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Posted on Jan 02, 2017

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The answer depends on the lender you are seeking to obtain the loan from. Each lender has a different policy and the minimum income requirement depends largely on that. For example, if you are planning to obtain the __Personal Loan in Mumbai__ from NBFCs like Bajaj Finserv, you can expect the minimum income requirement to be in between Rs 37, 000 - Rs 40, 000 in Mumbai. The same differs for applicants living in TIER 2 and TIER 3 cities. However, your salary requirements change lender to lender.

Now, if you are planning to apply at any public-sector bank, the income requirement might be on the lower side. Banks like the State Bank of India or the Central Bank of India have the responsibility to serve a larger mass, serve all categories of individuals and therefore the requirement will be on the lower side. Besides, the Central Bank of India doesn't even have a min-income requirement for their cent-Personal Loan scheme. Their rule is simple, the applicant is eligible for a maximum of 20 times of his/her gross salary subject to a maximum of Rs 10 lakh. The only drawback is, public sector banks can be an option for people thinking of borrowing a larger sum. Therefore, the suitable option is to apply at any NBFC.

Now, if you are planning to apply at any public-sector bank, the income requirement might be on the lower side. Banks like the State Bank of India or the Central Bank of India have the responsibility to serve a larger mass, serve all categories of individuals and therefore the requirement will be on the lower side. Besides, the Central Bank of India doesn't even have a min-income requirement for their cent-Personal Loan scheme. Their rule is simple, the applicant is eligible for a maximum of 20 times of his/her gross salary subject to a maximum of Rs 10 lakh. The only drawback is, public sector banks can be an option for people thinking of borrowing a larger sum. Therefore, the suitable option is to apply at any NBFC.

Apr 20, 2018 | Personal Computers & Internet

annual salary $40,000

annual bonus 3,600

11.1%

annual bonus 3,600

11.1%

Dec 16, 2015 | Office Equipment & Supplies

Salary & Govt. Concessions for a Member of Parliament (MP)

Monthly Salary : 12,000

Monthly Salary : 12,000

Jun 28, 2014 | Computers & Internet

The average salary of a mobile application developer comes up to about $90,000 in Canada!

Sep 24, 2013 | Toys

Multiply 28,000 by 1.06, then by 1.06, then by 1.06, then by 1.06.

Jan 22, 2012 | Computers & Internet

So expected returns are just a little more advanced version of probability - without getting too in detail it uses weighted averages so you do not have to add the same number 17 times.

Let's first define our variables:

E(X) = Expected Return X1 = Variable 1 P1 = Probability 1 (in decimal format so 55% would be .55) X2 = Variable 2 P2 = Probability 2 (P2 is also equal to 1 - P1)

So the expected return formula is as follows:

E(X) = (X1)*(P1) + (X2)*(P2)

Plugging in our given numbers we get E(X) = Expected Return X1 = 300,000 P1 = 10% or .1 X2 = 40,000 P2 = 1 - P1 = 1 - .1 = .9

E(X) = (300,000)*(.1) + (40,000)*(.9) E(X) = 66,000

Now remember this does not include the opportunity cost of spending your four years in college studying biology instead of another degree.

Let's first define our variables:

E(X) = Expected Return X1 = Variable 1 P1 = Probability 1 (in decimal format so 55% would be .55) X2 = Variable 2 P2 = Probability 2 (P2 is also equal to 1 - P1)

So the expected return formula is as follows:

E(X) = (X1)*(P1) + (X2)*(P2)

Plugging in our given numbers we get E(X) = Expected Return X1 = 300,000 P1 = 10% or .1 X2 = 40,000 P2 = 1 - P1 = 1 - .1 = .9

E(X) = (300,000)*(.1) + (40,000)*(.9) E(X) = 66,000

Now remember this does not include the opportunity cost of spending your four years in college studying biology instead of another degree.

Feb 27, 2011 | Texas Instruments BA-II Plus Calculator

this is an accounting problem, u have the wrong wweb site

Jul 15, 2010 | Computers & Internet

The formula that would have been used to increase his salary each year probably was: Original Salary * (100% + inflation) = New Salary

Rearranging this, we get: Original Salary = New Salary / (100% + inflation)

So...

Last Year: 42000 / 102% = 41176.47 = 41176 (rounded)

2 Years Ago: 41176.47 / 103% = 39977.16 = 39977 (rounded)

Rearranging this, we get: Original Salary = New Salary / (100% + inflation)

So...

Last Year: 42000 / 102% = 41176.47 = 41176 (rounded)

2 Years Ago: 41176.47 / 103% = 39977.16 = 39977 (rounded)

Oct 31, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Hi,
First of all please check the conditions but as far as i understand the conditions the program would be like this-

#include<stdio.h> #include<conio.h> void main() { int salary,bonus,totalsalary,hours; printf("enter salary"); scanf("%d",&salary); printf("enter hours"); scanf("%d",&hours); if(hours<45 && hours>=40) { bonus=500; } else { if(hours<40 && hours>=35) { bonus=300; } else { if(hours<=30 && hours>20) { bonus=150; } else { bonus=0; } } } totalsalary=salary+bonus; printf("Salary=%d",salary); printf("Bonus=%d",bonus); printf("Total Salary=%d",totalsalary); getch(); }

But the conditiosn given by you are not seems to be correct.Just correct the conditions value if wrong and run the program Thanks! mannu_rakesh

#include<stdio.h> #include<conio.h> void main() { int salary,bonus,totalsalary,hours; printf("enter salary"); scanf("%d",&salary); printf("enter hours"); scanf("%d",&hours); if(hours<45 && hours>=40) { bonus=500; } else { if(hours<40 && hours>=35) { bonus=300; } else { if(hours<=30 && hours>20) { bonus=150; } else { bonus=0; } } } totalsalary=salary+bonus; printf("Salary=%d",salary); printf("Bonus=%d",bonus); printf("Total Salary=%d",totalsalary); getch(); }

But the conditiosn given by you are not seems to be correct.Just correct the conditions value if wrong and run the program Thanks! mannu_rakesh

Aug 04, 2009 | Computers & Internet

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