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How do you get out of under ground train station

Trapped in under ground and unable to find way out..

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Keep pushing forward, your comrades will show you the way ;)

Posted on Jan 24, 2013

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Posted on Jan 02, 2017

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Im in process of a statutory declaration regarding a train fine


http://www.ptua.org.au/publications/fines/

Write a letter back explaining that you never got a fine notification three years ago and due to the length of time you require the exact details of the offence.
You will have a difficult time fighting this if you can't remember the details and did not keep written records of it.

Recommend that you try contacting a legal aid service in your country as a starting point or a public transport users association in your country for advice on what to do.

I want to acknowledge that I have some idea on how annoyed you must feel I am still annoyed from being unfairly entrapped by my experience in 1995


Back in 1995 the State Government decided to do cost cutting so you were allowed at the time in 1995 when your train station was unmanned to buy a ticket at the destination station,
On my particular day in 1995 I was in a hurry and the train was in the station I did not see that my train station was manned although it has only ever been manned for the one day of the year that there happened to be train inspectors on the train. So I had no excuse as the station was manned.
So I paid the fine - I regret I did not contest this fine

Oct 05, 2016 | Cars & Trucks

1 Answer

Why won't it sink to the bottom?


Air trapped in the unit. They do not float unless air is trapped. Turn upside down under water to relieve trapped air.

Jun 23, 2015 | Zodiac Baracuda G2 - In Ground Suction...

1 Answer

Lionel train problems


Check to be sure that the reverse unit is on. This may be a lever on the top of the locomotive or a slide switch under the engine. If that doesn't solve the problem, you will need to take the engine to a service center to be repaired. A list of service centers can be found at Lionel.com

Dec 20, 2013 | Crafts & Hobbies

1 Answer

. A person meets a


If the train's still going the right way, up about ((5 *60)/25) km/h. Classical relativity doesn't change it much at that person's speed, since c >> 25kmph, but that's not to say quantum relativity will continue to favor the Standard Model with the information given for meeting in your OS.

Jan 03, 2011 | Computers & Internet

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Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 110 miles per hour. Train A passes a station at 9:25am If train...


The first thing to figure out is the amount of time between the trains is 12 minutes. That would mean for train B to pass the station at 9:37 it would have to travel 22 miles in 12 minutes. Because, traveling at 110 miles/hour in 12 minutes the train would have travel 22 miles. Shown below shows the interpolation to come up with 22 miles.

oneplusgh_0.jpg
Train A had to traveled 12 minutes so, it would have been 20 miles ahead of the station. Screened below shows the interpolation to equal 20 miles.

oneplusgh_1.jpg
Though this calculation of 20 miles isn't necessary for the parametric solution that is being shown. It was very helpful in my solution in successive approximation. This parametric solution's starting point is at 9:37, not 20 miles ahead.

Using successive approximation, when train A traveled 200 miles in 2 hours, and train B was only 2 miles behind train A. At that point the time varibles needed to be broke down to minutes and seconds which gave me a real accurrate answer. Both trains were side by side in 2 hours and 12 minutes, and had traveled 220 miles from the station. You wouldn't believe how far the significant bits needed to be carried out to get such an accurate number. That's what gave me the idea to substitute, and use a parametric solution. In this solution the t (aka. time) is going to be substituted for the y axis. Next, I broke miles/hour down to mile/minute because, I knew the answer was in minutes: 2 hours and 12 minutes.

110/60=1.833333 so, -20+1.833333 t and 100/60=1.6666667 so, 1.6666667 t

Now load the equation:

oneplusgh_2.jpg
Now let's look at the solution from the graph. Each line represents a train.

oneplusgh_3.jpg
Notice how the two lines are converging. Where the two lines meet is the exact point when the two trains are side by side.

oneplusgh_4.jpg
Substituting t (aka. time) for the y axis show that at the point when the trains were side by side equals 132 minutes. Or 2 hours and 12 minutes. The distance traveled x axis=220 mile from the station.

To a point successive approximation would have been messy, and hard to follow. Somethings can only be solved by using graphs, or better solved by using graphs.

Dec 20, 2010 | Office Equipment & Supplies

2 Answers

I am unable to open some web page like irctc.co.in


hi,
Do the following steps,

Go to http://www.irctc.co.in/
Click Signup
Complete the reegistration process.
then again go to http://www.irctc.co.in/
Login with your credentials.
you will have "Plan my travels"
find Your Train and check avalibility.
then book ticket and make payment through card.

thanks it. everything should take not more than 20 minutes. have a happy journey.

thanks,
mac

Jul 02, 2009 | Intel Motherboard

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