Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

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Posted on Jan 02, 2017

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To solve a system of equations, there are two algebraic ways to solve them, one is by substitution, while the other is elimination.

1) 2a + 3b + 5 = 0

2) 2a + 4b + 10 = 0

-----------------------

-b -5 = 0 (subtract 2 from 1)

+b-b-5 = b

-5 = b

Substitute into 1) to solve for a.

2a + 3(-5) + 5 = 0

2a -15 + 5 = 0

2a -10 = 0

2a -10 + 10 = 10

2a = 10

---- ----

2 2

a=5

Substitute into 2) to check if we did it correctly.

2(5) + 4(-5) + 10 = 0

10 -20 + 10 = 0

0=0

Good luck.

Paul

1) 2a + 3b + 5 = 0

2) 2a + 4b + 10 = 0

-----------------------

-b -5 = 0 (subtract 2 from 1)

+b-b-5 = b

-5 = b

Substitute into 1) to solve for a.

2a + 3(-5) + 5 = 0

2a -15 + 5 = 0

2a -10 = 0

2a -10 + 10 = 10

2a = 10

---- ----

2 2

a=5

Substitute into 2) to check if we did it correctly.

2(5) + 4(-5) + 10 = 0

10 -20 + 10 = 0

0=0

Good luck.

Paul

Feb 10, 2015 | Office Equipment & Supplies

3/a + 1/2 -> ((3*2) + (1*a)) / (a*2) -> (6 + a)/2a

so

(6 + a)/2a = 11/5a -> (6 + a)*5a/2a = 11 -> 6 + a = 11*2/5

so

a = 22/5 - 6 = 4.4 - 6 = -1.6

so

(6 + a)/2a = 11/5a -> (6 + a)*5a/2a = 11 -> 6 + a = 11*2/5

so

a = 22/5 - 6 = 4.4 - 6 = -1.6

Sep 30, 2014 | SoftMath Algebrator - Algebra Homework...

Google translated the heading of you question as **Referenc(es)**ing** algebraic variables.**

Some Scientific calculators have a few memory locations called a, b, c, d, M, x and y. M is the continuous memory while the others are variables where you can store values in view of some future calculations. These are usually accessed with** STO> key + Letter **name to store the values and **RCL + letter name** to recall the values to the command line. The values are fixed to 0 by default or to the last values stored in the named memory locations. **However the calculators do not handle algebra, unless they have a COMPUTER ALGEBRA SYSTEM or CAS.** Only some graphing calculators have that capability.

Some Scientific calculators have a few memory locations called a, b, c, d, M, x and y. M is the continuous memory while the others are variables where you can store values in view of some future calculations. These are usually accessed with

Oct 07, 2013 | Aurora Electronics SC150X Scientific...

Helping in choosing the right category to post a question. As in X is the unknown category.

Mar 13, 2013 | HP Computers & Internet

If I've read your question correctly, you need to subtract: a2 +2a -7

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Insurance** in order to protect you're restaurant and the assets.

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Sep 01, 2012 | Thomson The Learning Equation Elementary...

This calculator cannot manipulate algebraic expressions. You can enter an expression and generate a table of values. You can enter an equation in one unknown and solve it. But you cannot do algebra.

You would need a calculator that has a Computer Algebra System (Algebra FX 2.0, or ClassPad 300/330). Sorry.

You would need a calculator that has a Computer Algebra System (Algebra FX 2.0, or ClassPad 300/330). Sorry.

May 10, 2012 | Casio FX-115ES Scientific Calculator

I believe that the algebraic expression should be written as:

(a + 2b)(a^2 - 2ab - 4b^2)

which can be rewritten as:

(a + 2b)^2 * (a - 2b)

The simplified form of this expression is:

(a^3 - 2a^2b - 4ab^2 + 2a^2b - 4ab^2 - 8b^3)

which can then be further simplified as:

(a^3 - 8b^3)

(a + 2b)(a^2 - 2ab - 4b^2)

which can be rewritten as:

(a + 2b)^2 * (a - 2b)

The simplified form of this expression is:

(a^3 - 2a^2b - 4ab^2 + 2a^2b - 4ab^2 - 8b^3)

which can then be further simplified as:

(a^3 - 8b^3)

Aug 24, 2011 | Bagatrix Algebra Solved! 2005 (105101) for...

Here, We deal with Some Special Products in Polynomials.

Certain products of Polynomials occur more often

in Algebra. They are to be considered specially.

These are to be remembered as Formulas in Algebra.

Remembering these formulas in Algebra is as important

as remembering multiplication tables in Arithmetic.

We give a list of these Formulas and Apply

them to solve a Number of problems.

We give Links to other Formulas in Algebra.

Here is the list of Formulas in

Polynomials which are very useful in Algebra.

Formulas in Polynomials :

** Algebra Formula 1 in Polynomials: ** * Square of Sum of Two Terms: *

** (a + b)2 = a2 + 2ab + b2 **

** (a - b)2 = a2 - 2ab + b2 **

** (a + b)(a - b) = a2 - b2 **

** (a + b)(a2 - ab + b2) = a3 + b3 **

** (a - b)3 = a3 - 3a2b + 3ab2 - b3 = a3 - 3ab(a - b) - b3 **

(First term + Second term)2

= (First term)2 + 2(First term)(Second term) + (Second term)2

Jul 02, 2011 | Computers & Internet

http://www.revisionworld.co.uk/gcse-revision/maths/number-and-algebra/algebra/algebraic-fractions

this link shows the formula and how to solve algebraic fractions. . .

thanks and have a nice day. . . .

this link shows the formula and how to solve algebraic fractions. . .

thanks and have a nice day. . . .

May 10, 2011 | Office Equipment & Supplies

Hello

**Rectangular Prism/Cuboid Definition:**

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

**Rectangular Prism/Cuboid Formula**:

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

Jan 15, 2011 | MathRescue Word Problems Of Algebra Lite

83 people viewed this question

Usually answered in minutes!

what about it? It's not really a problem... there is no = and no indication of which variable you are solving for.

in A-(B-2A)

You can simplify to 4A - B

But it cannot be SOLVED.

×