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The ratio of a triangle is 2:4:5. if the longest side of the triangle is 150 cm, find the area of the triangle?

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About 3420 square centimeters.

If this is homework, be sure to show your work.

Posted on Jan 05, 2013

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The area of triangle LMN is 18 ft2 and the area of triangle FGH is 24 ft2. If , what is the ratio of LM to FG?


In two similar triangles, the ratio of their areas is the square of the ratio of their sides. Let's assume LMN and FGH are similar triangles. The ratio of the areas of LMN to FGH is 18 to 24, or 3 to 4 or 0.75. We would then take the square root of 0.75 to get the ratio of the sides. I get 0.866. The reason it is the square is the area of a triangle is base times height divided by 2, and the base and height and sides of similar triangles are proportional.

Good luck.

Paul

Similar Triangles ratio of areas

Mar 12, 2015 | Office Equipment & Supplies

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Regular pentagon QRSTU has a side length of 12 cm and an area of about 248 square cm. Regular pentagon VWXYZ has a perimeter of 140 cm. Find the area of VWXYZ. Round to the nearest tenth.


Find the scaling ratio
Perimeter of first pentagon is 12*5=60 cm
Scale factor (2nd/first)=140/60 =7/3
Ratio of areas varies as the square of the scale factor for the lengths
Area of second / area of first =(7/3)^2 =49/9
Area of second pentagon =248 *(49/9) cm^2
Finish the calculation.

Jul 01, 2014 | Texas Instruments TI-83 Plus Calculator

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Regular pentagon QRSTU has a side length of 12 cm and an area of about 248 square cm. Regular pentagon VWXYZ has a perimeter of 140 cm. Find the area of VWXYZ. Round to the nearest tenth.


The two pentagons are similar. If k is the scale factor for the lengths, the ratio of the areas is k^2.
Pent 1 side =12 cm
Pent 2 side =140/5 =28 cm
Scale factor (larger over smaller) is k=28/12=7/3
Area of Pent_2= (49/9)*Area of Pent_1
Your answer should be C.

Jun 29, 2014 | Office Equipment & Supplies

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Volume of triangular pyramid


Here is to get you started. To increase the size of the image do a CTRL Plus (+) in your browser.
You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of (1/2)*SQRT(203) or about 7.1239 cm

913b74c4-c453-4afa-be3a-c3e781816e8d.png

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found), the measure of the second leg is (1/3) the altitude of the equilateral triangle that forms the base. You should find (1/3) m MH= (1/3)* (11/2)*SQRT(3)
bc7a3bcd-ec6e-4936-9887-c6372904fe9f.png

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).
2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).
3. Total area = area of base + lateral area.
4. Volume= (1/3)(Area of base)* (height of pyramid)
If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.
1fbf065d-6c1d-440a-9069-783127aa9842.png

Mar 29, 2014 | Office Equipment & Supplies

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1.the ratio of the corresponding sides of two similar traingle is 3:2 what is the ratio of there height 2.the ratio of the corresponding sides of two similar traingle is 5:9 what is the ratio of...


1. the ratio of there height is 3:2
2. the ratio of areas of the triangle is: 125:6561
3. the perimeter of smaller parallelogram is: 40 cm2
4. THe real length of the object is 7 cm

Jan 21, 2011 | Dell Computers & Internet

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A hypoteneus of a isoseles right triangle is10cm .find its area


Hypotenuse being 10 makes the other sides of the triangle 5radical2. Area of a triangle is 1/2*b*h, for an isosceles triangle, it will be 1/2*b*b.
1/2*(5rad2)*(5rad2) 1/2*5*5*rad2*rad2 1/2*25*2 25 cm^2

Sep 15, 2010 | Mathsoft StudyWorks! Middle School Deluxe...

2 Answers

Can you gave me a example of a right triangle problems?


In right triangle we are making 90 degree angle triangle, we can have problem for finding hypotenuse or finding sin or cos values of the side of the triangle. For ex,Find out the hypotenuse,sin and cos value of the right triangle with base 4 cm and perpendicular 3 cm Solution:Hypotenuse = SQRT(4^2 + 3^2) =SQRT(4*4 + 3*3) =SQRT(16+9)=SQRT(25)=5 cm For right triangle, sin(x)=3/5=0.6 cos(x)=4/5 =0.8

Jul 16, 2010 | Super Tutor Trigonometry (ESDTRIG) for PC

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Open it


If the distance is 2 cm longer than the short side of a right triangle then the lengths could then be assumed as:
160px-triangle_rectangle_vect.svg.png magnify-clip.pngRight triangle A/B = 3 cm
A/C = 1 cm
B/C = 3 cm

Nov 03, 2009 | Sport & Outdoor - Others

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