Below mention is my equation.

(437/10000)X = 0.287

I need to find the value 'X'

how to derive. Please help me

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Posted on Jan 02, 2017

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that sounds like a problem about "slopes" so I am looking at using the derivative, which is basically the slope of the graph.

- the equation of line PQ can be simplified to y(x) = -2kx + k -8

- derivative relative to X (k is a constant) gives you -2k

- derivative of y(x) = 4x + 7 relative to x gives you 4

if the lines are parallel then the slopes are equal:

-2k=4 gives you k = -2 => your function becomes y = 4x - 8

if the lines are perpendicular the two slopes multiplied together give you -1:

-2k * 4 = -1 gives you k=1/8 => function becomes y = -1/4x - 7/8 or in other words y = -(2x+7)/8

I have made graphic representation and it looks to be correct.

I hope it makes sense.

- the equation of line PQ can be simplified to y(x) = -2kx + k -8

- derivative relative to X (k is a constant) gives you -2k

- derivative of y(x) = 4x + 7 relative to x gives you 4

if the lines are parallel then the slopes are equal:

-2k=4 gives you k = -2 => your function becomes y = 4x - 8

if the lines are perpendicular the two slopes multiplied together give you -1:

-2k * 4 = -1 gives you k=1/8 => function becomes y = -1/4x - 7/8 or in other words y = -(2x+7)/8

I have made graphic representation and it looks to be correct.

I hope it makes sense.

Apr 12, 2017 | Homework

For the Equation to follow the following definitions apply

S = scfm (the answer you want)

P = Barometric pressure in Pounds per square inch when you measured the cfm.

14.696 = standard barometric pressure at sea level

So:

S = P/14.73 x cfm

Example: Denver

Barometric Pressure 11.50 psi

cfm = 5400

S = 11.5 / 14.696 x 5400 = 4225.6 scfm

There was a lot of debate in the Natural gas industry years ago about the Standard barometric pressure value. Some Companies used 14.69 psi and others used 14.73 psi.

If you use natural gas to heat your home this is the same equation used by the gas company to correct for altitude on your bill.

The equation is derived from Boyles Law which is accurate at pressures close to atmospheric pressure.

S = scfm (the answer you want)

P = Barometric pressure in Pounds per square inch when you measured the cfm.

14.696 = standard barometric pressure at sea level

So:

S = P/14.73 x cfm

Example: Denver

Barometric Pressure 11.50 psi

cfm = 5400

S = 11.5 / 14.696 x 5400 = 4225.6 scfm

There was a lot of debate in the Natural gas industry years ago about the Standard barometric pressure value. Some Companies used 14.69 psi and others used 14.73 psi.

If you use natural gas to heat your home this is the same equation used by the gas company to correct for altitude on your bill.

The equation is derived from Boyles Law which is accurate at pressures close to atmospheric pressure.

Feb 25, 2015 | Heating & Cooling

If your equation can be written in the form of a function (y=f(x)),

the slope of the function at a point is the derivative of the function at the point. For any function that is not a constant or linear, you need calculus to find the slope.

If the function is of the form y= ax +b, the slope is the value a.

the slope of the function at a point is the derivative of the function at the point. For any function that is not a constant or linear, you need calculus to find the slope.

If the function is of the form y= ax +b, the slope is the value a.

Mar 21, 2014 | Texas Instruments TI-84 Plus Calculator

It can calculate numerical values of derivatives of functions and definite integrals but it does not solve differential equations.

Aug 25, 2013 | Office Equipment & Supplies

There is only one stationary point for the function **y(x)=((x-1)^(1/3))*((x+2)^(2/3))** and it is pointwith coordinates** x=0 and y=-1.5859**

At first, first derivation is**y'(x)=x/((x-1)^(2/3))*((x+2)^(1/3))** and we obtained that **y'(0)=0**. Then we can find second derivation of the function and for value x=0 we could concluded that **y''(0)>0**. In this stationary point it is minimum value of the function.

Finally, at the points x=-2 and x=1 we have so called**critical values** for this function.

See captured images below

1. Second derivation for y(x)

2. Graph y(x)

3. Enlarged detail of the graph y(x)

At first, first derivation is

Finally, at the points x=-2 and x=1 we have so called

See captured images below

1. Second derivation for y(x)

2. Graph y(x)

3. Enlarged detail of the graph y(x)

Mar 27, 2012 | Texas Instruments TI-89 Calculator

First thing to do, before you enter the value of the equation to your calculator multiply the first term((1/3x+5) from the second term(1/3x+5) to make your answer simplified.Then after that you will observed that your answer look like in this pattern AX2 +BX+C it means that the equation is in general form of quadratic equation. So, in your problem,we are looking for a value of X1 and X2,when you used your calculator in solving this problem, First On you calculator then look for the mode then press it after that look for the equation(EQN).Then from the side of the word EQN there is a corresponding number to press,from my calculator it is number 5..Then press it.After you press it, there is a equations choices,look for the equation AX2 +BX+C then press it(given number to press). Now,enter the value of A, B and C from your simplified answer. After pressing the value of A press = sign from your calculator same as B and C.After you enter all the value of A,B and C continuously press = sign from your calculator till you get the answer, the value of X1 and X2.

Jun 14, 2011 | Texas Instruments TI-30 XIIS Calculator

Once the graph is drawn you can use the Calculate menu to find

You cannot find the location of an inflexion point as this requires the knowledge of the 2nd derivative of the function, and this calculator calculates the first derivative only. However, there may be 3rd-party programs that handle this, on ticalc.org website. Use at your own risk and under your sole responsibility.

To access the seven menu options above, you press [2nd][TRACE] to open the (CALC) menu. Use the Down and Up Arrows to move cursor along the menu options.

- 1:value, the value of the function at a point
- 2:Zero, the coordinate of a point where the function vanishes (has value zero)
- 3:minimum, the location of a point where the function has a minimum
- 4:maximum
- 5:intersect , the value of the function when it crosses the y-axis (y-intercept)
- 6:dy/dx, the value of the derivative of the function at a point.
- 7: Integral (f(x),dx)

You cannot find the location of an inflexion point as this requires the knowledge of the 2nd derivative of the function, and this calculator calculates the first derivative only. However, there may be 3rd-party programs that handle this, on ticalc.org website. Use at your own risk and under your sole responsibility.

To access the seven menu options above, you press [2nd][TRACE] to open the (CALC) menu. Use the Down and Up Arrows to move cursor along the menu options.

Oct 28, 2010 | Texas Instruments TI-84 Plus Calculator

Do you mean as in a linear equation? If so it is simple the slope of the equation. If you are referring to an exponential equation the derivative is always changing so no.

Sep 23, 2010 | Texas Instruments TI-Nspire Graphic...

If the setting Derivative is ON, the value of the first derivative is
evaluated at the point of the graph where the trace cursor happens to
be.

When you hit trace, the cursor was displayed at the X-value of -4. If you want the value of the derivative at x=2, just move the cursor to x=2. Use the right arrow key. Once the cursor is at x=2, the first derivative of the function at x=2 will be displayed.

- Here is a screen capture with the example of the function y=2x^2-3. I drew the tangent at x=2. It may not always be possible to have the value calculated at a point of your choosing. this is due to the finite value of the increment in the drawing. You may have to play with the window settings.

As you can see the computed value of the derivative is correct but the y-value is not (due to the finite pitch)

In the next screen capture all values are correct using trace, but the tangent line at x=2 was drawn separately.

When you hit trace, the cursor was displayed at the X-value of -4. If you want the value of the derivative at x=2, just move the cursor to x=2. Use the right arrow key. Once the cursor is at x=2, the first derivative of the function at x=2 will be displayed.

- Here is a screen capture with the example of the function y=2x^2-3. I drew the tangent at x=2. It may not always be possible to have the value calculated at a point of your choosing. this is due to the finite value of the increment in the drawing. You may have to play with the window settings.

As you can see the computed value of the derivative is correct but the y-value is not (due to the finite pitch)

In the next screen capture all values are correct using trace, but the tangent line at x=2 was drawn separately.

Apr 18, 2010 | Casio FX-115ES Scientific Calculator

You have some numerical value stored in the variable x, which the calculator is plugging into the resultant equation.

You can clear individual variables with 2ND [VAR-LINK]. You can clear all one-character variables a-z with 2ND [F6] 1. You can initialize the machine for a new problem with 2ND [F6] 2.

You can clear individual variables with 2ND [VAR-LINK]. You can clear all one-character variables a-z with 2ND [F6] 1. You can initialize the machine for a new problem with 2ND [F6] 2.

Feb 10, 2010 | Texas Instruments TI-89 Calculator

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