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I need need answer for..

Below mention is my equation.

(437/10000)X = 0.287

I need to find the value 'X'

how to derive. Please help me

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Posted on Jan 04, 2009


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The equation of the straight line PQ is 3-2kx+k+1=12,calculate,in each case,the numerical value of k if the line PQ is parrallel to the line y=4x+7;is perpendicular to the line y=4x+7;

that sounds like a problem about "slopes" so I am looking at using the derivative, which is basically the slope of the graph.
- the equation of line PQ can be simplified to y(x) = -2kx + k -8
- derivative relative to X (k is a constant) gives you -2k
- derivative of y(x) = 4x + 7 relative to x gives you 4

if the lines are parallel then the slopes are equal:
-2k=4 gives you k = -2 => your function becomes y = 4x - 8

if the lines are perpendicular the two slopes multiplied together give you -1:
-2k * 4 = -1 gives you k=1/8 => function becomes y = -1/4x - 7/8 or in other words y = -(2x+7)/8

I have made graphic representation and it looks to be correct.
I hope it makes sense.

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How do I convert cfm to scfm

For the Equation to follow the following definitions apply

S = scfm (the answer you want)
P = Barometric pressure in Pounds per square inch when you measured the cfm.
14.696 = standard barometric pressure at sea level


S = P/14.73 x cfm

Example: Denver

Barometric Pressure 11.50 psi
cfm = 5400

S = 11.5 / 14.696 x 5400 = 4225.6 scfm

There was a lot of debate in the Natural gas industry years ago about the Standard barometric pressure value. Some Companies used 14.69 psi and others used 14.73 psi.

If you use natural gas to heat your home this is the same equation used by the gas company to correct for altitude on your bill.

The equation is derived from Boyles Law which is accurate at pressures close to atmospheric pressure.

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How do you find the slope of an equation?

If your equation can be written in the form of a function (y=f(x)),
the slope of the function at a point is the derivative of the function at the point. For any function that is not a constant or linear, you need calculus to find the slope.
If the function is of the form y= ax +b, the slope is the value a.

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Runge kutta method on casio fx 991 ms

It can calculate numerical values of derivatives of functions and definite integrals but it does not solve differential equations.

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Can you find stationary points of this equation ((x-1)^1/3)*((x+2)^2/3))

There is only one stationary point for the function y(x)=((x-1)^(1/3))*((x+2)^(2/3)) and it is pointwith coordinates x=0 and y=-1.5859

At first, first derivation is y'(x)=x/((x-1)^(2/3))*((x+2)^(1/3)) and we obtained that y'(0)=0. Then we can find second derivation of the function and for value x=0 we could concluded that y''(0)>0. In this stationary point it is minimum value of the function.
Finally, at the points x=-2 and x=1 we have so called critical values for this function.
See captured images below

1. Second derivation for y(x)

2. Graph y(x)

3. Enlarged detail of the graph y(x)

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1 Answer


First thing to do, before you enter the value of the equation to your calculator multiply the first term((1/3x+5) from the second term(1/3x+5) to make your answer simplified.Then after that you will observed that your answer look like in this pattern AX2 +BX+C it means that the equation is in general form of quadratic equation. So, in your problem,we are looking for a value of X1 and X2,when you used your calculator in solving this problem, First On you calculator then look for the mode then press it after that look for the equation(EQN).Then from the side of the word EQN there is a corresponding number to press,from my calculator it is number 5..Then press it.After you press it, there is a equations choices,look for the equation AX2 +BX+C then press it(given number to press). Now,enter the value of A, B and C from your simplified answer. After pressing the value of A press = sign from your calculator same as B and C.After you enter all the value of A,B and C continuously press = sign from your calculator till you get the answer, the value of X1 and X2.

Jun 14, 2011 | Texas Instruments TI-30 XIIS Calculator

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How do we find the coordinates of a maximum,minimum or point of inflexion on the calculator?is it possible to find the differentiation of an equation with the calculator?thanks

Once the graph is drawn you can use the Calculate menu to find
  • 1:value, the value of the function at a point
  • 2:Zero, the coordinate of a point where the function vanishes (has value zero)
  • 3:minimum, the location of a point where the function has a minimum
  • 4:maximum
  • 5:intersect , the value of the function when it crosses the y-axis (y-intercept)
  • 6:dy/dx, the value of the derivative of the function at a point.
  • 7: Integral (f(x),dx)
For most of the foregoing calculations, you need to supply the interval of x-values that is of interest to you.To move the cursor along the curve to set the left limit and right limit of the interval of interest, use the LeftArrow and RightArrow keys.

You cannot find the location of an inflexion point as this requires the knowledge of the 2nd derivative of the function, and this calculator calculates the first derivative only. However, there may be 3rd-party programs that handle this, on website. Use at your own risk and under your sole responsibility.

To access the seven menu options above, you press [2nd][TRACE] to open the (CALC) menu. Use the Down and Up Arrows to move cursor along the menu options.

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Is there any way you can find the derivative without saying a point value?

Do you mean as in a linear equation? If so it is simple the slope of the equation. If you are referring to an exponential equation the derivative is always changing so no.

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Hi, I have two different Casio's, and I get the wrong answer in both - so I am doing something wrong.I want the derivate when x=2, and the derivate is "on". But when I ask for "trace" - x=4 shows up! Very...

If the setting Derivative is ON, the value of the first derivative is evaluated at the point of the graph where the trace cursor happens to be.
When you hit trace, the cursor was displayed at the X-value of -4. If you want the value of the derivative at x=2, just move the cursor to x=2. Use the right arrow key. Once the cursor is at x=2, the first derivative of the function at x=2 will be displayed.

- Here is a screen capture with the example of the function y=2x^2-3. I drew the tangent at x=2. It may not always be possible to have the value calculated at a point of your choosing. this is due to the finite value of the increment in the drawing. You may have to play with the window settings.

As you can see the computed value of the derivative is correct but the y-value is not (due to the finite pitch)
In the next screen capture all values are correct using trace, but the tangent line at x=2 was drawn separately.

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So im asked to get the derivative of an equation, for example 2x^4+3x^2. I press home, f3, and input my equation, ,x and then press enter. instead of the solution coming out to be 8x^3+6x, the solution...

You have some numerical value stored in the variable x, which the calculator is plugging into the resultant equation.

You can clear individual variables with 2ND [VAR-LINK]. You can clear all one-character variables a-z with 2ND [F6] 1. You can initialize the machine for a new problem with 2ND [F6] 2.

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