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Posted on Jan 02, 2017
SOURCE: mcculloch 310 oil mix ratio
The proper gas/oil ratio is 50:1, that is 50 parts gas, to one part (2) cycle oil.
If you plan on leaving gas in the tank when not being used, I always recommend adding some gas stabilizer, such as Sta-bil, which makes starting the chain saw easier regardless of how long the fuel mix has been sitting in the tank or saw (up to 2 years according to Sta-bil label)
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Posted on Sep 09, 2009
SOURCE: I need to know the
On the container of 2 cycle oil you buy, it will have a mixing chart. 50:1 (means 50 parts of gas to 1 part of oil) usually uses around 4 ounces of 2 cycle oil to each gallon of gasoline. The other compartment is for bar & chain oil, that is what lubricates the bar & chain.
Posted on Sep 06, 2010
Fuelleaking from the cap will not stop it running, 40-1 with good quaility two stroke oil shoule be fine, if there is a good spark and fuel at the plug, you need to check that the piston has not picked up, the hottest part of the engine is the exhaust side, so remove the muffler, and take a look at the piston skirt throught the open exhaust port, any signs of scuffing and it will need to come apart to check the damage.
Posted on Oct 11, 2011
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The calculated moles of C = [grams C] / [MW of C] = [188 g C / 12.0 g] = 15.7 mol C
Therefore, there are 15.7 moles of O2, as calculated from use of the math expression (with boxes) shown above.
The wanted GRAMS of O2 are calculated from MW of O2 times its number of moles, as follows:
Grams of O2 = 32.0 g O2 x 15.7 mol O2 = 502 grams O2.
For your convenience as you make conversions among grams and moles, you may use the following memory aid:
To go from moles to grams, just notice that moles are beside MW, so multiplying them will give grams (moles x MW = grams). If you want to go from grams to moles, notice that grams are over MW, so (grams/MW) = moles. If you should want to calculate MW, you would divide grams by moles, (grams/moles) = MW.
One more tip: When doing calculations, use at least the same number of significant figures (sig figs) in the molecular weights (and atomic weights) as is in the given numerical data. That is, since there are three sig figs in 188 grams of C, use 12.0 as the atomic weight of C, and 44.0 as the MW of CO2. You would obtain the same answer using 12 and 44, but as you may know, following this rule would be more important in other problems in which the digit past the decimal is not zero. This allows proper rounding off of the final calculated quantity.
Suggestion: Try out this method to other problems involving a chemical reaction. Good luck!
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