What is the correct format for finding the x intercepter?

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Posted on Jan 02, 2017

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SOURCE: solve for x-intercept and graph:f(x)= -x^2 + 2x -

Graph the function then use the trace function to locate the point(s) where two curves intersect. In your case one of the curves is the X-AXIS.

See the screen capture to learn how to use the trace functionality.

Posted on Jul 25, 2010

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To find the x-intercept, set y equal to zero and solve for x.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

Nov 06, 2014 | Computers & Internet

You put x=0 then y=0 in turn.

The x intercept, when y=0, gives 4x^2-9 = 0 or x = 3/2 = 1.5

The y intercept, x=0, gives y = -9

The x intercept, when y=0, gives 4x^2-9 = 0 or x = 3/2 = 1.5

The y intercept, x=0, gives y = -9

Sep 20, 2013 | Computers & Internet

If you use the definition of the y-intercept you will immediatedly find it.

**y-intercept = value of y when x=0.** Set x=0 in the function y=x and determine y. The y-intercept is also known as the initial value.

Oct 31, 2012 | Office Equipment & Supplies

The

To find the y-intercept, substitute 0 for x: y= (0)(0+2)(0-3)=0

For a true function there is ONLY one y-intercept, which is the y-coordinate of the point where the curve cuts the y-axis.

This is a cubic equation and its roots are x=0, x=-2, and x=3. Remember that a product of factors is equal to 0 if any of the factors is =0.

Aug 08, 2012 | Office Equipment & Supplies

The x intercept is where your line will cross the x axis. Therefore, the value for y at this point is 0. Substitute 0 for y in this equation and solve for x.

6x + 3(0) = 27

x = 27/6

x = 4 1/2

x intercept = (4 1/2, 0)

Follow the same reasoning for the y intercept.

6(0) + 3y = 27

y = 27/3

y = 9

y intercept = (0,9)

Now plot these two points and draw your line through them.

6x + 3(0) = 27

x = 27/6

x = 4 1/2

x intercept = (4 1/2, 0)

Follow the same reasoning for the y intercept.

6(0) + 3y = 27

y = 27/3

y = 9

y intercept = (0,9)

Now plot these two points and draw your line through them.

May 18, 2012 | SoftMath Algebrator - Algebra Homework...

This line is parallel to the x-axis, so there is no x-intercept. The y-intercept is just the value y=-2.

Jan 12, 2012 | Mcgraw-Hill Glencoe Algebra 1 Florida...

x-intercept: set y=0, and find x=4

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

The intercept point on the x-axis is (4,0)

y-intercept: set x=0, and find y=4/4=1

The intercept point on the y-axis is (0,1)

Jan 12, 2012 | Mcgraw-Hill Glencoe Algebra 1 Florida...

x-intercept (or zero of the function)

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Set y=0 in the equation and solve fo x: 2x-5(0)=20 and x=20/2=10

y-intercept (initial value)

Set x= 0 in the equation and solve for y: 2(0)-5y=20 and y=20/(-5)=-4

If the equation is in the slope-intercept form y=ax+b

1. y-intercept is b

2. To get the x-intercept ( zero of the function) Set y=0=ax+b, and x=-b/a

Aug 27, 2011 | Texas Instruments TI-84 Plus Calculator

y = x -3

This is a linear problem- so the usual way to solve the graph would be to solve where x = 0 and y= 0

if you use the format y = slope (m) * x + y intercept (b)- you would set y = 0

at that point it would be 0 = x -3 x = 3 Therefore where y = 0, x = 3. In a graph, that would point to the coordinate (3,0) for the x-intercept. To find the y-intercept, you'd set x = 0 at that point, you'd have the y-intercept being (0,-3)

so if y = 1, x would be 4; if y = 2, x = 5, and so on

This is a linear problem- so the usual way to solve the graph would be to solve where x = 0 and y= 0

if you use the format y = slope (m) * x + y intercept (b)- you would set y = 0

at that point it would be 0 = x -3 x = 3 Therefore where y = 0, x = 3. In a graph, that would point to the coordinate (3,0) for the x-intercept. To find the y-intercept, you'd set x = 0 at that point, you'd have the y-intercept being (0,-3)

so if y = 1, x would be 4; if y = 2, x = 5, and so on

Jun 22, 2011 | Computers & Internet

Have you graphed the equation? Are you asking someone to solve and give you the answer or tell you how to use your software?

Jun 19, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

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