Age problem a father is 8 times as old as his son and 4 times as old as his daughter. if the daugther is 4yrs. older than the son, how old is each? pls.... answer this. with representation and a tableif you want.

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Let x= the age of the son.

Therefore 8x=4(x+4)
Then 8x=4x+16
4x=16
x=4

Son is 4
Daughter is 8
Father is 32.

Posted on Dec 10, 2008

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"quadratic function" diophantus , a greek

Let x be Diophantus' age when he died.

His son died 4 years before Diophantus (so Diophantus was then x-4 years old). His son lived half as long as Diophantus so when he (son) died he was x/2.
Diophantus' son was born when Diophantus was (x-4)-x/2 years old. That was 5 years after his marriage so when Diophantus married he was (x-4)-x/2-5 years old. We also know that 1/6 of his life was spent in childhood, 1/12 in youth and 1/7 as bachelor so (x-4)-x/2-5=(1/6+1/12+1/7)x.
Now you solve last equation:
• x-4-x/2-5=11/28x
• x/2-11/28x=4+5
• 3/28x=9
• x=9*28/3=84 years

Diophantus was 84 years old when he died.

Sep 27, 2011 | Office Equipment & Supplies

Cory is 6 years older than her sister.Four years ago, she was 4 times as old her sister.how old is cory now?

let c = cory's age now let s = her sisters age now
cory's age now = sisters age + 6 years
=> c = s + 6
4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)
4 years ago cory was 4 times older than her sister
=> c - 4 = 4*(s-4)
We can simplify this to c = 4s - 16 +4 c = 4s - 12
We can then use simultaneous equations to solve the two equations
(i) c = s + 6 (ii) c = 4s - 12
If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24
We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12
For clarity: Her sister's age now is of course 6 4 years ago Cory would of been 8 and her sister would of been 2
I hope this helps and good luck! If you have more questions - ask away!
Many Thanks Don.

Sep 13, 2011 | Sunburst My Mathematical Life Single...

Father is 3 times as old as his daughter.In 12 years father will be 1 year less than twice his daugthers age.What is their age?

So the father is 3 times as old as his daughter.
Let F represent the age of the fatherLet D represet the age of the daughter
So we know from the first sentence,
F = 3 * D
From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,
First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D
But since its 12 years from now, we have to add 12 to both ages
(F + 12) + 1 = 2 * (D + 12)
Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11
Now we have to solve these two equations together, we can plug the first equation into the second,
F = 3 * DF = 2 * D + 11
3 * D = 2 * D + 11D = 11
So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation
F = 3 * DF = 3 * 11F = 33
So the father is 33 and the daughter is 11.

Jul 19, 2011 | Computers & Internet

Fathers age is reverse of son's age one year back father's age was twise the son's what is the current age of father

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Mar 02, 2011 | Apple Cell Phones

Ek dada,ek baap,ek pota,tino ka age 140 years.pota jitne month ka dada utne saal ka,pota jitne din ka baap utne week ka,tino ka age kya hoga?

Hahahaha, Aaala! Kafi sochna para, is tarha ho ga mere khyaal se;
140 Saal teenoN ki mila k banti hay;

Pota: 7Years
Baap: 49Years

7+49+84 = 140 (Theek)

Pota kitnay Month ka = 7 x 12 = 84 => Dada ki umer in years (Theek)

Pota kitnay Din ka = 7 x 365 = 2555din => Baap ki umer in weeks [ (49x365) / 7 ] = 2555 (Ye be Theek)

Concerned, Nooh bin Sikander

Dec 18, 2010 | Computers & Internet

Alvin is now 20 years older than his son.In 10 years,he will be twice as old as his son's age.What are their present age's?

Christine,

D=S+20 (Dad is 20 years older than Son)
D+10 = 2xS (In ten years Dad will be twice Son's current age)
therefore (by substitution):
S+20+10 = 2xS
S+30 = 2S
2S = S+30
2S-S = 30 (subtract S from both sides)
S = 30 (Son's current age) *answer*
D = S+20
D = 30+20

In ten years, Dad will be 60, which is twice Son's current age of 30.

Aug 27, 2010 | Mathsoft Solving and Optimization...

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