Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

4x+2y=8

x y

(0, -4)

Posted on Jan 26, 2009

This is the process of how you would solve this.

-move the -3x over to the right hand side, so you have:

y = 5 + 3x

- since you know what x is, plug in the x which is 1:

y = 5 + 3(1)

- solve the equation

y = 5+3

y = 8, so the solution is 8.

Posted on Dec 16, 2008

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Posted on Jan 02, 2017

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | Computers & Internet

It seems to me that you are trying to solve the quadratic equation

aX^2+bX+c=10 with a=-3, b=3, c=15 or**-3X^2+3X+15=0**.

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation**-3X^2+3X+15=0**..

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

**Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2**

**Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2** or about -1.791287847

Here SQRT stands for square root.

aX^2+bX+c=10 with a=-3, b=3, c=15 or

Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation

You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).

Discriminant is usually represented by the Greek letter DELTA (a triangle)

DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189

If the discriminant is positive (your case) the equation has two real solutions which are given by

Here SQRT stands for square root.

Aug 17, 2014 | SoftMath Algebrator - Algebra Homework...

Triple means 3 times as much. Example 15 is the triple of 5 because 15=5*3.

There is also the word TRIPLET which means a collection (ordered or not ordered) of three quantities or objects. When doing coordinate geometry in space you locate a point by giving its three coordinates (x,y,z). The collection of three numbers (x,y,z) is a triplet.

There is also the word TRIPLET which means a collection (ordered or not ordered) of three quantities or objects. When doing coordinate geometry in space you locate a point by giving its three coordinates (x,y,z). The collection of three numbers (x,y,z) is a triplet.

Apr 08, 2013 | The Learning Company Achieve! Math &...

Solve for Y first.

y= (1-3x)/-5

Then plug in a number for x and you'll get a Y value.

x= 0 y =-1/5

x1=1 y1= 2/5

(y-y1)/(x-x1) = m

m= your slope.

On that calculator you would do it the same way but graph it 1st and then pick to values that are easier to work with.

y= (1-3x)/-5

Then plug in a number for x and you'll get a Y value.

x= 0 y =-1/5

x1=1 y1= 2/5

(y-y1)/(x-x1) = m

m= your slope.

On that calculator you would do it the same way but graph it 1st and then pick to values that are easier to work with.

Nov 04, 2010 | MathAid Algebra II

Solve for x

5x+3x+(-15) + 5 becomes 8x-10=180

move 10 from left to right and you get8x190

8x = 190

x = 23.75

so the first angle is (5*23.75)-15 = 103.75

and the second angle is (3*23.75) +5 = 76.25

check by adding 76.25+103.75 = 180

Make sense? I love math, let me know it you need more help

5x+3x+(-15) + 5 becomes 8x-10=180

move 10 from left to right and you get8x190

8x = 190

x = 23.75

so the first angle is (5*23.75)-15 = 103.75

and the second angle is (3*23.75) +5 = 76.25

check by adding 76.25+103.75 = 180

Make sense? I love math, let me know it you need more help

Mar 06, 2010 | SuperTutor Homeworkhelp.Com Super Tutor...

Hello,

You have the method: apply it.

2 *(3x-4)(4x+5) =(6x-8)(4x+5)

Now apply the FOIL method

F: 6x*4x=24x^2

O: 6x*5=30x

I; -8*4x=-32x

L: -8*5=-40

so the result is

24x^2 + 30x-32x -40 =24x^2 -2x-40

You have the method: apply it.

2 *(3x-4)(4x+5) =(6x-8)(4x+5)

Now apply the FOIL method

F: 6x*4x=24x^2

O: 6x*5=30x

I; -8*4x=-32x

L: -8*5=-40

so the result is

24x^2 + 30x-32x -40 =24x^2 -2x-40

Oct 01, 2009 | The Learning Company Achieve! Math &...

This is an equation of a straight line, and we can easily find the the coordinates where this line intersects the axis in following ways:-

**for x-axis:-**

put y=0, 4x+2*0=8

4x =8

x =8/4

x =2

so intersection coordinates ate (2, 0)

**for y-axis:-**

put x=0, 4*0+2y=8

2y =8

y =8/2

y =4

so intersection coordinates ate (0, 4)

Thanks

Zulfikar ali

ali_zulfikar@yahoo.com

9899780221

put y=0, 4x+2*0=8

4x =8

x =8/4

x =2

so intersection coordinates ate (2, 0)

put x=0, 4*0+2y=8

2y =8

y =8/2

y =4

so intersection coordinates ate (0, 4)

Thanks

Zulfikar ali

ali_zulfikar@yahoo.com

9899780221

Jan 26, 2009 | SoftMath Algebrator - Algebra Homework...

7x-3 + 3x = -53

7x + 3x - 3 = -53

10x - 3 = -53

10x = -53 + 3

10x = -50

x = -5

Therefore 4x + 9 is equal to 4 times (-5) plus 9

-20 + 9 equals -11

7x + 3x - 3 = -53

10x - 3 = -53

10x = -53 + 3

10x = -50

x = -5

Therefore 4x + 9 is equal to 4 times (-5) plus 9

-20 + 9 equals -11

Dec 17, 2008 | SoftMath Algebrator - Algebra Homework...

B. 2((2-Y)/3)-Y=3

2(2-Y)-Y=9

4-2Y-Y=9

-3Y=9-4

-3Y=5

-Y=5/3

Y=-1.67

A. 3X+(-1.67)=2

3X-1.67=2

3X=2+1.67

3X=3.67

X=3.67/3

X=1.22

2(2-Y)-Y=9

4-2Y-Y=9

-3Y=9-4

-3Y=5

-Y=5/3

Y=-1.67

A. 3X+(-1.67)=2

3X-1.67=2

3X=2+1.67

3X=3.67

X=3.67/3

X=1.22

Nov 05, 2007 | SoftMath Algebrator - Algebra Homework...

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