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Let x= the age of the son.

Therefore 8x=4(x+4)

Then 8x=4x+16

4x=16

x=4

Son is 4

Daughter is 8

Father is 32.

Posted on Dec 10, 2008

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Posted on Jan 02, 2017

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Let x be Diophantus' age when he died.

His son died 4 years before Diophantus (so Diophantus was then x-4 years old). His son lived half as long as Diophantus so when he (son) died he was x/2.

Diophantus' son was born when Diophantus was (x-4)-x/2 years old. That was 5 years after his marriage so when Diophantus married he was (x-4)-x/2-5 years old. We also know that 1/6 of his life was spent in childhood, 1/12 in youth and 1/7 as bachelor so (x-4)-x/2-5=(1/6+1/12+1/7)x.

Now you solve last equation:

Diophantus was 84 years old when he died.

His son died 4 years before Diophantus (so Diophantus was then x-4 years old). His son lived half as long as Diophantus so when he (son) died he was x/2.

Diophantus' son was born when Diophantus was (x-4)-x/2 years old. That was 5 years after his marriage so when Diophantus married he was (x-4)-x/2-5 years old. We also know that 1/6 of his life was spent in childhood, 1/12 in youth and 1/7 as bachelor so (x-4)-x/2-5=(1/6+1/12+1/7)x.

Now you solve last equation:

- x-4-x/2-5=11/28x
- x/2-11/28x=4+5
- 3/28x=9
- x=9*28/3=84 years

Diophantus was 84 years old when he died.

Sep 27, 2011 | Office Equipment & Supplies

let c = cory's age now
let s = her sisters age now

cory's age now = sisters age + 6 years

=> c = s + 6

4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)

4 years ago cory was 4 times older than her sister

=> c - 4 = 4*(s-4)

We can simplify this to c = 4s - 16 +4 c = 4s - 12

We can then use simultaneous equations to solve the two equations

(i) c = s + 6 (ii) c = 4s - 12

If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24

We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12

__For clarity:__
Her sister's age now is of course 6
4 years ago Cory would of been 8 and her sister would of been 2

I hope this helps and good luck! If you have more questions - ask away!

Please take the time to rate this answer

Many Thanks Don.

cory's age now = sisters age + 6 years

=> c = s + 6

4 years ago, cory was 4 years younger ( i.e. c-4) and her sister was 4 years younger (s- 4)

4 years ago cory was 4 times older than her sister

=> c - 4 = 4*(s-4)

We can simplify this to c = 4s - 16 +4 c = 4s - 12

We can then use simultaneous equations to solve the two equations

(i) c = s + 6 (ii) c = 4s - 12

If we multiply both sides of equation (i) by 4 we get (iii) 4c = 4s + 24

We can then subtract equation (ii) from equation (iii) to eliminate the '4s' term => ( 4c = 4s + 24 ) - (c = 4s - 12) => 4c - c = 4s +24 - 4s +12 => 3c = 4s - 4s +36 => 3c = 36 => c = 36/3 => c = 12 => Cory's age now = 12

I hope this helps and good luck! If you have more questions - ask away!

Please take the time to rate this answer

Many Thanks Don.

Sep 13, 2011 | Sunburst My Mathematical Life Single...

Hi

Never.

Even a February 29th Leap Year birthday only rings their ages within 11-12 years of each other.

Never.

Even a February 29th Leap Year birthday only rings their ages within 11-12 years of each other.

Aug 27, 2011 | TOPICS Entertainment College Pro...

So the father is 3 times as old as his daughter.

Let F represent the age of the fatherLet D represet the age of the daughter

So we know from the first sentence,

F = 3 * D

From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,

First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D

But since its 12 years from now, we have to add 12 to both ages

(F + 12) + 1 = 2 * (D + 12)

Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11

Now we have to solve these two equations together, we can plug the first equation into the second,

F = 3 * DF = 2 * D + 11

3 * D = 2 * D + 11D = 11

So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation

F = 3 * DF = 3 * 11F = 33

So the father is 33 and the daughter is 11.

Let F represent the age of the fatherLet D represet the age of the daughter

So we know from the first sentence,

F = 3 * D

From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,

First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D

But since its 12 years from now, we have to add 12 to both ages

(F + 12) + 1 = 2 * (D + 12)

Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11

Now we have to solve these two equations together, we can plug the first equation into the second,

F = 3 * DF = 2 * D + 11

3 * D = 2 * D + 11D = 11

So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation

F = 3 * DF = 3 * 11F = 33

So the father is 33 and the daughter is 11.

Jul 19, 2011 | Computers & Internet

well there are two ways:

- u can request ur network operator to give u the unlocking code.[xpensiv]

or

- u can go to a mobile hardware repair shop and get ur mobile unlocked by a box device.[cheap]

- u can request ur network operator to give u the unlocking code.[xpensiv]

or

- u can go to a mobile hardware repair shop and get ur mobile unlocked by a box device.[cheap]

Mar 02, 2011 | Apple Cell Phones

Hahahaha, Aaala!
Kafi sochna para, is tarha ho ga mere khyaal se;

140 Saal teenoN ki mila k banti hay;

Pota:** 7Years**

Baap:**49Years**

Dada:**84Years**

**7+49+84 = 140 (Theek)**

Pota kitnay Month ka = 7 x 12 = 84 **=>** Dada ki umer in years** (Theek)**

Pota kitnay Din ka = 7 x 365 = 2555din **=>** Baap ki umer in weeks [ (49x365) / 7 ] = 2555 (**Ye be Theek**)

*Concerned, Nooh bin Sikander*

140 Saal teenoN ki mila k banti hay;

Pota:

Baap:

Dada:

Dec 18, 2010 | Computers & Internet

Father is 40 and child is 10

then 45 and 15

then 45 and 15

Dec 18, 2010 | Computers & Internet

(D=Dad's age, and S=Son's age)

D=S+20 (Dad is 20 years older than Son)

D+10 = 2xS (In ten years Dad will be twice Son's current age)

therefore (by substitution):

S+20+10 = 2xS

S+30 = 2S

2S = S+30

2S-S = 30 (subtract S from both sides)

D = S+20

D = 30+20

In ten years, Dad will be 60, which is twice Son's current age of 30.

Please ask for -Gort.

Aug 27, 2010 | Mathsoft Solving and Optimization...

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