Question about Office Equipment & Supplies

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The least common denominator is 9, so 1/3 and 4/9 are 3/9 and 4/9 .

Posted on Nov 26, 2012

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Posted on Jan 02, 2017

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I interpreted the question as:

(x-2)/(4-x) + 2/3 = (x-2)/12 or

(x-2) 2 (x-2)

------ + --- = -----

(4-x) 3 12

Now to find a common denominator.

I factor all the terms and see what is common, so it can be eliminated to leave the lowest common denominator.

(4 - x) - prime - cannot be factored

3 - prime - cannot be factored

12 - 4 x 3

What is common in the above? The 3, so we can eliminate one 3.

Common denominator - (4 -x) (3)(4)

So, we must multiply the numerator and denominator of the first term by 12 (3 x 4).

The next term's numerator and denominator must be multiplied by 4(4-x).

The term on the right of the equals sign must have the numerator and denominator multiplied by (4-x).

Good luck.

If you need more assistance, post again.

Paul

(x-2)/(4-x) + 2/3 = (x-2)/12 or

(x-2) 2 (x-2)

------ + --- = -----

(4-x) 3 12

Now to find a common denominator.

I factor all the terms and see what is common, so it can be eliminated to leave the lowest common denominator.

(4 - x) - prime - cannot be factored

3 - prime - cannot be factored

12 - 4 x 3

What is common in the above? The 3, so we can eliminate one 3.

Common denominator - (4 -x) (3)(4)

So, we must multiply the numerator and denominator of the first term by 12 (3 x 4).

The next term's numerator and denominator must be multiplied by 4(4-x).

The term on the right of the equals sign must have the numerator and denominator multiplied by (4-x).

Good luck.

If you need more assistance, post again.

Paul

Apr 02, 2018 | Homework

I think you want to reduce the fraction to the lowest terms.

Improper fraction 1 3/4 produces an improper fraction of 7/4 (1 times denominator plus numerator)

To reduce a fraction, we need to divide the numerator (number on top) and the denominator (number on the bottom) by the greatest common factor (GCF).

To get the GCF, find the factors of the numerators and denominators and find the greatest number that is in both lists.

The factors of 2 are 1, 2.

The factors of 10 are 1, 2, 5, 10.

The greatest (largest) number is both lists is 2, so we divide the numerator and denominator by 2 and get 1/5.

Good luck,

Paul

Improper fraction 1 3/4 produces an improper fraction of 7/4 (1 times denominator plus numerator)

To reduce a fraction, we need to divide the numerator (number on top) and the denominator (number on the bottom) by the greatest common factor (GCF).

To get the GCF, find the factors of the numerators and denominators and find the greatest number that is in both lists.

The factors of 2 are 1, 2.

The factors of 10 are 1, 2, 5, 10.

The greatest (largest) number is both lists is 2, so we divide the numerator and denominator by 2 and get 1/5.

Good luck,

Paul

Feb 06, 2018 | Homework

Factor both the numerator and denominator, and then divide both the numerator and denominator by the greatest common factor.

For example, 1/3 + 1/6 = 2/6 + 1/6 = 3/6. We have to simplify 3/6. The factors of 3 are 3 and 1. The factors of 6 and 1, 2, 3, and 6. The greatest common factor is 3. Dividing the numerator and denominator by 3 results in 1/2.

Good luck.

Paul

For example, 1/3 + 1/6 = 2/6 + 1/6 = 3/6. We have to simplify 3/6. The factors of 3 are 3 and 1. The factors of 6 and 1, 2, 3, and 6. The greatest common factor is 3. Dividing the numerator and denominator by 3 results in 1/2.

Good luck.

Paul

Nov 23, 2015 | Texas Instruments TI-84 Plus Calculator

5 1/3 =16/3 because 5 x 3 + 1 = 16 then keep your denominator of 3

2 2/3 = 8/3 because 2 x 3 + 2 = 8 then keep your denominator of 3

1 1/3 = 4/3 because 1 x 3 + 1 = 4 then keep you denominator of 3

therefore

16/3 + 8/3 + 4/3 = 28/3 = 9 1/3

2 2/3 = 8/3 because 2 x 3 + 2 = 8 then keep your denominator of 3

1 1/3 = 4/3 because 1 x 3 + 1 = 4 then keep you denominator of 3

therefore

16/3 + 8/3 + 4/3 = 28/3 = 9 1/3

Mar 07, 2014 | Cars & Trucks

Unfortunately this calculator does not display results in radical form. If you enter SQRT(147) you get 12.12435565...

What you are asking for is called**rationalizing** an irrational expression. Usually one tries to get rid of radicals that appear in the denominators. Here is an example.

Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?

Recall the identity** (a-b)*(a+b)= a^2-b^2**. It is true for any **a** and **b **

**Rationalizing a denominator** (usual case)

Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))

[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=**c^2-d**

You see that there is no radical.

Now take**1/(c+SQRT(d))**. To get rid of the radical from the denominator multiply it by (c-SQRT(d)). But to leave the value of your expression ** 1/(c+SQRT(d))** unchanged, you must multiply both numerator and denominator by (c-SQRT(d)).

The numerator becomes 1*(c-SQRT(d))=**c-SQRT(d)**, and the denominator **(c^2-d)**.

Finally, the rationalized form of the expression**1/(c+SQRT(d))** is

[**c-SQRT(d)**]**/[c^2-d]**.

**Rationalizing a numerator**

Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same

Example:**(c+SQRT(d))**, the denominator here is 1

**(c+SQRT(d))**=(c+SQRT(d))*[c-SQRT(d)]/[c-SQRT(d)]. This gives

**[c^2-d]/[c-SQRT(d)]**

You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.

Your case is a lot simpler

SQRT(147)=7*SQRT(3)

Multiply it by SQRT(3)/SQRT(3) which is 1. This gives

SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

**SQRT(147)= 21/SQRT(3)**

What you are asking for is called

Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?

Recall the identity

Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))

[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=

You see that there is no radical.

Now take

The numerator becomes 1*(c-SQRT(d))=

Finally, the rationalized form of the expression

[

Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same

Example:

You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.

Your case is a lot simpler

SQRT(147)=7*SQRT(3)

Multiply it by SQRT(3)/SQRT(3) which is 1. This gives

SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

Feb 09, 2014 | Texas Instruments TI-30XA Calculator

12 has factors 2*2*3

8 has factors 2*2*2

So lowest common denominator is 2*2*2*3 or 24

3/12 = 6/24 and 3/8 = 9/24

8 has factors 2*2*2

So lowest common denominator is 2*2*2*3 or 24

3/12 = 6/24 and 3/8 = 9/24

Jan 16, 2014 | Mathsoft Computers & Internet

Convert each mixed number (what you call mixed fraction) to an improper fraction, then multiply the two numerators and multiply the two denominators. Reduce the resulting fraction to its simplest form

Example

(2 1/3)*(1 5/7)=?

Convert 2 1/3 to an improper fraction 2 1/3=2+ 1/3 = 6/3+1/3=7/3

Convert 1 5/7 to an improper fraction 1 5/7=1+ 5/7 =7/7 +5/7=12/7

(2 1/3)*(1 5/7)= (7/3)*(12/7)= (7*12)/(3*7)

The 7's in the numerator and denominator cancel one another leaving

12/3=4

**(2 1/3)*(1 5/7)=4**

Not all products of mixed numbers will give a simple result as this one. More likely they will not.

Example

(2 1/3)*(1 5/7)=?

Convert 2 1/3 to an improper fraction 2 1/3=2+ 1/3 = 6/3+1/3=7/3

Convert 1 5/7 to an improper fraction 1 5/7=1+ 5/7 =7/7 +5/7=12/7

(2 1/3)*(1 5/7)= (7/3)*(12/7)= (7*12)/(3*7)

The 7's in the numerator and denominator cancel one another leaving

12/3=4

Not all products of mixed numbers will give a simple result as this one. More likely they will not.

Dec 12, 2013 | Computers & Internet

The LCD of the denominators is 24, so rewrite the sum as

3/24 + 6/24 + 8/24 + 4/6

This gives 21/24, which reduces to 7/8 .

3/24 + 6/24 + 8/24 + 4/6

This gives 21/24, which reduces to 7/8 .

Oct 25, 2012 | Office Equipment & Supplies

A quantity into which all the denominators of a set of fractions may be
divided without a remainder.

See this link

LINK

See this link

LINK

Jun 28, 2010 | Mathsoft Mathcad Expert Solver Full...

Hello,

You must first eliminate the denominators by reducing the different expressions to the same denominators. Use the distributivity property of multiplication to expand your terms. Gather similar monomials. Do all the cleaning to reduce your equation to one of the 2 types that the calculator can handle.[Mode][5:EQN] [3: ax2+bx+c] or [4:ax3+bx2+cx+d]

**Remember :Any solution that makes one of the original denominators equal 0 must be rejected.**

**Hope it helps.**

You must first eliminate the denominators by reducing the different expressions to the same denominators. Use the distributivity property of multiplication to expand your terms. Gather similar monomials. Do all the cleaning to reduce your equation to one of the 2 types that the calculator can handle.[Mode][5:EQN] [3: ax2+bx+c] or [4:ax3+bx2+cx+d]

Jun 15, 2009 | Casio FX-115ES Scientific Calculator

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