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Substitute 4 and -4 for x in the equations y=x+1 and 2y-2=2x. Describe the results


y = x+1
y = (4) + 1
y = 5

y = x + 1
y = (-4) + 1
y = -3

2y - 2 = 2x
2y - 2 = 2 (4)
2y - 2 = 8
2y - 2 + 2 = 8 + 2
2y = 10
2y/2 = 10/2
y = 5

2y - 2 = 2(-4)
2y - 2 = -8
2y -2 + 2 = -8 + 2
2y = -6
2y / 2 = -6 /2
y = -3

The results are the same, implying that they are the same line.

Why?

2y - 2 = 2x
2y - 2 + 2 = 2x + 2
2y = 2x + 2
divide everything by 2
y = x + 1

Good luck,

Paul

Feb 07, 2017 | The Office Equipment & Supplies

1 Answer

2^42


2^42 = 4,398,046,511,104

Nov 12, 2014 | Cooktops

1 Answer

How to converting 39.37 base 10 base 2?


The easiest to understand (and the longest) method is to subtract off the powers of 2. The highest power of 2 in 39.37 is 2^5=32,
39.37-32 = 7.37. The next lowest power of 2 is 16, which is greater than our number, as is 8..

39.37
-32 = 1 (2^5) = 32
7.37
0 = 0 (2^4) = 16
7.37
0 = 0 (2^3) = 8
7.37
-4.00 =1 (2^2) = 4
3.37
- 2.00 = 1 (2^1) = 2
1.37
-1.00 = 1 (2^0) = 1
.37
0 =0 (2^(-1)) = .5
.37
-.25 = 1 (2^(-2)) = .25
.12
0 = 0 (2^(-3)) = .125
.1200
- .0625 = 1 (2^(-4)) = .0625
.05750
-.03125 = 1 (2^(-5)) = .03125
.026250
-.015625 = 1 (2^(-6)) = .015625
.010625
-.0078125 = 1 (2^(-7)) = .078125
.0028125
0 = 0 (2^(-8)) = .00390625
.0028125
-.001953125 = 1 (2^(-9)) = .001953125
.000859375
and so forth...
Reading the coefficients of the powers of 2, one gets:
100111.010111101...

May 05, 2014 | Mathsoft Computers & Internet

1 Answer

X^2+13x+22=7


x^2+13x+15=0
Recall (x+a)^2=x^2+2ax+a^2
Write x^2+2*(13/2)x+15, and compare the terms in x. a=13/2
x^2+13x+15=x^2+2(13/2)x+(13/2)^2-(13/2)^2+15
The first three terms are the expansion of (x+13/2)^2
You expression is equivalent to
(x+13/2)^2-[(13/2)^2-15]=(x+13/2)^2-[SQRT(109)/2]^2
Use the identity for the difference of two squares a^2-b^2=(a-b)(a+b)
This gives
x^2+13x+15=(x+13/2)^2-[SQRT(109)/2]^2=
[x+13/2 -SQRT(109)/2][x+13/2+SQRT(109)/2]
The polynomial can be written as (x-a)(x-b) (Note a has nothing to do with the one used above to complete the square. You can use any name for the roots, x_1, x_2, anything.
The two roots are on the screen captures below.

50683d1f-d4c4-43e6-8a47-b41eedc7a4cf.png985b04c7-b0cb-4d5a-9695-9d47c04c1a84.png

PS. I prefer to manipulate exact expressions with radicals. If you do not like it use the decimal approximations.

Jan 18, 2014 | Texas Instruments TI-84 Plus Calculator

2 Answers

Zip code of makati city philippines


Hi,

ZIP Codes & Phone Area Code of the City of Makati..
Location ZIP Code Phone Area Code

Ayala-Paseo de Roxas

1226
2

Bangkal

1233
2

Bel-air

1209
2

Cembo

1214
2

Comembo

1217
2 Dasmarinas Village North 1221 2

Dasmarinas Village South

1222
2

Forbes Park North

1219
2

Forbes Park South

1220
2

Fort Bonifacio Naval Stn.

1202
2

Fort Bonifacio (Camp)

1201
2

Greenbelt

1228
2

Guadalupe Nuevo

1212
2 Guadalupe Viejo 1211 2 Kasilawan 1206 2 La Paz-Singkamas-Tejeros 1204 2 Legaspi Village 1229 2 Magallanes Village 1232 2 Makati Commercial Ctr. 1224 2 Makati CPO + Buendia Ave 1200 2 Olympia & Carmona 1207 2 Palanan 1235 2 Pasong Tamo & Ecology Vill 1231 2 Pembo 1218 2 Pinagkaisahan-Pitogo 1213 2 Pio del Pilar 1230 2 Poblacion 1210 2 Rembo (East) 1216 2 Rembo (West) 1215 2 Salcedo Village 1227 2 San Antonio Village 1203 2 San Isidro 1234 2 San Lorenzo Village 1223 2 Sta. Cruz 1205 2 Urdaneta Village 1225 2

Valenzuela, Santiago, Rizal
1208 2
Thanks for using FixYa.

Jun 22, 2011 | Computers & Internet

1 Answer

How do i solve the equation x2-13x+36=0


Use the quadratic formula or completing the square.
Completing the square:
x^2 -13x=-36
x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2
The left side can be factored as (x-13/2)^2.
The right side is (13^2-36*4)/4=(169-144)/4=25/4
Assembling the two sides
(x-13/2)^2=25/4
Taking the square roots x-13/2=+ or - 5/2
Case 1 : x-13/2=+ 5/2.
Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.
Solving for x, you get the other root as x=(13-5)/2=8/2=4.
The roots are x1=9, and x2=4

Apr 20, 2011 | Casio FX-115ES Scientific Calculator

1 Answer

I have problem in how to call the matrix using fuction


I don think u are in the right way to program the Matrix in C language, i found a lot of syntax error in your code, but nevermind i had correct it for u. Maybe still need a little correction for your own. Following code:

void matrix(int a[2][2],int b[2][2],int c[2][2]);
main()
{
int a[2][2]={{3,3},{4,4}};
int b[2][2]={{1,1},{2,2}};
int c[2][2]={0},i,j;
matrix(a,b,c);
printf("product of 2 matrix is");
for(i=0;i<2;i++)
{
for(j=0;j<2;j++)
printf(" %d",c[i][j]);
printf(" ");
}
}
void matrix(int a[2][2],int b[2][2],int c[2][2])
{
int row,col,sum1=0,sum2=0;
for(col=0;col<2;col++)
{
row=0;
sum1=(a[row][col]*b[row][col])+(a[row][col]*b[row+1][col]);
c[row][col]=sum1;
sum2=(a[row+1][col]*b[row][col])+(a[row+1][col]*b[row+1][col]);
c[row+1][col]=sum2;
}
}

Sep 10, 2009 | Intel Computers & Internet

2 Answers

Geometric Mean


can't quite make out the detail on buttons on the image I have of your calculator but here goes.

say for example, the geometric mean of 2 × 3 × 6 × 8 is the 4th root of 288, or approximately 4.12.

enter nth root first, in this case 4 then shift then root symbol then open bracket, 2x3x6x8, close bracket then = ,
should give you 4.1195 etc

Jun 04, 2008 | Casio FX-300MS Calculator

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