# Find thier ages

Edwin is twice as old as ruel. in 3 years, edwin willbe 13 years lessthan thrice as old as ruel. Find thier ages

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Edwin is 14. Ruel is 7.

In 3 years Edwin will be 17. Edwin will be 10. (3*10 - 13 = 17)

Let x=Ruel's age now, and 2x=Edwin's age now.

2x+3=3(x+3)-13
2x+3=3x+9-13
2x+3=3x-4
2x+7=3x
7=x

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## Related Questions:

### Adjoa is three years older than her brother Kwame.seven years ago,the sum of their ages 13years.calculate the sum of their present ages.

Let Adjoa's age be x and Kwame's y.
• Adjoa is 3 years older than Kwame: x=y+3
• Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
• Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
• 2y-4-7=13
• 2y=24
• y=24/2=12 years
• x=y+3=12+3=15 years
• sum of their present ages is x+y=12+15=27 years

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### The sum of ages of marian, diana and carlos are 17. Two years from now marian will twice as old as diana. if carlos is half as old as marian four years from now. How ald are they now ? Pls show the...

Let m be Marian's age, d Diana's age and c Carlos age.
• sum of ages is 17: m+d+c=17
• two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
• Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
• now: m+d+c=m+m/2-1+m/2-2=17
• 2m=17+3=20
• m=20/2=10 years
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• c=m/2-2=5-2=3 years
Marian is 10 years old, Diana 4 years old and Carlos is 3 years old.

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

### Tom is 5 times as old as todd.In seven years Tom's age will be 6 years more than 3 times as old as Todd. How old is Todd

Todd is 4 years old.

Let Tom's age = X
Let Todd's age = Y

From the given facts:

X = 5Y

and

X + 7 + 6 = 3 ( Y + 7 )
X+13 = 3Y + 21
X = 3Y + 8

So if:
X=5Y
and
X=3Y+8

Then:
5Y=3Y+8
2Y=8
Y=4

I hope that helps.

Joe.

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Correction: Bob is thrice as old as Peter.
Let b be the current age of Bob, and p the current age of Peter. Now, b=3p
Six years earlier the relations was: b-6=4*(p-6)=4p-24.
Take the 6 to the right side leaving b=4p-18
Remember that now b=3p. Use it in the equation above
b=(3p)=4p-18, This becomes 3p=4p-18 or 0=p-18, and p=18
Peter is 18 years old, and Bob is 3*18=54 years old.
Verification: 6 years ago Peter was 12 years old and Bob 48 years old. 48/12=4.

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### Mary who is sixteen years old is four times as old as her brother.How old will mary be when his twice as old as her old brother?

Let the brother's age be x:
16years for Mary = 4x years for Brother

From equation: 4x = 16
x = 4
Therefore, the brother is 4 years old.

Mary Brother
16 4
After 4 years + 4 4
20 8
After the next 4 years + 4 4
24 12

24 is twice as old as 12; therefore for the sister to be twice as old as brother she will 24years when her brother is 12 years.

Or by calculation;

If 4 is the age for the brother, when the sister is 16, and y years will pass for the to be such that the sister is twice as old as the brother, then;

16 + y = 2(4 + y)
16 + y = 8 + 2y
16 - 8 = 2y - y
8 = y
Therefore, 8 years elapse before the sister is twice as old as the brother.

Sister will be: (16 + 8) = 24years
Brother will be: (4 + 8) = 12years

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### Father is 3 times as old as his daughter.In 12 years father will be 1 year less than twice his daugthers age.What is their age?

So the father is 3 times as old as his daughter.
Let F represent the age of the fatherLet D represet the age of the daughter
So we know from the first sentence,
F = 3 * D
From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,
First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D
But since its 12 years from now, we have to add 12 to both ages
(F + 12) + 1 = 2 * (D + 12)
Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11
Now we have to solve these two equations together, we can plug the first equation into the second,
F = 3 * DF = 2 * D + 11
3 * D = 2 * D + 11D = 11
So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation
F = 3 * DF = 3 * 11F = 33
So the father is 33 and the daughter is 11.

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### Give me one example of quadratic age word problem.

Within 11 years, the age of Peter will be half the square of the age he was 13 years ago. Calculate the current age of Peter.

Suzy is ten years older than Billy, and next year she will be twice as old as Billy. How old are they now?

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### Jasmin is twice as old as rodney nine years ago

Hi,

Let the present age of the Rodney = X
present Age of the Jasmin = Y

As per the Situation,

Y-9 = 2 (X - 9)
Y-9 = 2X - 18
Y = 2X - 18 +9
Y = 2X-9

Second,

X + Y = 45
Y = 45 - X

Taking Both the situations,

2X - 9 = 45 - X
3X = 54
X = 54/3 = 18

Y = 45 - 18 = 27

Hence,

Age of Jasmin = 27

Let me know, if needed further assistance.

Hope i helped you.

Thanks for using ' Fixya ' and have a nice day!!

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Allan is 19 and Roy is 13.

Solution:

First we have 2 variables, their ages: I used Allan = x & Roy = y
Equation 1: X - 4 = 2*(Y-4) - 3
We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.
Equation 2: X = Y + 6

Substitute Y + 6 for X in equation 1:
X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3
That simplifies to Y + 2 = 2Y - 8 - 3
Rewrite it again: Y + 2 = 2Y - 11
Add 11 to both sides: Y + 13 = 2Y
Subtract Y from both sides: 13 = Y

Now plug 13 in for y in Equation 2
X = Y + 6
X = 13 + 6
X = 19

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### Algebra

Paul 3 years younger to his friend peter. In seven years, the product of their ages would be 5 more than the product of their ages 5 years ago. How old are they now?

Oct 31, 2008 | Texas Instruments TI-30XA Calculator

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