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Angle of depression

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Lauren was standing on the pier at the beach approach trying to find her sister. She spotted her at the water’s edge at an angle of depression of 28°. If the pier is 5 yards above the sand, how far down the beach is Lauren’s sister?

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angle of depression - 9cd8f44.jpg ð XAC = ð ACB (Angle of elevation= Angle of depression)
AB = 5 Yards
BC = ?
Now Tan C= AB/BC
BC = AB/ Tan C
BC = 5 / Tan 28 Yards
BC = 5/.531709 Yards
BC = 9.403632 Yards

Posted on Jan 10, 2009

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Try checking this site for information on Angles of Depression and Elevation.

Posted on Feb 23, 2011

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A right angle triangle with length of AB 10cm and AC 20cm, how do I find the angle of BC

Assuming that the angle at A is the right angle, Pythagoras' theorem says that the length of the hypotenuse (the side opposite the right angle) is the square root of the sum of the squares of the other two sides. In your case, AB and AC are 'the other two sides' and BC is the hypotenuse, so:

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length BC = V 10 + 20 = V 100 + 400

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and the angle at B is arc-tan(20/10) - 26.5 deg and 63.5 deg)

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(5x-15)+(3x+5)=180 angle a = (5x-15) degrees (obtuse) angle b = (3x+5) degrees (acute) both angles are supplementary to each other equaling 180 solving for x

Solve for x
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move 10 from left to right and you get8x190
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so the first angle is (5*23.75)-15 = 103.75
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Make sense? I love math, let me know it you need more help

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An airplane is flying at a height of 2 miles above the ground. The distance along the ground from the airplane to the airport is 5 miles. What is the angle of depression from the airplane to the airport?

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

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I need an urgent help..pleassssssssseeeee....

cafdef1.jpg Given AC = 2675 feet
ð XAC= 14 degree
Therefore ð ACB = 14
Now Sin C= AB/AC
AB = AC . Sin C
AB = 2675 * Sin 14 feet
AB = 2675 * 0.241922 feet
AB = 647.1411 feet

Jan 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

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Hi Jehho soria

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Nov 14, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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what is the value of sin30.28?
how can it be found using log table?

Sep 07, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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