
clrscr();
long int units,charge=0;
float total;
const int rent=25;
cout << "Enter the number of units used : ";
cin>>units;
if(units>200)
charge=(units-200)*20+150*40+50*60;
else if(units>50)
charge=(units-50)*40+50*60;
else
charge=units*60;
total=0.01*charge+rent;
cout << "You have used " << units << " units." << endl;
cout << "Your total telephone bill is $" << total;
getch();
return 0;


Please accept the solution. Thanks, Lucy
}
This program takes in the number of units used ('units') as a screen input from the user.
It then calculates the total telephone bill for the customer on the following basis :
A compulsory fee of $25, plus
60 cents per unit for the first 50 units,
40 cents per unit for the next 150 units,
20 cents per unit for anything above 200 units.
It then outputs the bill using the 'cout' command.

Jan 12, 2011 | Microsoft Educational & Reference Software

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What causes some parabolas to have no x-intercepts?


If the parabola has its concavity turned downward and it maximum value is lower than 0 then the value of the functions are always negative (never reach 0).
Similarly, if the parabola has it concavity turned upward, and its minimum value is positive, then all the values of the functions are positive (never reach zero). Thus if y is never equal to zero the function has no x intercepts.
The concavity is called by some people the mouth.

Aug 20, 2010 | SoftMath Algebrator - Algebra Homework...

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In algebra formula,,,,carpeting cost $20.00 sq. yd you carpet a room that has a width of 15 ft, for $ 800.00 ,,what is the lenght of the room


Here is the Solution:

1. Convert 15 ft into yards. 1 yard = 3 feet
=> 15 ft = 5 yd

2. Find the area of the given room. The cost for given room is given, and cost for carpeting 1 sq. yd is given. So,
800/20 = 40 {i.e. 40 sq. yd (area of the given room)}

3. Now, Length * Width = Area
=> x * 5 = 40 [Taking Length = x yd]
=> x = 40/5
=> x = 8 yd
=> x = 8 * 3 ft
=> x = 24 ft

So, Length of the given room is 24 ft (8yd).

I hope this solved your problem (in time).

Sep 10, 2009 | SoftMath Algebrator - Algebra Homework...

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Angle of alevation


height =50
length = 60
angle=x

tangent(x)=50/60
tangent(x)=0.833
x=39.8 degree

Mar 01, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

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Determining the equation of the parabola


V (2,0) and Focus (2,2)
since the focus is 2 units above the vertex, the parabola opens upward

vertex (h,k)
a is the focal length (distance between the vertex and the focus)
a = 2
(2 units above the vertex)

(x-h)^2 = 4a (y-k)
(x-2)^2 = 4(2) (y-0)
x^2 - 4x + 4 = 8 (y)
x^2 - 4x + 4 = 8y
x^2 - 4x - 8y + 4 = 0

**Answer: "(x-2)^2 = 8 (y)" or in expanded form "x^2 - 4x - 8y +4"

Nov 18, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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Problems about areas


Let x = the width of the women's court. Then 2x is the length of the women's court.
the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4
The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

Oct 03, 2008 | Educational & Reference Software

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