Question about Intel Dot Station (INTC300AIO) PC Desktop

2 yrs back, 'BIG APPLE' of Hyderabad was selling it here in New Delhi for Rs. 3500/- with Cel 300, 4.3GB HDD & 64MB SD RAM.

Go & buy some Dell P4 system with LGA775 pinless CPU

Posted on Mar 07, 2010

Rs.6500/-

Posted on Sep 17, 2009

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Posted on Jan 02, 2017

Knowing the small things and tips will help you buy a right cot for your baby. Here we provide some useful tips regarding how to buy the baby cots:

1. Doing a small research regarding baby cot at online will provide the best information regarding types and designs of baby cot.

2. You must look for the adjustable and portable baby cot which adjust the size according to baby grown up.

3. Select the baby cots colour which matches in the nursery room.

4. You also take a suggestion of your friends as well relatives If they purchase a baby cot.

5. Decide the space In the room where you place baby cots and buy a baby cot regarding the space of the baby room.

6. Try to buy a stylish and classy baby cot for your baby, which ensures the Australian standards

1. Doing a small research regarding baby cot at online will provide the best information regarding types and designs of baby cot.

2. You must look for the adjustable and portable baby cot which adjust the size according to baby grown up.

3. Select the baby cots colour which matches in the nursery room.

4. You also take a suggestion of your friends as well relatives If they purchase a baby cot.

5. Decide the space In the room where you place baby cots and buy a baby cot regarding the space of the baby room.

6. Try to buy a stylish and classy baby cot for your baby, which ensures the Australian standards

Jan 27, 2016 | Baby Gear

csc(x)=1/sin(x)

sec(x)=1/cos(x)

csc(x)/sec(x)=(1/sin(x))*(cos(x)=cot(x)

csc(x)*cot(x)/sec(x)=(cot(x))^2=(tan(x))^(-2)

sec(x)=1/cos(x)

csc(x)/sec(x)=(1/sin(x))*(cos(x)=cot(x)

csc(x)*cot(x)/sec(x)=(cot(x))^2=(tan(x))^(-2)

Jul 12, 2014 | Super Tutor Trigonometry (ESDTRIG) for PC

umps

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jots

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dust

duos

dump

duct

dots

dost

docs

cuts

cusp

cups

cums

cuds

coup

cots

cost

cops

comp

cods

tops

toms

tofu

sump

sumo

stud

stop

spud

spot

soup

soft

scud

puts

pout

pots

post

pods

outs

oust

opus

opts

must

muds

mots

most

mops

mods

juts

just

jump

judo

jots

fops

dust

duos

dump

duct

dots

dost

docs

cuts

cusp

cups

cums

cuds

coup

cots

cost

cops

comp

cods

Feb 06, 2014 | Games

[tan(x)]^2 or tan^2 x

Sep 16, 2013 | Super Tutor Trigonometry (ESDTRIG) for PC

Remove webcamera nice cotting ok

Sep 24, 2011 | HP Pavilion dv1000 Notebook

You can follow this link:

http://support.dell.com/support/downloads/driverslist.aspx?os=WW1&catid=5&dateid=-1&impid=-1&osl=EN&typeid=-1&formatid=-1&servicetag=&SystemID=PLX_PNT_CEL_GX270&hidos=WW1&hidlang=en&TabIndex=&scanSupported=False&scanConsent=False

and download the Interl Driver for Gigabit LOM

http://support.dell.com/support/downloads/driverslist.aspx?os=WW1&catid=5&dateid=-1&impid=-1&osl=EN&typeid=-1&formatid=-1&servicetag=&SystemID=PLX_PNT_CEL_GX270&hidos=WW1&hidlang=en&TabIndex=&scanSupported=False&scanConsent=False

and download the Interl Driver for Gigabit LOM

Dec 31, 2010 | Dell OptiPlex GX270 PC Desktop

dude dont waste money on that ****

Oct 19, 2009 | HP Compaq EVO Intel Celeron 1.7GHz / 256MB...

I shall attempt :D

1) cosec A + cot A = 3

we know that (cot A)^2 + 1 = (cosec A)^2

Hence, (cosec A)^2 - (cot A)^2 = 1

thus, (cosec A + cot A) (cosec A - cot A) = 1

3 (cosec A - cot A) = 1

(cosec A - cot A) = 1/3

(cosec A - cot A) = 1/3

(cosec A + cot A) = 3

Summing them, 2 cosec A = 3 1/3

cosec A = 6 2/3 = 5/3

sin A = 0.15

Thus, cos A = sqrt (1 - (sin A)^2) = 0.989

2) Prove that (1+tan x - sec x)(1 + cot x + cosec x) =2

expand

LHS= 1 + cot x + cosec x + tan x + 1 + tan x cosec x - sec x - sec x cot x - sec x cosec x

We can calculate that

tan x cosec x = sec x (since tan x = sin x / cos x)

sec x cot x = cosec x

so the above is

LHS = 1 + cot x + cosec x + tan x + 1 + sec x - sec x - cosec x - sec x cosec x

LHS = 2 + cot x + tan x - sec x cosec x

LHS = 2 + cos x / sin x + sin x / cos x - 1 / (sin x cos x)

LHS = 2 + [{cos x}^2 + {sin x}^2 - 1] / (sin x cos x)

LHS = 2 (proved)

1) cosec A + cot A = 3

we know that (cot A)^2 + 1 = (cosec A)^2

Hence, (cosec A)^2 - (cot A)^2 = 1

thus, (cosec A + cot A) (cosec A - cot A) = 1

3 (cosec A - cot A) = 1

(cosec A - cot A) = 1/3

(cosec A - cot A) = 1/3

(cosec A + cot A) = 3

Summing them, 2 cosec A = 3 1/3

cosec A = 6 2/3 = 5/3

sin A = 0.15

Thus, cos A = sqrt (1 - (sin A)^2) = 0.989

2) Prove that (1+tan x - sec x)(1 + cot x + cosec x) =2

expand

LHS= 1 + cot x + cosec x + tan x + 1 + tan x cosec x - sec x - sec x cot x - sec x cosec x

We can calculate that

tan x cosec x = sec x (since tan x = sin x / cos x)

sec x cot x = cosec x

so the above is

LHS = 1 + cot x + cosec x + tan x + 1 + sec x - sec x - cosec x - sec x cosec x

LHS = 2 + cot x + tan x - sec x cosec x

LHS = 2 + cos x / sin x + sin x / cos x - 1 / (sin x cos x)

LHS = 2 + [{cos x}^2 + {sin x}^2 - 1] / (sin x cos x)

LHS = 2 (proved)

May 12, 2009 | ValuSoft Bible Collection (10281) for PC

hi there yes you need to pull the middle handle right up almost halfway high as cot then flip sides out they will automatically lock then close the handle x

May 09, 2009 | Baby Gear

sec^4X- sec^2X = 1/cot^4X + 1/cot^2X

RHS

1/cot^4X + 1/cot^2X

=1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X)

=Sin^4X/Cos^4X + Sin^2X/Cos^2X

=Sin^4X/Cos^4X + Cos^2X.Sin^2X/Cos^4X

=Sin^2X/Cos^4(Sin^2X + Cos^2X)

=Sin^2X/Cos^4X

=(1-Cos^2X)/Cos^4X

=1/Cos^4X - Cos^2X/Cos^4X

=1/Cos^4X - 1/Cos^2X

=Sec^4X - Sec^2X

=LHS

RHS

1/cot^4X + 1/cot^2X

=1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X)

=Sin^4X/Cos^4X + Sin^2X/Cos^2X

=Sin^4X/Cos^4X + Cos^2X.Sin^2X/Cos^4X

=Sin^2X/Cos^4(Sin^2X + Cos^2X)

=Sin^2X/Cos^4X

=(1-Cos^2X)/Cos^4X

=1/Cos^4X - Cos^2X/Cos^4X

=1/Cos^4X - 1/Cos^2X

=Sec^4X - Sec^2X

=LHS

Feb 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

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