Question about MathRescue Word Problems Of Algebra Lite

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Area of triangel = 1/2BH

2 1/5 = 11/5

(1/2)(11/5)(5/9)= 55/90

approximately .61 yards

Posted on Nov 09, 2012

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Posted on Jan 02, 2017

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I find the easiest way to solve these is to sketch them first (I'm a visual learner;) We get a nice right-angled triangle, with the right-angle at B. The formula for the area of a triangle is 1/2 * base* height or (base * height)/2.

We can use BC or AB as the base.

If we use BC as the base, the length is 9-4 or 5. The height is 6-2 or 4.

We can now but the base and the height in the formula to figure out the area.

Good luck.

Paul

We can use BC or AB as the base.

If we use BC as the base, the length is 9-4 or 5. The height is 6-2 or 4.

We can now but the base and the height in the formula to figure out the area.

Good luck.

Paul

Mar 19, 2015 | Office Equipment & Supplies

In two similar triangles, the ratio of their areas is the square of the ratio of their sides. Let's assume LMN and FGH are similar triangles. The ratio of the areas of LMN to FGH is 18 to 24, or 3 to 4 or 0.75. We would then take the square root of 0.75 to get the ratio of the sides. I get 0.866. The reason it is the square is the area of a triangle is base times height divided by 2, and the base and height and sides of similar triangles are proportional.

Good luck.

Paul

Similar Triangles ratio of areas

Good luck.

Paul

Similar Triangles ratio of areas

Mar 12, 2015 | Office Equipment & Supplies

720.

Here is how i did it (my way).

1. doubled the area to 160 and found two sides of a square that would equal the area (a*b). I chose the numbers 16 (which I will use for the base of my triangle and 10 for the height.

2. Checking my answer, (h*b)/2 I see that my triangle area is indeed 80

3. multiply the base *3 = 48 and height *3 = 30

4. (30*48) / 2=720

5. Work check using calculated area of a square 3x larger: (a*b)=area (48*30) = 1440 1/2 of the area creates a triangle so: (1440/2) = 720

This may not be common core or whatever is being taught now, but having a basic knowledge of geometry allows me to figure out problems like these pretty easily.

Here is how i did it (my way).

1. doubled the area to 160 and found two sides of a square that would equal the area (a*b). I chose the numbers 16 (which I will use for the base of my triangle and 10 for the height.

2. Checking my answer, (h*b)/2 I see that my triangle area is indeed 80

3. multiply the base *3 = 48 and height *3 = 30

4. (30*48) / 2=720

5. Work check using calculated area of a square 3x larger: (a*b)=area (48*30) = 1440 1/2 of the area creates a triangle so: (1440/2) = 720

This may not be common core or whatever is being taught now, but having a basic knowledge of geometry allows me to figure out problems like these pretty easily.

Mar 06, 2015 | Office Equipment & Supplies

The are of a triangle is 1/2 * the base * the height.

So if the triangle is 2 for the base and 4 for the height. it would be (2*4*1/2) or 2*4=8, 8*1/2=4. So the area of the triangle would be 4 square (until of measure).

Of course this assumes you know the base and the height of the particular triangle.

This site might be a bit more helpful for calculations where some of the numbers may not be known. Good luck!

http://www.wikihow.com/Calculate-the-Area-of-a-Triangle

So if the triangle is 2 for the base and 4 for the height. it would be (2*4*1/2) or 2*4=8, 8*1/2=4. So the area of the triangle would be 4 square (until of measure).

Of course this assumes you know the base and the height of the particular triangle.

This site might be a bit more helpful for calculations where some of the numbers may not be known. Good luck!

http://www.wikihow.com/Calculate-the-Area-of-a-Triangle

Feb 04, 2015 | The Learning Company Achieve! Math &...

A pyramid has 5 sides including the base. If the base is a rectangle L long and W wide, its area is L*W.

The other sides are triangles. If the height of the pyramid is H, the triangles that are L wide at the base will have a height of the square root of half of W squared plus H squared, or SQRT((.5*W)^2+H^2) and the two that are W wide at the base will have a height of SQRT((.5*L)^2+H^2). The area of a triangle is .5*height*base, so the total surface two triangles with the same height and base is 2*.5*height*base = height*base.

So, the total surface area of a pyramid L long by W wide by H tall would be:

L*W (the area of the base)

+ L*SQRT((.5*W)^2+H^2) (the area of the 2 triangles with base L)

+ W*SQRT((.5*L)^2+H^2) (the area of the 2 triangles with base W)

Hope this is helpful!

The other sides are triangles. If the height of the pyramid is H, the triangles that are L wide at the base will have a height of the square root of half of W squared plus H squared, or SQRT((.5*W)^2+H^2) and the two that are W wide at the base will have a height of SQRT((.5*L)^2+H^2). The area of a triangle is .5*height*base, so the total surface two triangles with the same height and base is 2*.5*height*base = height*base.

So, the total surface area of a pyramid L long by W wide by H tall would be:

L*W (the area of the base)

+ L*SQRT((.5*W)^2+H^2) (the area of the 2 triangles with base L)

+ W*SQRT((.5*L)^2+H^2) (the area of the 2 triangles with base W)

Hope this is helpful!

May 23, 2014 | Encore Math Advantage Algebra II and...

Hypotenuse squared = base squared + height squared.

H^2 = 5^2 + 4^2

H^2 = 25 + 16

H^2 = 41

H = sqrt(41)

Hypotenuse = about 6.4 feet

H^2 = 5^2 + 4^2

H^2 = 25 + 16

H^2 = 41

H = sqrt(41)

Hypotenuse = about 6.4 feet

May 06, 2014 | Office Equipment & Supplies

Here is to get you started. To increase the size of the image do a CTRL Plus (+) in your browser.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of** (1/2)*SQRT(203) **or about 7.1239 cm

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),**the measure of the second leg is (1/3) the altitude** **of the equilateral triangle** that forms the base. You should find (1/3) m MH= (1/3)* **(11/2)*SQRT(3)**

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

Mar 29, 2014 | Office Equipment & Supplies

Use the formula for the area of the triangle with symbols.

Let b be the measure of the base, and h the measure of the height.

The area of the triangle is A= b*h/2 (original situation)

Now consider the new situation (situation2)

Let b` the new base and h`the new height.

We have b'=2b, and h`=h/2

The new area A`=b`*h`/2=(2b)*(h/2)/2=b*h/2 and that is equal to the original situation.

Now consider a third situation

Let b"=2b, h"=h

**A"=b"*h"/2=(2b)*h/2=2(b*h/2)=2A**

Let b be the measure of the base, and h the measure of the height.

The area of the triangle is A= b*h/2 (original situation)

Now consider the new situation (situation2)

Let b` the new base and h`the new height.

We have b'=2b, and h`=h/2

The new area A`=b`*h`/2=(2b)*(h/2)/2=b*h/2 and that is equal to the original situation.

Now consider a third situation

Let b"=2b, h"=h

Mar 10, 2012 | Computers & Internet

Use the formula for the area of the triangle Area=b*h/2.

If the base becomes b'=2b and h'=h/2, then the area of this new triangle is Area'= (2b)*(h/2)/2.

As you can see the two 2's introduced cancel one another and the area is unchanged. A'=A.

If the base is doubled and the height remains the same, then b''=2b, and h''=h. Substitute in the area formula for a triangle to get

A''=b''*h''/2= (2b)*h/2= 2*(b*h/2)=2A

You see that in this case the area is doubled.

If the base becomes b'=2b and h'=h/2, then the area of this new triangle is Area'= (2b)*(h/2)/2.

As you can see the two 2's introduced cancel one another and the area is unchanged. A'=A.

If the base is doubled and the height remains the same, then b''=2b, and h''=h. Substitute in the area formula for a triangle to get

A''=b''*h''/2= (2b)*h/2= 2*(b*h/2)=2A

You see that in this case the area is doubled.

Jan 18, 2012 | Computers & Internet

o find the area of a triangle, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that aparallelogram can be divided into 2 triangles. For example, in the diagram to the left, the area of each triangle is equal to one-half the area of the parallelogram.

Since the area of a parallelogram is , the area of a triangle must be one-half the area of a parallelogram. Thus, the formula for the area of a triangle is: or where is the base, is the height and**·** means multiply.
The base and height of a triangle must be perpendicular to each other. In each of the examples below, the base is a side of the triangle. However, depending on the triangle, the height may or may not be a side of the triangle. For example, in the right triangle in Example 2, the height is a side of the triangle since it is perpendicular to the base. In the triangles in Examples 1 and 3, the lateral sides are not perpendicular to the base, so a dotted line is drawn to represent the height.

Since the area of a parallelogram is , the area of a triangle must be one-half the area of a parallelogram. Thus, the formula for the area of a triangle is: or where is the base, is the height and

May 13, 2011 | Computers & Internet

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