Question about Super Tutor Trigonometry (ESDTRIG) for PC
A pilot flies a plane north for 300 kilometers then 80 degrees east for 100 kilometers, find the distance from the starting point and direction
this is solved by starting with the SECOND leg of the flight considered as a triangle.
Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.
Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).
Now get the total flight NORTH = 300 + 11 = 311
- and total EAST = 83.9
Finally, use Pythagoras theorem.to get the total DISTANCE:
square root of ( 311 squared + 83 squared ) = 321 km
Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees
Posted on Dec 19, 2008
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Posted on Jan 02, 2017
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