Question about Texas Instruments TI-83 Plus Calculator

I'm given 4 linear equations, need to determine the adjoint [A+] and inverse [A-] matrices. To help, my initial matrix using the linear equations should look like: 1-2-1-1 2-(-1)-3-1 3-1-1-(-1) 1-2-(-1)-(-1)

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Posted on Jan 02, 2017

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SOURCE: ERR:SINGULAR MAT when finding inverse of matrices

If a matrix has a determinant of 0, this error appears. If you get this error, your matrix doesn't have an inverse.

Posted on Jun 06, 2009

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Step 1 - replace each x with a y and replace each y with an x

x=6y+24

Step 2 - Solve for y to get the equation in the slope intercept form y=mx+b

Step 3 - get the 24 to the other side by subtracting 24 for both sides

x-24=6y + 24 - 24

Simplify

x - 24 = 6y

Divide by the coefficient in front of the y to get y by itself.

x/6 - 24/6 = y

x/6 -4 = y

Write in the normal format by switching the sides.

y = x/6 - 4

Good luck.

Paul

x=6y+24

Step 2 - Solve for y to get the equation in the slope intercept form y=mx+b

Step 3 - get the 24 to the other side by subtracting 24 for both sides

x-24=6y + 24 - 24

Simplify

x - 24 = 6y

Divide by the coefficient in front of the y to get y by itself.

x/6 - 24/6 = y

x/6 -4 = y

Write in the normal format by switching the sides.

y = x/6 - 4

Good luck.

Paul

May 07, 2016 | Office Equipment & Supplies

For two linear equations, one can use

comparison, substitution, or addition/combination.

For more linear equations one uses the Cramer Rule that involves matrices and their determinants.

comparison, substitution, or addition/combination.

For more linear equations one uses the Cramer Rule that involves matrices and their determinants.

Sep 16, 2014 | Office Equipment & Supplies

Adjoint of a square (non singular matrix) = product of the determinant of matrix by the inverse of matrix. **Adjoint([A])= det( [A]) * [A]^-1**.

To get the inverse of a matrix, have its name displayed on command line then press the reciprocal key [x]^-1

To get the inverse of a matrix, have its name displayed on command line then press the reciprocal key [x]^-1

May 23, 2014 | Casio Fx-991es Scientific Calculator

What do you mean by "solve matrix"? Do you want its determinant? Its inverse? The eigenvalues and eigenvector? Solve a system of linear equations?

Jun 11, 2013 | Casio FC-200V Scientific Calculator

The TI-34 doesn't work with matrices.

Even if it did, you'd have to define what you mean by "compute." There are a lot of things that can be computed from a matrix, such as determinant, row and column norms, inverse, and eigenvalues.

Even if it did, you'd have to define what you mean by "compute." There are a lot of things that can be computed from a matrix, such as determinant, row and column norms, inverse, and eigenvalues.

Nov 21, 2012 | Texas Instruments TI-34 Scientific...

You should consult a Linear Algebra book. Besides, these calculator cannot handle matrices of dimensions 4x4 or higher . With matrices of dimension 3x3 and less it is probably easier to use the Cramer rules directly.

Nov 06, 2012 | Texas Instruments TI-30 XIIS Calculator

The FX-991ES offers simple matrix operations like basic arithmetic, plus the slightly more complex operations determinant and inversion. Furthermore, it is limited to matrices with a maximum size of three rows and three columns.

The rank of a matrix is defined as the number of linearly independent row or column vectors. You can perform a simple partial test for square matrices by calculating the determinant of the matrix:

Unfortunately, this is all support the calculator offers. For small matrices (i.e. 4x4 or smaller), you should familiarize yourself with the Gau? Elimination Method algorithm for solving linear equation systems. It is a two-step procedure where a matrix first is converted to its row echelon form, and second to row canonical form to solve the LES.

You need to follow the algorithm only through the first part, the number of non-zero rows after this step equals the rank of the matrix. With a little exercise you will be able to do it faster on paper than trying to do it with your calculator only.

For larger matrices I suggest to use a PC with more powerful math software (Maple, Mathematica, ...) or, if you know some basic computer programming, just write the necessary program yourself, which is also a very good exercise both in programming and understanding the algorithm.

The rank of a matrix is defined as the number of linearly independent row or column vectors. You can perform a simple partial test for square matrices by calculating the determinant of the matrix:

- Enter the matrix into matrix variable MatA.
- Press [SHIFT] [4] [7] [SHIFT] [4] [3] [)] [=]

Unfortunately, this is all support the calculator offers. For small matrices (i.e. 4x4 or smaller), you should familiarize yourself with the Gau? Elimination Method algorithm for solving linear equation systems. It is a two-step procedure where a matrix first is converted to its row echelon form, and second to row canonical form to solve the LES.

You need to follow the algorithm only through the first part, the number of non-zero rows after this step equals the rank of the matrix. With a little exercise you will be able to do it faster on paper than trying to do it with your calculator only.

For larger matrices I suggest to use a PC with more powerful math software (Maple, Mathematica, ...) or, if you know some basic computer programming, just write the necessary program yourself, which is also a very good exercise both in programming and understanding the algorithm.

Jan 16, 2011 | Casio FX-115ES Scientific Calculator

I am afraid you cannot use the TI8xPlus family of calculators to solve linear systems in matrix form. In this calculator, matrices must have real coefficients.

You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation

-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10

15a+8b-8d=0

8a+8c+10d=0

-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.

I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

- define X = a+i*b
- Define Y=c+i*d
- Rewrite the first equation substituting a+i*b for X and c+i*d for y.
- Gather all real terms together, and all imaginary terms together on the left.
- You will have (8a-15b-8c) +i(15a+8b-8d) = 10 +0i
- This equation can be split into two equations by saying that

- the real part pf the left member is equal to the real part of the right member, this gives 8a-15b-8c=10, and
- the imaginary part of the left member is equal to the imaginary part of the right member, this gives 15a+8b-8d=0

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation

-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10

15a+8b-8d=0

8a+8c+10d=0

-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.

I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

Feb 10, 2010 | Texas Instruments TI-84 Plus Calculator

Hello,

To solve Ohm's law you need no sophisticated calculator. If you know two quantities, you readily calculate the third. Application of Kirchhoff's (two h) laws to linear circuits, gives you a linear system of equations. If a calculator can solve linear systems, or handles matrices, the limitations would pertain to the maximum dimension of the matrices.

I just tried the TI83 to define a 45x45 square matrix and a 55x45 matrix. The maximum number of rows or columns is 99. But it will depend on memory.

If you have the TI84PLUS Silver Edition it should be fine. You can upgrade to a TI 89 Platinum, which can handle symbolic calculations (with undefined coefficients a, b, c).

Hope it helps.

To solve Ohm's law you need no sophisticated calculator. If you know two quantities, you readily calculate the third. Application of Kirchhoff's (two h) laws to linear circuits, gives you a linear system of equations. If a calculator can solve linear systems, or handles matrices, the limitations would pertain to the maximum dimension of the matrices.

I just tried the TI83 to define a 45x45 square matrix and a 55x45 matrix. The maximum number of rows or columns is 99. But it will depend on memory.

If you have the TI84PLUS Silver Edition it should be fine. You can upgrade to a TI 89 Platinum, which can handle symbolic calculations (with undefined coefficients a, b, c).

Hope it helps.

Sep 17, 2009 | Texas Instruments TI-84 Plus Silver...

If a matrix has a determinant of 0, this error appears. If you get this error, your matrix doesn't have an inverse.

Jun 02, 2009 | Texas Instruments TI-84 Plus Silver...

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