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FM TANSMITTERS IS NOT WORKING PROPERLY

WHILE TRAVELLING IN TRAIN AND BUSES INSIDE THE CITY ITSELF IT NOT RECIVING PROPERLY , PLZ HELP ME HOW TO SOLVE THIS PROBLEM

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Hey basically it should work even if u are in a bus or train.But the only thing it get troubles is when u are around a Big mountains/hills etc.observe it when u travel next time.
I guess so.

Posted on Jan 31, 2009

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Posted on Jan 02, 2017

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What is the price of bus ticket from cape town to humansdorp


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One train leaves a station heading west, while another leaves two hours later travelling 15km/h faster heading east. After 6 hours the trains are 580 km apart. How fast is each train travelling?


To start out, you need to figure out what the equation for the problem is. You know a few things that should help you along the way:
  • The trains are 580 km apart
  • one train traveled for 6 hours
  • the other train traveled for 4 hours
  • one train is going 15km/h faster than the other.
Knowing these facts you can write the equation 6x+4x+60=580.

The 6 at the front is how many hours the first train traveled. the 4 is the hours the second train traveled. the 60 is (4*15) which is how much faster the second train was going. the 580 is the total distance between them.

Solve for x

10x=520
x=52

So the westbound train was going 52 km/h and the east bound train was going 67km/h.

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1 Answer

Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a station at 9:25am If train...


The first thing to figure out is the amount of time between the trains is 12 minutes. That would mean for train B to pass the station at 9:37 it would have to travel 22 miles in 12 minutes. Because, traveling at 110 miles/hour in 12 minutes the train would have travel 22 miles. Shown below shows the interpolation to come up with 22 miles.

oneplusgh_0.jpg
Train A had to traveled 12 minutes so, it would have been 20 miles ahead of the station. Screened below shows the interpolation to equal 20 miles.

oneplusgh_1.jpg
Though this calculation of 20 miles isn't necessary for the parametric solution that is being shown. It was very helpful in my solution in successive approximation. This parametric solution's starting point is at 9:37, not 20 miles ahead.

Using successive approximation, when train A traveled 200 miles in 2 hours, and train B was only 2 miles behind train A. At that point the time varibles needed to be broke down to minutes and seconds which gave me a real accurrate answer. Both trains were side by side in 2 hours and 12 minutes, and had traveled 220 miles from the station. You wouldn't believe how far the significant bits needed to be carried out to get such an accurate number. That's what gave me the idea to substitute, and use a parametric solution. In this solution the t (aka. time) is going to be substituted for the y axis. Next, I broke miles/hour down to mile/minute because, I knew the answer was in minutes: 2 hours and 12 minutes.

110/60=1.833333 so, -20+1.833333 t and 100/60=1.6666667 so, 1.6666667 t

Now load the equation:

oneplusgh_2.jpg
Now let's look at the solution from the graph. Each line represents a train.

oneplusgh_3.jpg
Notice how the two lines are converging. Where the two lines meet is the exact point when the two trains are side by side.

oneplusgh_4.jpg
Substituting t (aka. time) for the y axis show that at the point when the trains were side by side equals 132 minutes. Or 2 hours and 12 minutes. The distance traveled x axis=220 mile from the station.

To a point successive approximation would have been messy, and hard to follow. Somethings can only be solved by using graphs, or better solved by using graphs.

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Where do I go to register my garmin and get the traffic set up


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I bought a '96 Mustang with an Alpine CHM 5620 CD player already installed. The unit appears in great shape and looks as if it were installed by a pro. It seems to load up the CD cartridge and change CDs...


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i hope this helps
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