Edwin is twice as old as ruel. in 3 years, edwin willbe 13 years lessthan thrice as old as ruel. Find thier ages

Edwin is 14. Ruel is 7.

In 3 years Edwin will be 17. Edwin will be 10. (3*10 - 13 = 17)

Let x=Ruel's age now, and 2x=Edwin's age now.

2x+3=3(x+3)-13

2x+3=3x+9-13

2x+3=3x-4

2x+7=3x

7=x

If you are going to post these, the least you could do is rate them as Fixya. :-) Thanks!

Posted on Dec 12, 2008

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Posted on Jan 02, 2017

let c = cory's age now
let s = her sisters age now

cory's age now = sisters age + 6 years

=> c = s + 6

4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)

4 years ago cory was 4 times older than her sister

=> c - 4 = 4*(s-4)

We can simplify this to c = 4s - 16 +4 c = 4s - 12

We can then use simultaneous equations to solve the two equations

(i) c = s + 6 (ii) c = 4s - 12

If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24

We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12

__For clarity:__
Her sister's age now is of course 6
4 years ago Cory would of been 8 and her sister would of been 2

I hope this helps and good luck! If you have more questions - ask away!

Please take the time to rate this answer

Many Thanks Don.

cory's age now = sisters age + 6 years

=> c = s + 6

4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)

4 years ago cory was 4 times older than her sister

=> c - 4 = 4*(s-4)

We can simplify this to c = 4s - 16 +4 c = 4s - 12

We can then use simultaneous equations to solve the two equations

(i) c = s + 6 (ii) c = 4s - 12

If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24

We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12

I hope this helps and good luck! If you have more questions - ask away!

Please take the time to rate this answer

Many Thanks Don.

Sep 13, 2011 | Sunburst My Mathematical Life Single...

yes... 13+5=18 31+5=36 36/2 =18

Jul 20, 2011 | MathRescue Word Problems Of Algebra Lite

test email mama heta udeta yanawa.

Dec 23, 2010 | Computers & Internet

Jamie = x

Luiz = x+4

Ramon = x+7

3x+11=29

3x=18

x=6

Jamie = 6 , Luiz = 6+4 = 10 , Ramon = 6+3 = 13

Luiz = x+4

Ramon = x+7

3x+11=29

3x=18

x=6

Jamie = 6 , Luiz = 6+4 = 10 , Ramon = 6+3 = 13

Oct 13, 2010 | MathRescue Word Problems Of Algebra Lite

This is more of a trial and error question, not a math question; however,

If Jason is 26, then last year he was 25 (5 squared) and next year he will be 27, which is the cube of 3 (3x3x3=27).

Got it?

-Gort.

If Jason is 26, then last year he was 25 (5 squared) and next year he will be 27, which is the cube of 3 (3x3x3=27).

Got it?

-Gort.

Sep 18, 2010 | Mathsoft Solving and Optimization...

(D=Dad's age, and S=Son's age)

D=S+20 (Dad is 20 years older than Son)

D+10 = 2xS (In ten years Dad will be twice Son's current age)

therefore (by substitution):

S+20+10 = 2xS

S+30 = 2S

2S = S+30

2S-S = 30 (subtract S from both sides)

D = S+20

D = 30+20

In ten years, Dad will be 60, which is twice Son's current age of 30.

Please ask for -Gort.

Aug 27, 2010 | Mathsoft Solving and Optimization...

Allan is 19 and Roy is 13.

Solution:

First we have 2 variables, their ages: I used Allan = x & Roy = y

Equation 1: X - 4 = 2*(Y-4) - 3

We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.

Equation 2: X = Y + 6

Substitute Y + 6 for X in equation 1:

X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3

That simplifies to Y + 2 = 2Y - 8 - 3

Rewrite it again: Y + 2 = 2Y - 11

Add 11 to both sides: Y + 13 = 2Y

Subtract Y from both sides: 13 = Y

Now plug 13 in for y in Equation 2

X = Y + 6

X = 13 + 6

X = 19

Solution:

First we have 2 variables, their ages: I used Allan = x & Roy = y

Equation 1: X - 4 = 2*(Y-4) - 3

We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.

Equation 2: X = Y + 6

Substitute Y + 6 for X in equation 1:

X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3

That simplifies to Y + 2 = 2Y - 8 - 3

Rewrite it again: Y + 2 = 2Y - 11

Add 11 to both sides: Y + 13 = 2Y

Subtract Y from both sides: 13 = Y

Now plug 13 in for y in Equation 2

X = Y + 6

X = 13 + 6

X = 19

Oct 08, 2009 | Vivendi Math Blaster Algebra (03763) for...

X+X+28=4(X+X)

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

Apr 21, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Since you have the answer, the easiest way to work with this is to work with real numbers and break it down. What are the knowns?

Rose + 25 = Dad

10 + 25 = 35 (today)

5 years ago, Dad (then 30) was 2x old as Rose will be 5 years from now (+5), or (30/2) -5 = 10

You can also put this into formulas

Rose + 25 = Dad

Dad - 5 = 2 * (Rose + 5)

So, if Dad = Rose + 25, you can substitute one for the other in the 2nd formula, like so:

(Rose + 25) - 5 = 2 * (Rose + 5)

Rose + 20 = 2 * (Rose + 5)

Now, you can solve for Rose and eventually come up with 10

I hope this helps.

Rose + 25 = Dad

10 + 25 = 35 (today)

5 years ago, Dad (then 30) was 2x old as Rose will be 5 years from now (+5), or (30/2) -5 = 10

You can also put this into formulas

Rose + 25 = Dad

Dad - 5 = 2 * (Rose + 5)

So, if Dad = Rose + 25, you can substitute one for the other in the 2nd formula, like so:

(Rose + 25) - 5 = 2 * (Rose + 5)

Rose + 20 = 2 * (Rose + 5)

Now, you can solve for Rose and eventually come up with 10

I hope this helps.

Jul 20, 2008 | Computers & Internet

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