Question about Texas Instruments TI-30X-IISTK Scientific Calculator

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Posted on Jan 02, 2017

SOURCE: Problem entering matrices - only the working out step is shown

try hitting the diamond button and then hitting answer after it shows up, it should give you a different outcome than the original. hope that helped.

Posted on Nov 12, 2008

SOURCE: My Ti-89 won't factor a quadratic equation with imaginary roots.

(a-b)3

Posted on Apr 04, 2009

SOURCE: TI-15 square root Function

Hello,

You should enter it as follows [SQRT]36 ) [ENTER/=].

If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.

Hope it helps.

Posted on Sep 07, 2009

SOURCE: how do I find the

For square roots, use the square root key just to the left of the divide key. For example, 4 square-root = will give you 2.

The calculator doesn't have any way to store equations, scientific or otherwise. If you mean scientific notation, use the EE key just above the 7 key to enter exponents. For example, to enter 1.23x10^6, press 1 . 2 3 EE 6. For negative exponents, make sure to use the +- key to the right of the decimal point instead of the - key.

Posted on Sep 22, 2010

SOURCE: were is the square root

Square root is the 2nd function of the square key, to the left of the 7 key. To compute the square root of 62, press 2nd [square-root] 6 2 ) =

Posted on Nov 15, 2010

If the quadratic equation has no roots, you cannot find the roots. The discriminate is negative, so if we attempt to use the quadratic equation, we get no roots.

For example, y=x^2 +0x + 3

a=1, b=0, c=3

(-b+/- sqrt(b^2 -4ac))/2a

Substituting in the numbers, we get

x= (-0 +/-sqrt(0^2 - 4(1)3))/2

x= (0 +/- sqrt (-12))/2

We cannot do the square root of -12. Therefore, there are no roots. This is the same as having no x-intercepts. The discriminant is b^2-4ac. In this case it is -12. Thus, there are no real roots.

However, you can still determine the maximum or minimum, the vertex, the axis of symmetry, the y-intercept and the stretch/compression. With this information you can graph the equation.

In this case, the y-intercept is 3, the vertex is at (0,3), the axis of symmetry is x=0, the minimum value of the function is 3.

Good luck.

Let me know if you have any questions.

Paul

For example, y=x^2 +0x + 3

a=1, b=0, c=3

(-b+/- sqrt(b^2 -4ac))/2a

Substituting in the numbers, we get

x= (-0 +/-sqrt(0^2 - 4(1)3))/2

x= (0 +/- sqrt (-12))/2

We cannot do the square root of -12. Therefore, there are no roots. This is the same as having no x-intercepts. The discriminant is b^2-4ac. In this case it is -12. Thus, there are no real roots.

However, you can still determine the maximum or minimum, the vertex, the axis of symmetry, the y-intercept and the stretch/compression. With this information you can graph the equation.

In this case, the y-intercept is 3, the vertex is at (0,3), the axis of symmetry is x=0, the minimum value of the function is 3.

Good luck.

Let me know if you have any questions.

Paul

Nov 04, 2015 | Casio FX991ES Scientific Calculator

You do not need a calculator for this proportion.

For a proportion a/b=c/d, the product of the extrems (a*d) is equal to the product of the means (b*c).

In your case x*x=8*8 or x^2=64.

The two solutions are x=+square root (64) or x=-square root(64).

For a less trivial equation, you can use the**solve** feature of the FX-119ES. To do so, use the ALPHA keyboard to enter your equation; once the equation is typed in, do not press the main equal sign, but the Solve key (the key is located near the top left corner of the keyboard). You will be prompted to solve for X?.

For a proportion a/b=c/d, the product of the extrems (a*d) is equal to the product of the means (b*c).

In your case x*x=8*8 or x^2=64.

The two solutions are x=+square root (64) or x=-square root(64).

For a less trivial equation, you can use the

Feb 24, 2012 | Casio FX-115ES Scientific Calculator

Hi rayalak857,

Have a nice day.

Calculator does not have a solve program, but you can use it to solve the quadratic equation with a little effort. If you know the theory skip toward the end.

Here is the example:

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps. Goodluck

Thank you for using fixya.

Have a nice day.

Calculator does not have a solve program, but you can use it to solve the quadratic equation with a little effort. If you know the theory skip toward the end.

Here is the example:

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps. Goodluck

Thank you for using fixya.

Sep 13, 2011 | Casio FX-300MS Calculator

You don't want the square root. In this example, you want the sixth root.

Press 4 5 2nd [xth-root] 6 =

The xth-root is the shifted function of the y^x key, located just above the divide key.

Press 4 5 2nd [xth-root] 6 =

The xth-root is the shifted function of the y^x key, located just above the divide key.

Jun 11, 2011 | Texas Instruments TI-30XA Calculator

Use the quadratic formula or completing the square.

Completing the square:

x^2 -13x=-36

x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2

The left side can be factored as (x-13/2)^2.

The right side is (13^2-36*4)/4=(169-144)/4=25/4

Assembling the two sides

(x-13/2)^2=25/4

Taking the square roots x-13/2=+ or - 5/2

Case 1 : x-13/2=+ 5/2.

Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.

Solving for x, you get the other root as x=(13-5)/2=8/2=4.

The roots are x1=9, and x2=4

Completing the square:

x^2 -13x=-36

x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2

The left side can be factored as (x-13/2)^2.

The right side is (13^2-36*4)/4=(169-144)/4=25/4

Assembling the two sides

(x-13/2)^2=25/4

Taking the square roots x-13/2=+ or - 5/2

Case 1 : x-13/2=+ 5/2.

Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.

Solving for x, you get the other root as x=(13-5)/2=8/2=4.

The roots are x1=9, and x2=4

Apr 20, 2011 | Casio FX-115ES Scientific Calculator

A circle is not a function and cannot be graphed in the regular y=screen. You can graph a circle in parametric mode.

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

To graph a circle in the regular y= screen, you have to graph it in 2 lines on the y= screen. I assume you've solved for y and gotten a square root equation. Remember a square root can be positive or negative. In line 1 of y= screen graph what you've been graphing and then graph the same equation in line 2 but with a negative in front of the equation. You'll get something that looks like an oval since the calculator screen is rectanglular. To make it look more circular (both parts aren't going to connect), press zoom and then select #5 (square).

Aug 01, 2009 | Texas Instruments TI-83 Plus Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and**x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3.**If disc is negative, there are no real solutions.**

To find the solutions you**replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then

and

2.

3.

To find the solutions you

Hope it helps.

Jun 26, 2009 | Sharp EL-531VB Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Callit disc.

**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and**x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3.**If disc is negative, there are no real solutions.**

To find the solutions you**replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Callit disc.

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then

and

2.

3.

To find the solutions you

Hope it helps.

May 17, 2009 | Sharp EL-531VB Calculator

Hello,

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

**disc= (b^2-4*a*c)**

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then** x1=(-b+square root of disc)/(2*a)**

and**x2= (-b-square root of disc)/(2*a)**

2.** If disc=0** , square root of disc =0 and** x1=x2=-b/(2*a)**

3.**If disc is negative, there are no real solutions.**

To find the solutions you**replace a, b, and c **by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.

Let the equation be ax^2 +bx+c=0

You compute the discriminant Call it disc.

1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.

Then

and

2.

3.

To find the solutions you

Hope it helps.

May 05, 2009 | Sharp EL-531VB Calculator

1. square of 12

2. cube root of 48 a raise to 5 y raise to 6

3. square root of 128 y raise to 5

4. 6th root of 9 y raise to 2

5. cube root of 24 y raise to 5

6. 10th root of 32 x raise to 5

7. 15th root of 64 x raise to 9

8. 4th root of 10000

9. cube root of 192 p raise to 5

10. cube root of 256 y raise to 12

2. cube root of 48 a raise to 5 y raise to 6

3. square root of 128 y raise to 5

4. 6th root of 9 y raise to 2

5. cube root of 24 y raise to 5

6. 10th root of 32 x raise to 5

7. 15th root of 64 x raise to 9

8. 4th root of 10000

9. cube root of 192 p raise to 5

10. cube root of 256 y raise to 12

Jul 04, 2008 | Texas Instruments TI-89 Calculator

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