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365 transmitters

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Hi,

Motorola Two-Way Radios

365??????????

Not near enough info given, please give as much info as you can, just mentioning the brand and a number means very little to me.

Cheers,
Peter

Posted on Mar 10, 2013

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How many people must be in a room before the probability that some share a birthday becomes at least 50 percent? Use different values of n in the formula and approximate to the nearest n. show all work.


With two people in the room, the probability that the second person shares a birthday with the first is 1/365 (let's ignore leap years for the time being). Thus, the probability that they DON'T share a birthday is 364/365.

Add a third person. The probability that this person does not share a birthday with either of the first two (assuming they don't share a birthday) is 363/365. Thus, the probability that none of the three share a birthday is (364/365)*(363/365).

The probability that a fourth person doesn't share a birthday with any of the first three is 362/365. Thus the probability that none of the four share a birthday is (364/365)*(363/365)*(362/365).

See the pattern here? The probability of the n-th person not sharing a birthday is (366-n)/365. Keep adding people and multiplying the terms together until the probability of no one sharing a birthday drops below 0.5 --- which is when the probability of at least one pair sharing a birthday climbs above 50%.

Since this sounds like a homework problem, you'll have to do the rest.

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