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Posted on Jan 02, 2017

SOURCE: what are the three consecutive integers whose sum

Let X be the lowest of the 3 integers

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Posted on Jan 28, 2011

SOURCE: find three consecutive odd integers whose sum is

if the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers

Posted on Sep 21, 2011

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

Let x be the smallest number.

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

Here's a simple (and inefficient) 35s program. It simply goes through a loop 25 times, adding up the numbers.

A001 LBL A

A002 25

A003 STO A

A004 0

A005 RCL+ A

A006 DSE A

A007 GTO A005

The sum of the first N positive integers can be calculated more efficiently as N(N+1)/2 .

A001 LBL A

A002 25

A003 STO A

A004 0

A005 RCL+ A

A006 DSE A

A007 GTO A005

The sum of the first N positive integers can be calculated more efficiently as N(N+1)/2 .

Mar 10, 2014 | HP 35s Programmable Scientific Calculator...

The two numbers are 32 and 34. The rest is your homework, you do it.

Dec 19, 2013 | Office Equipment & Supplies

15, 16, 17, 18

If this is a homework problem, be sure to show your work.

If this is a homework problem, be sure to show your work.

Aug 01, 2011 | Office Equipment & Supplies

X + ( X + 2 ) + ( X + 4 ) = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

Let X be the lowest of the 3 integers

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

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