Question about Super Tutor Trigonometry (ESDTRIG) for PC

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Posted on Jan 02, 2017

I have a friend who needs a wheelchair at airports when she flies. She simply books them in advance with the airport and mostly they are waiting for her, though sometimes she has to wait on the plane until a staff member is free.

Aug 15, 2016 | Health & Beauty

the pilots name is your name as you are flying the plane

haven't you got any better questions to ask this page

haven't you got any better questions to ask this page

Sep 15, 2015 | Toys

There is no such thing as still air in nature.

Nov 12, 2014 | Office Equipment & Supplies

no airport where plane is leaving, no name of flight company

go to this website and check http://www.flightstats.com/go/Home/home.do

go to this website and check http://www.flightstats.com/go/Home/home.do

Oct 30, 2013 | Hardware & Accessories

Draw the airport. (X marks the spot) Draw the distances from the airport (to scale) to indicate the position of the Plane. Use a protractor to work out the correct angle.

To Calculate:

a=48 b=49 Angle= Tan-1(a/b)

To Calculate:

a=48 b=49 Angle= Tan-1(a/b)

Sep 25, 2013 | Cars & Trucks

v will represent plane's airspeed.

We can divide pilot's trip in 2 parts:

1.5-t=200/(v-30)

We also know that t=200/v so we substitute that into equation:

1.5-200/v=200/(v-30)

To solve this equation we multiply it with v*(v-30)=v^2-30v first. We get:

1.5(v^2-30v)-200(v-30)=200v

Now we get rid of brackets:

1.5v^2-45v-200v+600-200v=0

or

1.5v^2-445v+600=0

This is quadratic equation, so we get 2 solutions (sqrt= square root):

We can divide pilot's trip in 2 parts:

- first 200km, when he is flying with speed v. The time it takes him to fly this part of trip is t=200/v
- last 200km, when he is flying with speed v-30. The time it takes him to fly this part is 200/(v-30)

1.5-t=200/(v-30)

We also know that t=200/v so we substitute that into equation:

1.5-200/v=200/(v-30)

To solve this equation we multiply it with v*(v-30)=v^2-30v first. We get:

1.5(v^2-30v)-200(v-30)=200v

Now we get rid of brackets:

1.5v^2-45v-200v+600-200v=0

or

1.5v^2-445v+600=0

This is quadratic equation, so we get 2 solutions (sqrt= square root):

- v=(445+sqrt(445^2-4*1.5*600))/(2*1.5)=295.3 km/h
- v=(445-sqrt(445^2-4*1.5*600))/(2*1.5)=1.4 km/h

Sep 08, 2011 | Casio ClassPad 300 Calculator

Yes you can there is a small red plane in the airport or there is a seaplane at the small dock up behind the old bikers bar

May 05, 2011 | Sony Video Game Consoles & Games

When its receives a signal from a satellite it receives also information about satellite positions in the coming days. When you boarded the plane you must have turned off the GPS, so it could not keep track of your position. You land a long distance away and turn GPS on. It starts to search for the satellites according to the information stored in it that pertains to their positions over Dallas. It is unable to lock on the satellites. And then it was able to receive GPS signals from other satellites and all fell into place.

Yes it will happen again if you travel long distances in a short period of time. If you cannot keep it turned on during the trip, you should try to update satellite positions through Internet after you reset the time zone.

You should also be patient, and give it time to find its bearings.

Yes it will happen again if you travel long distances in a short period of time. If you cannot keep it turned on during the trip, you should try to update satellite positions through Internet after you reset the time zone.

You should also be patient, and give it time to find its bearings.

Jan 21, 2010 | Fine Digital FineDrive 400 GPS Receiver

a2+b2=c2

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

Oct 08, 2009 | SoftMath Algebrator - Algebra Homework...

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Dec 19, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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