Question about Inverter Aims Pure Sine Wave Power 2000/5000w

My aims 5000 watt inverter is showing that it is pulling more amps than it should on the display. For example an 8 amp dryer is pulling about 180 amps whereas it should not even be registering on the display at all. What would cause this?

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The amp meter on this unit measures the battery current. So if you have an 8 amp load at 120 vac you will draw more than 80 amps at 12 volts and 40 amps at 24 volts. While this may not explain the 180 amps that you are seeing -- it's possible that the dryer is drawing more than 8 amps.

Posted on Jan 11, 2009

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Posted on Jan 02, 2017

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dear see that :

1- the range of voltage which inverter work between it for example 180-260 v

2- most small generator voltage reach more than 260V so the inveter not work

3-check the frequency of genaratoer if it not fix the inverter will mot work

1- the range of voltage which inverter work between it for example 180-260 v

2- most small generator voltage reach more than 260V so the inveter not work

3-check the frequency of genaratoer if it not fix the inverter will mot work

Oct 12, 2014 | Aims Power AIMS PWRIC300012W 3000 Watt |...

The correct size of inverter is an easy calculation and important to ensure long life from the inverter and the life of the appliances getting there power from the inverter. To calculate you take the volts and multiply by the amps which equals the wattage. Every appliance has a tag which must state the volts and amps. Locate the tag to find the information. Here is an example.

Under Counter Refrigerator 1.3 amps (120 volts x 1.3 amps = 156 watts)

Microwave (120 volts x 10 amps = 1200 watts)

Alarm Clock Radio (120 volts x .03 amps = 3.6watts)

TV (120 volts x .6 amps = 72 watts)

You now add all the watts together, since the above list could likely be running at the same time. There is a combine wattage of 1431.6 watts. In this example you would need at least a 1500 watt inverter. However given some unknown variables personally I would get a 2500 watt inverter. Less stress on the inverter, will lengthen the life of the inverter. Had the total been 1,000 watts a 1,500 watt inverter would suffice.

You must also remember that your alternator on your vehicle must be able to keep up with the power demand of not only your vehicle needs but your inverter needs as well.

Under Counter Refrigerator 1.3 amps (120 volts x 1.3 amps = 156 watts)

Microwave (120 volts x 10 amps = 1200 watts)

Alarm Clock Radio (120 volts x .03 amps = 3.6watts)

TV (120 volts x .6 amps = 72 watts)

You now add all the watts together, since the above list could likely be running at the same time. There is a combine wattage of 1431.6 watts. In this example you would need at least a 1500 watt inverter. However given some unknown variables personally I would get a 2500 watt inverter. Less stress on the inverter, will lengthen the life of the inverter. Had the total been 1,000 watts a 1,500 watt inverter would suffice.

You must also remember that your alternator on your vehicle must be able to keep up with the power demand of not only your vehicle needs but your inverter needs as well.

on Apr 23, 2010 | Electronics - Others

It sounds to me that you have a load that draws too much from time to time. If the inverter will run without a load without a problem, try adding loads one at a time until it starts to trip off. That should give you an idea as to what the problem is. It could be that there is a problem internal to the inverter that causes it to trip prematurely..

Jul 11, 2014 | Inverter Aims Pure Sine Wave Power...

Too vague, but look for bulging capacitors and replace them as needed.

JOAT

JOAT

May 09, 2014 | AIMS 5000 Watt 12 Volt DC Power Inverter...

Let us look at the math. 1250 watts at 120 volts is w=va Watts equals volts times amps. Or in this case 1250 divided by 120 volts = 10.41 amps. But what is the 12 volt side capable of drawing. 1250 watts divided by 12 volts. 104.10 amps. This is more than what the average cigarette lighter or power port can provide. So, yes you need to connect directly to the battery, you can use a relay rated for 100 A in between the inverter and battery to control the power to the inverter. I would use a good #2 copper welding cable for the power leads. Now, if you are not planning on using the whole 1250 watts, then you can use a #4 welding cable (it is very flexible) for power leads.

JOE

JOE

Jan 21, 2011 | Inverter Aims Pure Sine Wave Power...

Not sure of the first issue with the radio, but the inverters output is 300 watts at 110v, not 12 volts. If your receptacle is rated at 180 watts that means it draws 15 amps (180/12=15 amps)-I have used a 400 watt inverter in various cars, and never had an issue, and remember just because it is rated at 400 watts does not mean it will draw that much, depending on what is plugged in-a laptop, for example, only uses about 80 watts. Your converter will '**** down' if the load is determined to be too high.

Dec 24, 2010 | 1996 Chrysler Cirrus

Not cheap but high quality - Mastervolt

Feb 19, 2018 | Inverter Aims Pure Sine Wave Power...

A 5000 wat inverter is very large. Your alternator could not supply it alone without the batteries. The moderate to low usage is the key. Calculate the wattage of the load you want to connect. Depending on what else you're doing with the truck, lights, heater, air condition etc, you could probably draw somewhere between 1,0000-1500 watts on that alternator. Rember even if your alternator is rated for 150amps (large alt) it is not a 100% duty cycle. Alternators are usually around 50% duty cycle, so figure about 75amps continuous, or around 900 watts. That's considerably less than your 5,000 watt inverter. Buy a generator.

Jul 01, 2010 | Inverter Aims Pure Sine Wave Power...

it could have an internal fuse or two

May 12, 2009 | Inverter AIMS Power 5000 / 10000W

If you want to get more precise, figure out everything in terms of power (watts).

Basic electrical rule 1, 2 and 3:

voltage x current = power

or re-arranged:

current = power divided by voltage

or re-arranged:

voltage = power divided by current

For example, 12V X 2 amps = 24 watts.

or another example, 400 watts divided by 120 Volts = 3.33 amps

A 55W headlight that uses 12V would draw 55 /12 = 4.6 amps @ 12V

A 55 watt light bulb in a lamp at home would draw 55 / 120 = 0.46 amps @ 120V

As the previous post mentioned, inverters are not perfect when convertering 12V into 120V. If the converter consumes 1000W from the 12V battery, then a 90% effecient converter would generate 900W of 120V AC power best case. The other 100W is lost primarily as heat.

The other thing that gets tricky is that these ratings and the formula above are used for resistive loads, like light bulbs or hair dryers. Anything with a motor or transformer is considered an inductive load and can get much more tricky to calculate.

Consequently you need to give your self a safety margin when figuring out how big an inverter you need.

How does work in a practical sense?

Lets say you want an inverter for TV, DVD and Sat. Receiver. Look at the back of TV or in the manual. It should say how many watts it consumes. Lets say it is 400W. The DVD might be 100W and the Sat. receiver 50W - just as an example.

400 + 100 + 50 = 550 Watts. (just as an example)

You might think, well no problem, I'll use a 600 Watt inverter and have 50 watts left over. Depending on your inverter, that 600W might really be 600 x 90% effecient = 540 Watts of AC, less a 20% margin of error for the inductive transformers in the electronic of the TV, DVD and Sat. receiver 540 - 20% = 432 Watts.

Now you can see your 600 Watt inverter isn't big enough to do the job.

If we really need 550 watts of AC, add 10% to make up the effiency loss, then add a safety margin for inductive loads.

550 + 10% = 605 + 20% = 726 Watts.

Sounds more like an 800W inverter fits the job.

What does that mean in terms of wiring the 12V batteries to the inverter?

from the formula above:

current = power divided by voltage

In our example, we have an 800W inverter that runs on 12V

The current would thererfore be:

current = power divided by voltage

current = 800 watts divided by 12V

current = 66 amps.

That is important info because you can not use light gauge wire to carry 66 amps worth of 12V to the inverter nor could you use a 20A fuse to protect your inverter.

Now that's a lot of science for a guy who just wants to run a toaster on an inverter right?

800W / 120V = 6.66 amps

Using garryp's ratio 11:1, 6.66 x 11 = 73 amps.

That is a good ratio with a good safety margin.

This is all just MHO and should not taken as solid technical advise. In other words, don't blame me if you blow yourself up.

Basic electrical rule 1, 2 and 3:

voltage x current = power

or re-arranged:

current = power divided by voltage

or re-arranged:

voltage = power divided by current

For example, 12V X 2 amps = 24 watts.

or another example, 400 watts divided by 120 Volts = 3.33 amps

A 55W headlight that uses 12V would draw 55 /12 = 4.6 amps @ 12V

A 55 watt light bulb in a lamp at home would draw 55 / 120 = 0.46 amps @ 120V

As the previous post mentioned, inverters are not perfect when convertering 12V into 120V. If the converter consumes 1000W from the 12V battery, then a 90% effecient converter would generate 900W of 120V AC power best case. The other 100W is lost primarily as heat.

The other thing that gets tricky is that these ratings and the formula above are used for resistive loads, like light bulbs or hair dryers. Anything with a motor or transformer is considered an inductive load and can get much more tricky to calculate.

Consequently you need to give your self a safety margin when figuring out how big an inverter you need.

How does work in a practical sense?

Lets say you want an inverter for TV, DVD and Sat. Receiver. Look at the back of TV or in the manual. It should say how many watts it consumes. Lets say it is 400W. The DVD might be 100W and the Sat. receiver 50W - just as an example.

400 + 100 + 50 = 550 Watts. (just as an example)

You might think, well no problem, I'll use a 600 Watt inverter and have 50 watts left over. Depending on your inverter, that 600W might really be 600 x 90% effecient = 540 Watts of AC, less a 20% margin of error for the inductive transformers in the electronic of the TV, DVD and Sat. receiver 540 - 20% = 432 Watts.

Now you can see your 600 Watt inverter isn't big enough to do the job.

If we really need 550 watts of AC, add 10% to make up the effiency loss, then add a safety margin for inductive loads.

550 + 10% = 605 + 20% = 726 Watts.

Sounds more like an 800W inverter fits the job.

What does that mean in terms of wiring the 12V batteries to the inverter?

from the formula above:

current = power divided by voltage

In our example, we have an 800W inverter that runs on 12V

The current would thererfore be:

current = power divided by voltage

current = 800 watts divided by 12V

current = 66 amps.

That is important info because you can not use light gauge wire to carry 66 amps worth of 12V to the inverter nor could you use a 20A fuse to protect your inverter.

Now that's a lot of science for a guy who just wants to run a toaster on an inverter right?

800W / 120V = 6.66 amps

Using garryp's ratio 11:1, 6.66 x 11 = 73 amps.

That is a good ratio with a good safety margin.

This is all just MHO and should not taken as solid technical advise. In other words, don't blame me if you blow yourself up.

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