Question about Super Tutor Trigonometry (ESDTRIG) for PC

const feet_per_mile = 5280

distance = 8.5

print "the distance is "+distance "+miles or+" distance*feet_per_mile+" feet."

distance = 8.5

print "the distance is "+distance "+miles or+" distance*feet_per_mile+" feet."

Jul 14, 2014 | Educational & Reference Software

Let x be the distance travelled in miles, and y the fare. The equation that models the situation is

y=1.25+ 1.5x

The fare for the crosstown ride is y=$11.75. To find the number of miles, substitute 11.75 for y in the equation and solve for x

1.5x+1.25=11.75

1.5x= 11.75-1.25=10.5

x=10.5/1.5=7

The ride was 7 mile long.

y=1.25+ 1.5x

The fare for the crosstown ride is y=$11.75. To find the number of miles, substitute 11.75 for y in the equation and solve for x

1.5x+1.25=11.75

1.5x= 11.75-1.25=10.5

x=10.5/1.5=7

The ride was 7 mile long.

Jul 06, 2012 | MathRescue Word Problems Of Algebra Lite

Taking 93000000 Miles as Distance between earth and sun, you want to know how much time it takes for the light to touch Earth's atmosphere

93000000 / 186000 = 500sec

500 secs is 8 min 30sec Approx

so it takes 8 mins and approx 30 secs for light to reach from sun to earth

93000000 / 186000 = 500sec

500 secs is 8 min 30sec Approx

so it takes 8 mins and approx 30 secs for light to reach from sun to earth

Jun 26, 2010 | Dk Multimedia I Love Math - 2nd (2071074)...

The stopping distance is proportional to square of speed.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

Jun 12, 2010 | Bagatrix College Algebra Solved Full...

obtuse angle is the angle between 17.411 and 26.40

and area can be found out by root of (s(s-a)(s-b)(s-c))

where s=(a+b+c)/2

and area can be found out by root of (s(s-a)(s-b)(s-c))

where s=(a+b+c)/2

Mar 08, 2010 | Super Tutor Trigonometry (ESDTRIG) for PC

HI JH,

You may have omitted a direction from the initial distance.

In it's current wording, the boat is 23km west of its starting point.

You may have omitted a direction from the initial distance.

In it's current wording, the boat is 23km west of its starting point.

Nov 11, 2009 | The Learning Company Achieve! Math &...

a2+b2=c2

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

Oct 08, 2009 | SoftMath Algebrator - Algebra Homework...

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Dec 19, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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