Question about Texas Instruments TI-89 Calculator

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Can you Factor on a TI-84? IF not, does the TI-89?

I have a TI-84 but cannot factor problems like 6x(squared)+11x+4 = answer = (3x-4)(2x-1). I know how to factor, but would like to have a calculator that can do it. Is there a program I can buy for the TI-84 and program it, or will I need to purchase the TI-89? Does the TI-89 factor like this?

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Well, to answer part of your question, yes... the TI-89 does factor like this. it is inputted like this:

factor(6*x^2+11*x+4,x)

Check the catalog in the TI-84 (which is 2nd-zero) and look under F for factor()

Posted on Jan 19, 2009

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Chacha answers


It seems to me that you are trying to solve the quadratic equation
aX^2+bX+c=10 with a=-3, b=3, c=15 or -3X^2+3X+15=0.
Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation -3X^2+3X+15=0..
You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).
Discriminant is usually represented by the Greek letter DELTA (a triangle)
DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189
If the discriminant is positive (your case) the equation has two real solutions which are given by
Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2
Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2 or about -1.791287847
Here SQRT stands for square root.

Aug 17, 2014 | Computers & Internet

1 Answer

Chacha answers


It seems to me that you are trying to solve the quadratic equation
aX^2+bX+c=10 with a=-3, b=3, c=15 or -3X^2+3X+15=0.
Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation -3X^2+3X+15=0..
You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).
Discriminant is usually represented by the Greek letter DELTA (a triangle)
DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189
If the discriminant is positive (your case) the equation has two real solutions which are given by
Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2
Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2 or about -1.791287847
Here SQRT stands for square root.

Aug 17, 2014 | SoftMath Algebrator - Algebra Homework...

1 Answer

My ti 89 won't factor


The polynomial cannot be factored in the set of Real numbers: The roots of the polynomial equation are complex.
You should use the command cFactor( found under F2:Algebra> A:Complex>2:cFactor(
However, you should set the Mode Complex>Rectangular, and the EXACT/APPROXIMATE mode to Exact, otherwise your roots will be in decimal representation.
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Simplify 4x^2-36/x^2+2x-15*2x^2+11x+5/16x^2+16x-96/6x^2-7x+2/3x^2-4x-4


-42x^2 - 36/x^2 + 18x + 47/48x^2 - 4

I am confident that this is the simplified form.

Mar 16, 2011 | Computers & Internet

1 Answer

(2x+3y)(3x+2y)


(2x - 3y)(3x + 2y) = 2x*3x + 2x*2y - 3y*3x - 3y*2y
= 6x^2 + 4xy - 9xy - 6y^2
= 6x^2 - 5xy - 6y^2 You multiply each element in the first set of brackets by each element in the second set of brackets and then consolidate like terms and arrange them in sequence of powers, first x and then y. So:
2x by 3x = 6x squared
2x by 2y = 4xy
-3y by 3x = -9xy
-3y by 2y = 6y squared

6x squared -5xy + 6y squared

Dec 04, 2010 | Yahoo Computers & Internet

1 Answer

6x squared - 10x =0


Factor out 3X
3X(2X-5)=0
The expression is equal to zero if one of the factors on the left side equals zero.
1st solution: 3X=0, thus X=0
2nd solution 2X-5 = 0 if X=5/2

Sep 10, 2010 | Office Equipment & Supplies

2 Answers

6x2+11x+3


15 + 11x
14 + -14x
Next time use asterisks for multiplication symbols ***********************************************
or you will confuse many people

Sep 27, 2009 | The Learning Company Achieve! Math &...

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Inputing factors on a casio fx-115es calculator


Unless I am failing to understand your problem, just combine like terms to get:
9x^2+2x+4 and then enter those coefficients into the quadratic solver.
That will get you the two answers -- both of them will be complex.
If you wanted to turn those two answers into factors (complex) of the original equation simply
change the signs on each and put an x in front.
Of course, the quadratic formula would also work.
CG

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1 Answer

When factoring or finding deriv. it gives me number?


oh yeah, you must've archived x, that is, you put a number onto the x variable so that the calculator calculates the answer for you, and THEN AUTOMATICALLY calculates the answer when x is in terms of that number. I am guessing you accidentally did 10[sto] x at one point. You can simply unarchived the x number and everything will be dandy!

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